presidency | Twitter Bot , Web Scraper
kandi X-RAY | presidency Summary
kandi X-RAY | presidency Summary
presidency is a web service that collects and acts on data related to the US presidency, with a potential to expand further. This includes Executive Orders, Proclamations, Speeches, Legislation (Signed, Veto'd, Pending), Statements & Press Releases, etc. Inspired initially by the American Presidency Project, it now scrapes from the APP and WhiteHouse.gov. It also includes scripts supporting client apps, such as a Twitter bot for real time updates on new documents released.
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Top functions reviewed by kandi - BETA
- Scrape all presidents .
- Return the election data as a dictionary .
- Displays all appointments .
- Get all discussions .
- Generate rss feed
- Get information about the object .
- Retrieves information about the passage .
- Return a JSON representation of the instance .
- List all documents .
- List all appointment objects .
presidency Key Features
presidency Examples and Code Snippets
Community Discussions
Trending Discussions on presidency
QUESTION
Im not sure why but I cant seem to get this footer to go properly to the bottom, my body seems to only be going halfway up the page? I wrapped the whole thing in main to see if that would fix it if I set a height on that, it seemingly only goes the same height every single time. Its like its not catching the viewport or something and causing it to only go about half way up. Also please be easy im a new coder so if your awnser has just general advice to improve im all about it. Thanks ahead of time!
...ANSWER
Answered 2021-May-24 at 00:16The line max-height: 100vh in #tribute-info is the cause of this. If you remove it, the footer will display correctly at the bottom.
In addition, the
QUESTION
ANSWER
Answered 2020-Nov-19 at 11:26If it is STR you can use X.split(','). For example:
QUESTION
I have a probleme right now. I'm trying to fetch data from an api rest WebSite Url, i've made all the things i was needed to do, but it doesn't working. I don't know what is this problem, thank's for helping me Error : Expected BEGIN_OBJECT but was BEGIN_ARRAY at line 1 column 75 path $.data
AllClass.kt
...ANSWER
Answered 2020-Oct-24 at 15:45In provided JSON data field is a JSONArray, not a JSONObject, so you need to change
QUESTION
I have a string that contains sentences. If this string contains more character then a given number. I'd like to split up this string into several strings with less then the max number of character, but stil containing full sentence.
I did the below, which seem to run okay, but not sure if I will experience bugs putting this in production. Does the below look okay?
...ANSWER
Answered 2020-Oct-05 at 13:22To better explain my point about problem with the second if block, expressed in comments, see following example.
We want string of max len=15, i.e. 1520 in this case is 16. As you can see first 3 items in the list are 5 + 6 + 4 = 15, so, fisrt shortened_sentence should consists of first 3 items in the list. but it does not. because the logic of the second if is incorrect.
QUESTION
I have the following code:
...ANSWER
Answered 2020-Sep-23 at 22:23When I checked the data, it has some noisy entries like:
QUESTION
I have a string of text scraped from a website using rvest. However, the text is broken up into sections that are not defined by heading tags in the HTML. Instead, they are just classified with tags.
For example, the tag structure looks like
...ANSWER
Answered 2020-Jul-21 at 17:08Here's one approach to isolate the bold section headers using html_nodes:
QUESTION
I am planning to set up a simple script to see if words from a wordlist can be found in a Pandas DataFrame common_words. In case of a match, I would like to return the corresponding DataFrame entry, while the DF has the format life balance 14, long term 9, upper management 9, highlighting the word token and its occurrence number.
The code below is however currently only printing the error KeyError: True with regards to line print('Group 1:', df[df[i].loc[df[i].str.contains(x).any()]]). Does anyone know a smart way to return the DataFrame output word instead of the error?
The relevant code section is:
...ANSWER
Answered 2020-Jun-25 at 18:56I think it might be helpful to break the code into chunks. This should work if I understood the code correctly:
QUESTION
I am trying to solve a vehicle routing problem with 5 drivers for deliveries. I am using haversine and lat-long to calculate the distance matrix. I am new to OR tools, so following the vrp example.
The issues is that the out 0f 5 drivers, only routes are generated for 2 drivers and these routes are very long. I want to generate multiple shorter routes so that all the drivers are utilized. Can please check if I am setting some constraint wrong.
Can someone please explain, how to set "Distance" dimension and SetGlobalSpanCostCoefficient in google OR-tools. Here is the code and output.
...ANSWER
Answered 2019-May-29 at 10:22You should reduce vehicle maximum travel distance. currently you set it to 80. and your routes distances are 20 and 26.
QUESTION
So, I am trying to make a sorter that sorts text by its chronological order on a paper.
The algorithm:
...ANSWER
Answered 2020-May-12 at 18:33The error you are getting happens when str.index can't find the substring you're searching for. You can see this in a simpler example:
QUESTION
page1 and page2 URL. I want to fetch all the content from the 1st URL and only the main text from the 2nd URL and append it to the main text of 1st URL. This is only one article. function parse_indianexpress_archive_links() contains a list of news articles URLs. I m getting all the results from page1 but the next_maintext column from page2 results output
ANSWER
Answered 2020-May-11 at 14:34This is not how Scrapy works (I mean next_page request) How to fetch the Response object of a Request synchronously on Scrapy?.
But in fact you don't need synchronous requests. All you need is to check for a next page and pass current state (item) to the callback that will process your next page. I'm using cb_kwargs (it's a recommended way now). You may need to use request.meta if you have an old version.
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