faceid | Face Detection and Identification for Smart Toy | Computer Vision library
kandi X-RAY | faceid Summary
kandi X-RAY | faceid Summary
Face Detection and Identification for Smart Toy: Geomex Soft.
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faceid Key Features
faceid Examples and Code Snippets
Community Discussions
Trending Discussions on faceid
QUESTION
I need to manage app-level permissions that are device-specific. there are 4 permissions:
- faceID login
- camera
- storage
- location
What I need to develop is, if I enable-disable switches on these permissions, it should be reflected on app settings too. for eg. If I have disabled camera permission; it should show disable in settings-> privacy -> camera -> App (disabled) Is this possible?
Current development: I have enabled it all by default. and stored it in UserDefaults. Whenever a user wants to access the feature, I check the value stored in UserDefault. Allow if enabled and show a message if disabled. But disabled doesn't mean it's disabled from the device settings. I hope I've explained my question properly :/
...ANSWER
Answered 2021-Jun-10 at 20:31You cannot programmatically remove a permission you have been granted.
Once you have a permission you have it until the user turns it off in settings.
Accordingly, it doesn't make sense to provide a UI to disable permissions in your app.
What you can do is provide a UI to disable features that use those permissions. For example, a switch to turn on/off "Login with FaceId" or "Report my location"; if the switch is off your app might still have the permission, but your app won't make use of it.
QUESTION
I have some lists and try to combine them to a dictionary. Using zip()
worked fine I thought. But while working more with my created dictionary I came to the conclusion, that the tuples returned from zip()
are a real problem. Problem in this case means that using the code from this answer on my previous question creates just an empty list. The complete code so far can be seen and tested here.
My lists look like:
...ANSWER
Answered 2021-Jun-04 at 10:40Do you mean?:
QUESTION
hope you all have a great day. I´ve been working on a CNN type model that works as a FaceID, my data was only pictures of me, the model has no error, but when I predict it always give me the same output for everything(it says 100 percent for every face, even is not me), i think it is the Y value, but im not sure. What i want is the output to be wether is ME or OTHER. Here is my code
...ANSWER
Answered 2021-May-20 at 16:08The answer is inside your question. You say your data was only pictures of you. That means you trained the model using photos with the same label y = 1
. So it's logical that the model will always predict y = 1
. If you want the model to distinguish between photos of you and photos of other people, you must train the model using both photos of you as well as photos of other people, and set y = 1
for your photos, and y = 0
for other people's photos.
Note: In your code, this if condition always returns true:
QUESTION
So I'm trying to make a faceID with Tensorflow using CNN type, i only gave to my data 15 images of my face(is a simple project), and i want it to predict if it is my face or is not my face, like true or false, the problem is that I don't understand what is the error in my code. this is
...ANSWER
Answered 2021-May-19 at 15:31As stated by @Frightera, replacing:
model.add(Dense(classes))
by model.add(Dense(1))
should work.
Your label is an integer but your last layer output a 2d array.
QUESTION
if (navigator.credentials && window.PublicKeyCredential) {
const available = await window.PublicKeyCredential.isUserVerifyingPlatformAuthenticatorAvailable();
if (available) {
const newCredentialInfo = await navigator.credentials.create(options);
var response = newCredentialInfo.response;
var clientExtensionsResults = newCredentialInfo.getClientExtensionResults();
alert(JSON.stringify(response))
alert(JSON.stringify(clientExtensionsResults));
}
else {
alert("Unsupported");
}
}
...ANSWER
Answered 2021-Apr-25 at 01:30I see you're calling navigator.credentials.create()
in your component's
componentDidMount()
. macOS and iOS Safari both require that WebAuthn API calls that want to use Touch ID must be made as a result of a "user gesture":
The amount of unsolicited prompts has been surprisingly low. The situation is different with the release of Face ID and Touch ID for the web. So, Face ID and Touch ID for the web require user gestures to function. (User gestures are not required for security keys for backward compatibility.)
