shovel | You can version-control your code | Frontend Framework library
kandi X-RAY | shovel Summary
kandi X-RAY | shovel Summary
You can version-control your code, you want to version-control your datasets too. Very many data science workflows can be broken down into working on three stages of data:. The principle of shovel is to help store and version your "input", when combined with versioned code all of your results can be reproducible. How you manage your "working" and your "output" is out-of-scope, and up to you. This is the first major goal of shovel: making it easier to reproduce results in the future. The second major goal is to store our datasets centrally (on S3 for now), so that everyone may access everything. This is good for collaboration. This is also good for organising our datasets, and for backing them up.
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Top functions reviewed by kandi - BETA
- List objects in a bucket
- Build a prefix
- Return a boto3 client
- Bury an object in the bucket
- Parse version string
- Helper function to list objects in S3
- List nodes in a bucket
- Upload objects to S3
- Get contents of an object
- Wrapper for dig
- Get the defaultpit instance
- Get default configuration
- B bury
- Get an instance of the pit
- Return a list of files
- List all datasets in S3
- List all projects in S3
- List versions of S3
- Download objects from bucket
- Downloads a tree
shovel Key Features
shovel Examples and Code Snippets
Community Discussions
Trending Discussions on shovel
QUESTION
Trying to make a minecraft plugin here. I am trying to make a custom ore generator. The generator is cube, it has no exterior walls on the outside and the middle is filled with ores.
When I create a generator I don't save every single location object because every player can have multiple generator and that would be a massive amount of blocks in no time. What I do instead is that I save the min and max location for the border and for that inside cube(Why save both for border and cube? Well I'll explain in a bit) in a Object called CubeLocation that also stores the cubeId.
So I save the cubes in a HashMap - (This is not the id of a player, but i generate a random uuid when creating each code).
And I also save the Location in a HashSet
Now for my problem. I need to check if the location of the broken block is inside a cube. What I have at the moment is something like this
...ANSWER
Answered 2022-Mar-19 at 17:10I suggest you to do multiple things :
- Use less variable. It will not directly fix the amount of items, but it will help in performance. It's also mostly a suggestion than will make the code quickly more readable. For example, you can add position of a center, then store the size. So you require only 5 variables:
QUESTION
I have a complex use case that I can currently mostly solve with JQ, but am wondering if JQ is no longer the right tool for the job, or if there is a way I can generalize my filter. The use case is to create a statistical aggregate of sorted key value counts in large data set of newline delimited JSON. The issue I am running into relates to the number of keys in my data set becoming too large of a filter for jq to actually compile.
Below is a sample input, note that it includes arrays.
Input: (input.json)
...ANSWER
Answered 2022-Mar-17 at 18:45You could use the --stream
option to read in the big input in smaller pieces
QUESTION
I have a hash table (for tagging items) with an extra column for the strength of the relationship between items and their tags:
...ANSWER
Answered 2022-Mar-08 at 08:35You can simply use in
:
QUESTION
I made a Selfbot on Discord (please do not tell me its against the ToS, I have already been told hundreds of times) to send the string "Hello!" everytime someone sends "!hello", and it can also grind other bots such as Dank Memer, all via an on_message() function. But for some reason, when I run the bot, it can login into the account, but the on_message() doesn't seem to work. There is a print() function called in it which is also not displayed, which means that the bot cannot react to the on_message function. It is currently hosted and run on https://replit.com. Please help, I cannot continue developing it after this.
Full Code here:
...ANSWER
Answered 2022-Feb-19 at 16:52Recent Discord API Changes disallows Self-Bots (which is against Discord's ToS) to receive message contents from other users (except itself), hence why your message commands will not work.
QUESTION
This is probably going to be simple but I can't figure it out. I have the following in the razor page:
...ANSWER
Answered 2022-Feb-18 at 02:38Try to add id to your form,and submit the form after alert("end of test");
:
QUESTION
I am trying to create a new array where elements of the original array are replaced with their corresponding values in the hash. I want to compare every element in arr to the key in hash and if they are equal shovel them into the arr and return it at the end. Why is my code not working and how can I access/return the key value of the respective entry in hash, not only the value pointed to by the key? If you get what I am saying.
