eco | An aggregated data set of chess opening names | Machine Learning library

 by   niklasf Python Version: Current License: CC0-1.0

kandi X-RAY | eco Summary

kandi X-RAY | eco Summary

eco is a Python library typically used in Artificial Intelligence, Machine Learning, Deep Learning applications. eco has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However eco build file is not available. You can download it from GitHub.

An aggregated data set of chess opening names. field | description --- | --- eco | [ECO] classification name | Opening name (English language) fen | [EPD] of the root position (en passant field only if legal) moves | Most common moves to reach the root position based on master games, in UCI notation.
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              eco has a low active ecosystem.
              It has 83 star(s) with 25 fork(s). There are 8 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 9 have been closed. On average issues are closed in 4 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of eco is current.

            kandi-Quality Quality

              eco has 0 bugs and 0 code smells.

            kandi-Security Security

              eco has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              eco code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              eco is licensed under the CC0-1.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              eco releases are not available. You will need to build from source code and install.
              eco has no build file. You will be need to create the build yourself to build the component from source.
              It has 113 lines of code, 3 functions and 3 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of eco
            Get all kandi verified functions for this library.

            eco Key Features

            No Key Features are available at this moment for eco.

            eco Examples and Code Snippets

            No Code Snippets are available at this moment for eco.

            Community Discussions

            QUESTION

            Is `Object.freeze(Object.prototype)` only the hazard for extending `Object.prototype` with Symbols?
            Asked 2022-Mar-19 at 21:13

            So, fundamentally, this question is Not opinion-based. I seriously pursuit this issue objectively without feeling mostly arisen from the predominant opinion - Why is extending native objects a bad practice?

            and this quesion is related but unanswered questions:

            If Object.prototype is extended with Symbol property, is it possible to break code without specifically designed APIs to access Symbol in JavaScript?

            Should the extension of built-in Javascript prototypes through symbols also be avoided?

            The first question is already closed as they say it's opinion based, and as you might know in this community once a question is Banned, however we modified it, moderators will never bother to re-open. That is the way how the things work here.

            For the second question. For some unknown reason, the question has been taken more seriously and not considered as opinion based although the context is identical.

            There are two parts to the "don't modify something you don't own" rule:

            1. You can cause name collisions and you can break their code.

              By touching something you don't own, you may accidentally overwrite something used by some other library. This will break their code in unexpected ways.

            2. You can create tight dependencies and they can break your code.

              By binding your code so tightly to some other object, if they make some significant change (like removing or renaming the class, for example), your code might suddenly break.

            Using symbols will avoid #1, but you still run into #2. Tight dependencies between classes like that are generally discouraged. If the other class is ever frozen, your code will still break. The answers on this question still apply, just for slightly different reasons.

            Also, I've read opinions(how can we discuss such a thing here without "opinion" base?), they claim

            a) Library code Using Symbols exists and they may tweak Symbol API (such as Object.getOwnPropertySymbols())

            b) extending object property with Symbol is not different from non-Symbol property fundamentally.

            Here, for the major rationale of untouching Object.prototype is due to #1, almost all answers I saw claimed that and we don't have to discuss if there is no Symbol usage.

            However, Using symbols will avoid #1 as they say. So most of the traditional wisdom won't apply anymore.

            Then, as #2 says,

            By binding your code so tightly to some other object, if they make some significant change (like removing or renaming the class, for example), your code might suddenly break.

            well, in principle, any fundamental API version upgrade will break any code. The well-known fact is nothing to do with this specific question. #2 did not answer the question.

            Only considerable part is Object.freeze(Object.prototype) can be the remaining problem. However, this is essentially the same manner to upgrade the basic API by some other unexpectedly.

            As the API users not as API providers, the expected API of Object.prototype is not frozen.

            If some other guys touch the basic API and modifies it as frozen, it is he/she who broke the code. They upgraded the basic API without notice.