See Apple's introduction of their support for WebAuthn for more guidance: https://webkit.org/blog/11312/meet-face-id-and-touch-id-for-the-web/
If you update your React code to move the logic that calls navigator.credentials.create()
into, say, a button click handler, you'll be able to use Face ID. It'll require you click a button to trigger WebAuthn instead of just loading the page, but that's the reality of working with WebAuthn on an Apple OS.
QUESTION
I'm having a problem sending a data stream from kinesis to DynamoDB. I used this lambda function to do the job. When I try the test button in the lambda, it sends the data to DynamoDB. However, when I try to send from the data stream, I get this error "string indices must be integers". Any solution please? Thanx
Here is the code
...ANSWER
Answered 2021-Apr-02 at 07:54SOLVED The for loop should have been like this
QUESTION
FaceID allows storage of credentials but not retrival. I'm seeing this error when inspecting via the xcode console. If I run the same code from xcode locally everything works fine.
returned Error Domain=com.apple.LocalAuthentication Code=-1004 "Caller is not running foreground."
To make it even more strange if I install a different version from testflight and then reinstall the original broken version it starts working again.
...ANSWER
Answered 2021-Mar-09 at 02:33This error always comes up for me as -1004 so I added a check to my error handling block like this:
QUESTION
I am currently able to reproduce an error, where SecItemAdd
fails when testing on devices which have a Passcode set but Biometry is not yet setup on the device (but generally available).
The error:
OSStatus gives -25293
, which seems to be errSecAuthFailed
.
What I want to achieve:
I want to store an Item to the Keychain with Device Passcode as the minimal security requirement. Additionally, if Biometry is enabled, I want to allow users to use it to protect and access the item. In contrast to .userPresence
I want to prevent the item to be accessible when Biometry changes, so .biometryCurrentSet
in the flags seems to the be right option.
So the failing combination is kSecAttrAccessibleWhenPasscodeSetThisDeviceOnly
for the protection level with SecAccessControlCreateFlags
being [.biometryCurrentSet, .or, .devicePasscode]
.
The example code (minimal demo to reproduce):
...ANSWER
Answered 2021-Mar-18 at 08:17Filed as Radar FB9039075.
A teammate (https://stackoverflow.com/users/2451589/julien-klindt, thanks for this!) received feedback from Apple (using DTS) afterwards:
The
.or
operator here refers to the read operation. That is, to read the item the system must be able to satisfy one or more of the specified constraints. However, things are failing in your case at the add operation. Here the presence of.biometryCurrentSet
indicates that the keychain must tag the item with the current biometric set, and that can’t possibly work because no biometrics are currently configured.
So this is as designed. Apple suggest creating a feature request for the described behavior, if wanted.
In terms of workarounds, it seems reasonable to catch this error and then ask Local Authentication whether biometry is enabled. If it isn’t, you can fall back to
.devicePasscode
.
If it's not needed to have changes in Biometry invalidate the item, I would suggest to use .userPresence
instead.
QUESTION
Hello im trying to print a list of ints and i keep getting that erro.
I have a structure that have a list on it.
...ANSWER
Answered 2021-Mar-02 at 06:31I don't think the error message really belongs to the line that causes the problem here (have you tried <<
-ing the list itself before?), but
QUESTION
I did a program that I wished to distribute to my co-workers, they are not VBA oriented. So I wish to distribute it easily.
I created an Add-in, when install the add-in needs to create a custom Ribbon. I tried my best, but I cannot find easy to understand documentation.
My code is as follow :
...ANSWER
Answered 2021-Jan-28 at 23:44Here's an example of how you can do it without using any external application, just a text editor. But you will have to be careful to write XML code properly, or the excel file may not open correctly (make a backup copy).
You will create a folder named "customUI" and, inside that folder, a file named "customUI.xml"
You will write all your Ribbon details inside "customUI.xml". I wrote this example, covering the issues you listed: Big buttons and icons (Images list in https://bert-toolkit.com/imagemso-list.html) / Tooltip description (screentip and supertip) / Ribbon name (tab label) / Group names (group labels)
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install faceid
You can use faceid like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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