nums | translates Python and NumPy to optimized | GPU library
kandi X-RAY | nums Summary
kandi X-RAY | nums Summary
NumS is a Numerical cloud computing library that translates Python and NumPy to distributed systems code at runtime. NumS scales NumPy operations horizontally, and provides inter-operation (task) parallelism for those operations. NumS remains faithful to the NumPy API, and provides tight integration with the Python programming language by supporting loop parallelism and branching. NumS' system-level operations are written against the Ray API; it supports S3 and basic distributed filesystem operations for storage and uses NumPy as a backend for CPU-based array operations.
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Top functions reviewed by kandi - BETA
- Compute the average along axis
- Sum the array along an axis
- Divide two arrays together
- Broadcasts blocks to given shape
- Inversion of U
- Inverse inverse function
- Compute the einsum operator
- Adds a child node to the tree
- Load blocks from a text file
- Create block array from array
- Return the maximum of x1 and x2
- Calculate nan variance of an array
- Compute the minimum of two arrays
- Compute the maximum of x1 and x2
- Multiplies x1 and x2
- Find the minimum of x1 and x2
- Compute the dot product of two arrays
- Calculate the minimum value of a block array
- Calculate the maximum value of a block array
- Calculate the nanmean of an array
- Compute the nansum along axis
- Compute the arctan between x1 and x2
- Compute the covariance matrix
- Calculate the percentile of an array
- Compute the quantile of an array
- Calculate the nanstd along an axis
nums Key Features
nums Examples and Code Snippets
Lines of Code : 35License : Permissive (MIT License)
Copydef check_polygon(nums: list[float]) -> bool:
"""
Takes list of possible side lengths and determines whether a
two-dimensional polygon with such side lengths can exist.
Returns a boolean value for the < comparison
of the la def top_k_frequent_2(nums, k):
frequency = {}
# count the frequency of each unique element
for num in nums:
if num in frequency:
frequency[num] += 1
else:
frequency[num] = 1
arr = [(frequency[ def top_k_frequent_1(nums, k):
frequency = {}
# count the frequency of each unique element
for num in nums:
if num in frequency:
frequency[num] += 1
else:
frequency[num] = 1
arr = [(frequency[ Community Discussions
Trending Discussions on nums
QUESTION
First time actually using anything to do with swing - sorry for the poor code and crude visuals!
Using swing for a massively over-complicated password checker school project, and when I came to loading in a JMenuBar, it doesn't render properly the first time. Once I run through one of the options first, it reloads correctly, but the first time it comes out like this:
First render attempt
But after I run one of the methods, either by clicking one of the buttons that I added to check if it was just the JFrame that was broken or using one of the broken menu options, it reloads correctly, but has a little grey bar above where the JMenuBar actually renders: Post-method render
The code for the visuals is as follows:
...ANSWER
Answered 2021-Jun-15 at 18:29You should separate creating your menu from your content. Please review the following example. I decoupled your menu, component, and event logic into meaningful phases.
QUESTION
Here is the question:
...ANSWER
Answered 2021-Jun-15 at 16:06You have to assign the number of elements of the array to return (2 in this case) to what the argument returnSize points at (*returnSize) to tell the judge system how large the array you returned is.
QUESTION
I'm creating an int (32 bit) vector with 1024 * 1024 * 1024 elements like so:
...ANSWER
Answered 2021-Jun-14 at 17:01Here are some techniques.
Loop UnrollingQUESTION
I was writing a simple loop in C++ and was wondering what the time complexity would be.
My intuition tells me that it is O(n*log(n)) but I couldn't come up for a proof for the n*log(n)
ANSWER
Answered 2021-Jun-14 at 14:10Worst case is when the input has only unique numbers. In that case, the equivalent is:
QUESTION
For exmaple if I have a JavaScript Object like,
...ANSWER
Answered 2021-Jun-13 at 16:27convert string to int:
parseInt()- this will turn a number withing""to it's value.convert string to boolean: use
Boolean(value)or!!value
QUESTION
I am trying to make write a code that makes a graph of front and backward slashes based upon the values that user input
...ANSWER
Answered 2021-Jun-13 at 08:361. The first change to make to understand your output is the final print. Change it to an f-string or print the message and the output using separate print's. When you do print('some text\n', output) the comma gets inserted as a space after the newline and skews the top row of your output. How it looks when correct:
QUESTION
I want to iterate values to my 2D array by using a nested for loop but here is what I have so far. I think it does populate my 2D array but not with the numbers I want. I want it to populate with the powers of 2 starting at 2. So my outcome would look like: 2, 4, 8, 16, 32, 64.. and so on until my rows and columns are complete.
My code:
...ANSWER
Answered 2021-Jun-13 at 07:35This should work:
QUESTION
I am implementing the quick-select algorithm to get the kth element in an array, and I am stuck at a place where I don't know how to resolve. Here is my code that doesn't work:
ANSWER
Answered 2021-Jun-13 at 06:59If k < partitionIndex, only check the left partition, else only check the right partition.
QUESTION
def max_end3(nums):
for i in range(len(nums)):
if nums[0] > nums[2]:
nums[0] = nums[0]
nums[1] = nums[0]
nums[2] = nums[0]
return nums
elif nums[2] > nums[0]:
nums[0] = nums[2]
nums[1] = nums[2]
nums[2] = nums[2]
return nums
elif nums[0] == nums[2]:
nums[0] = nums[0]
nums[1] = nums[0]
nums[2] = nums[0]
return nums
ANSWER
Answered 2021-Jun-12 at 14:59You've got repeated logic. That is, in each of the three if clause blocks, you're setting all three locations equal to a particular value and then returning nums. Furthermore, you're using an if block to determine which of the two values is larger. The built-in function max will do this for you. So,
QUESTION
I want to make a password validator. When a user types a password, it will check for some special characters and numbers and length.
Conditions:
- At least 1 letter between [a-z] and 1 letter between [A-Z].
- At least 1 number between [0-9].
- At least 1 character from [$#@].
- Minimum length 6 characters.
- Maximum length 16 characters.
My code:
...ANSWER
Answered 2021-Jun-11 at 03:49you can
- use
setto check if there are numbers and special characters in the password - use
not .islower()andnot .isupper()to check for at least 1 capital and at least 1 small letter. Since theislower()method returnsFalseif the string contains at least one uppercase alphabet.
code:
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