            For instance, in Haskell, there are many language extensions. Probably they solve the collision issue well, and most importantly, they won't "freeze" the basic API because freezing the basic API would brake their eco.

            Therefore, I observe that Object.freeze(Object.prototype) is the anti-pattern. It cannot be justified as a matter of course to prevent Object.prototype extension with Symbols.

            So here is my question. Although I observe this way, is it safe to say:

            In case of that Object.freeze(Object.prototype) is not performed, which is the anti-pattern and detectable, it is safe to perform extending Object.prototype with Symbols?

            If you don't think so, please provide a concrete example.

            ...

            ANSWER

            Answered 2022-Mar-17 at 03:18

            Extending the Object prototype is a dangerous practice.

            You have obviously done some research and found that the community of javascript developers overwhelmingly considers it to be a very bad practice.

            If you're working on a personal project all by yourself, and you think the rest of us are all cowards for being unwilling to take the risk, then by all means: go ahead and modify your Object prototype! Nobody can stop you. It's up to you whether you will be guided by our advice. Sometimes the conventional wisdom is wrong. (Spoiler: in this case, the conventional wisdom is right.)

            But if you are working in a shared repository, especially in any kind of professional setting, do not modify the Object prototype. Whatever you want to accomplish by this technique, there will be alternative approaches that avoid the dangers of modifying the base prototypes.

            The number one job of code is to be understood by other developers (including yourself in the future), not just to work. Even if you manage to make this work, it is counterintuitive, and nobody who comes after you will expect to find this. That makes it unacceptable by definition, because what matters here is reasonable expectations, NOT what the language supports. Any person who fails to recognize that professional software development is a team effort has no place writing software professionally.

            You are not going to find a technical limitation to extending the Object prototype. Javascript is a very flexible language -- it will give you plenty of rope with which to hang yourself. That does not mean it's a good idea to place your head in the noose.

            Source https://stackoverflow.com/questions/71505938

            QUESTION

            How to select a row by name and also the previous row in bash or python?
            Asked 2022-Mar-07 at 12:24

            Imagine that we have this data:

            ...

            ANSWER

            Answered 2022-Mar-07 at 12:01

            You might use python for this task following way, let file.txt content be

            Source https://stackoverflow.com/questions/71380544

            QUESTION

            Organising dataframe with pandas and pivot table
            Asked 2022-Feb-14 at 13:31

            I would like to modified my dataframe using melt and table pivot.

            I have this dataframe :

            ...

            ANSWER

            Answered 2022-Feb-14 at 13:31

            First is not necessary defined years in value_vars in DataFrame.melt, if need all of them:

            Source https://stackoverflow.com/questions/71112465

            QUESTION

            Expected to receive a SlashCommandChannelOption builder, got undefined instead
            Asked 2022-Jan-30 at 16:13

            While creating a command using Discord.js v13, I encountered an interesting error that I can't seem to figure out.

            If I use a command handling system and create a command with a channel input field via the Application Commands feature Discord created not so long ago for Developer applications, I run into the following error when running the Node.js application:

            ...

            ANSWER

            Answered 2021-Aug-16 at 18:14

            The function you pass as an argument into .addChannelOption() method is expected to return an instance of SlashCommandChannelOption, which in your case is channel. So make sure to return the channel.

            Source https://stackoverflow.com/questions/68807171

            QUESTION

            copy a column from file1 when the ID's matches to file2 and print output according to file 2
            Asked 2022-Jan-29 at 08:09

            I have 2 files,

            head file1

            ...

            ANSWER

            Answered 2022-Jan-29 at 08:09

            This awk should work for you:

            Source https://stackoverflow.com/questions/70892847

            QUESTION

            How do I make my very simple Shiny App to work?
            Asked 2021-Dec-29 at 22:00

            I am new with Shiny App and I wanted to try something very simple but I'm having a hard time with it.

            I have a data that looks like this:

            ...