...ANSWER
Answered 2021-Dec-20 at 07:31Ruby's Hash::fetch
would be a technique to get your desired result:
QUESTION
I have a couple of lines of code in Python that I am trying to replicate in R, but I'm admittedly not skilled enough at this point to figure it out.
Here's the code in Python:
...ANSWER
Answered 2021-Dec-15 at 13:18library(tidyverse)
df <- tibble(
col_a = c("blue shovel 1024", "red shovel 1022", "green bucket 3021", "green rake 3021", "yellow shovel 1023"),
col_b = c("blue", "red", "green", "blue", "yellow")
)
df
#> # A tibble: 5 x 2
#> col_a col_b
#>
#> 1 blue shovel 1024 blue
#> 2 red shovel 1022 red
#> 3 green bucket 3021 green
#> 4 green rake 3021 blue
#> 5 yellow shovel 1023 yellow
unique_words <- unique(df$col_b)
unique_words
#> [1] "blue" "red" "green" "yellow"
unique_words_regex <- unique_words %>% paste0(collapse = "|")
df <- mutate(df, result = col_a %>% str_extract(unique_words_regex))
df
#> # A tibble: 5 x 3
#> col_a col_b result
#>
#> 1 blue shovel 1024 blue blue
#> 2 red shovel 1022 red red
#> 3 green bucket 3021 green green
#> 4 green rake 3021 blue green
#> 5 yellow shovel 1023 yellow yellow
QUESTION
I have the task of checking to see if values in a number of different columns appear in a character string in a field that contains an item name. If the values appear in this item name column, they need to be extracted and placed in a new column. I need to search one column at a time, so it will look like this: In column A, search for unique values from column B. I'll need to do this for a number of times where column A will always be the same, but the set of unique values from column B will be different because I'm using unique values from column B. Here's some example data:
...ANSWER
Answered 2021-Dec-03 at 20:01I think this works for you:
QUESTION
We are currently using RabbitMQ Dynamic Shovels to forward messages to Azure Event Hub. Recently we setup a new Queue to be forwarded to Event Hub. Some messages in this Queue have a size of over 1MB which is the limit for messages on Event Hub. Because of this limit the messages bounce back and are sent again a few times each second. This creates a lot of network traffic which can be an issue.
Is there any way to send messages that bounce back to a DLX (dead letter exchange) or to a different queue? We have looked for some Dynamic Shovel options but could not find any that would be of any use.
...ANSWER
Answered 2021-Nov-01 at 04:57Thank you Jesse Squire. Posting your suggestion as an answer to help other community members.
Generally, for cases when your payload is (or may be) larger than the allowable size, we recommend considering the claim check pattern where you store your payload in some other durable store (such as Blob storage) and then publish the event with a body that points to that resource.
You can refer to Dead-lettering dead-lettered messages in RabbitMQ.
You can also open an issue on GitHub: rabbitmq-server
QUESTION
I have built a React component which has two children: one displays a graph (vis.js) and when the user hovers over a node in the graph, the main component is made aware of this by a state change. The only child using this state is a div (sibling to the graph).
However, when the state changes, all children (including the graph) are re-rendered. I do not want to render the graph every time I hover over a node, just its sibling.
This is my code:
...ANSWER
Answered 2021-Oct-18 at 13:19You can use React.memo()
, React.useCallback
for avoiding re-rendering stuff in react component. Avoiding React component re-renders with React.memo
Example :
Button
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install shovel
AWS_ACCESS_KEY_ID - for boto
AWS_SECRET_ACCESS_KEY - for boto
SHOVEL_DEFAULT_BUCKET - the bucket in which to store your data
SHOVEL_DEFAULT_ROOT (bottomless-pit) - the root prefix for the default Pit your data will be stored in (shovel will always include this as the prefix when writing to your bucket.
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