            ANSWER

            Answered 2021-Dec-29 at 22:00

            knowing that the value from the inputs are characters, we can use the special construct .data[[]] to select a variable using a string.

            Source https://stackoverflow.com/questions/70523685

            QUESTION

            image as circle background (d3.js svg)
            Asked 2021-Dec-08 at 15:40

            UPDATED I have made a force directed graph using D3.js. Each node corresponds to a company, and each link corresponds how they are related to each other according to the link color. What I would like to achieve is to use the image URLs within "nodes" data and show a different image for each bubble. Currently I was able to set a fixed static/identical image for all of my bubbles. I tried to connect the pattern to my "nodes" data, but unsuccessfully which ended up in an infinite loop.

            Simple HTML canvas for my svg and two buttons for the zoom in and zoom out by click.

            ...

            ANSWER

            Answered 2021-Dec-08 at 12:15

            I've used your code to assemble a small example, which you can see below.

            1. Inside svg > defs, create one pattern per node and use that pattern (with the ID of the company) to fetch the logo of that company;
            2. Reference the pattern for the node using the information you already have.

            Some pointers on your code:

            1. You already use ES6 logic, so you can also use Array.prototype.map and other functions. They're generally much more readable (and natively implemented!) than d3.map;
            2. There is no need to keep so many arrays of values, generally having fewer sources of truth for your data will make the code simpler to maintain and update in the future;
            3. Use clear variable names! LS and LT are logical when you know the context, but when you revisit this code in 6 months you might not instantly know what you were talking about when you wrote it.

            Source https://stackoverflow.com/questions/70264049

            QUESTION

            add columns to specific level pivot tables in pandas
            Asked 2021-Nov-11 at 08:39

            I am trying to achieve this multi-indexing form with a pandas pivot table.

            since the original data were like this.

            I used this code table = pd.pivot_table(df, index=str(df.columns[0]), columns =list(df.columns[1:4]), values='Value') to get this result

            but now I need to add these three columns (Forcast, Tolerance, Baseline Forcast) to the most detailed level of the pivot table for each subproduct like adding them under the ECo, I tried this table[('OcP', 'CoC', 'tolerance')] = 0 it worked but added the column to the end of the pivot table like this.

            so how can add them and make them fall under the same sub-category that is already existed not at the end of the pivot like shown above? Note: I know there are similar questions but they didn't solve my case.

            ...

            ANSWER

            Answered 2021-Nov-11 at 08:39
            table[('OcP', 'CoC', 'tolerance')] = 0
            

            Source https://stackoverflow.com/questions/69908971

            QUESTION

            How do I change a dataframe in a nested list to a list
            Asked 2021-Nov-03 at 13:15

            I have a data frame with three columns (Category, Sub.category and Acitivty). I need a nested list, with these three levels to put into shinyTree.

            I'm trying to match the format of this .Rds file to create a shinyTree.

            My full table is 99 lines, I've included 30 below, but may need to do over 100+ in the same way.

            So far I've got

            ...

            ANSWER

            Answered 2021-Nov-03 at 13:15

            Here is a possible approach using rrapply() in the rrapply-package to unmelt the data.frame to a nested list:

            Source https://stackoverflow.com/questions/69804732

            QUESTION

            Flutter Populate items into listView from sharedPreferenes json
            Asked 2021-Nov-03 at 05:33

            I am trying to populate a gridview.builder with items i have in an adapter class. I have successfully done that by hard coding the items. My model class is like this :

            ...

            ANSWER

            Answered 2021-Nov-03 at 05:33

            you can do it like this.

            Source https://stackoverflow.com/questions/69811703

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install eco

            You can download it from GitHub.
            You can use eco like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            Improvements, additions and fixes are welcome.
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/niklasf/eco.git

          • CLI

            gh repo clone niklasf/eco

          • sshUrl

            git@github.com:niklasf/eco.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link