Doga | : chart_with_upwards_trend : HTTP log monitoring console
kandi X-RAY | Doga Summary
kandi X-RAY | Doga Summary
:chart_with_upwards_trend: HTTP log monitoring console for Humans
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Doga
Doga Key Features
Doga Examples and Code Snippets
for dog in session.query(DogTbl).\
filter(
and_(DogTbl.State.op('&')(Dog.Old),
DogTbl.State.op('&')(Dog.Bark))).\
order_by(DogTbl.Name).all():
print(dog.Name, dog.State)
import random
consonants_pat = 'BCDFGHJKLMNPQRSTVXZ'.lower()
vowels_pat = 'aeiouy'
train_data = '''
This our sentence to be used as a training dataset
It should be longer
'''
def build_mix
dftest['newcol'] = dftest['col2'].str[:-1]
i1 = dftest.groupby('newcol')['col1'].nunique()
print('match: ', sum(i1 == 1))
#match: 2
print('MisMatch: ', sum(i1 > 1))
#MisMatch: 1
Community Discussions
Trending Discussions on Doga
QUESTION
My code is supposed to clear any character that isn't a-z
or A-Z
. For other characters, for instance á à ã ă â é è ê
if I can make it work, I'll make them change from á
to a
and è
to e
etc.
ANSWER
Answered 2021-Jun-09 at 13:42You can use wcout
and wstring
to deal with Unicode character in C++ within Windows:
QUESTION
I have an array of objects, objects look like this:
...ANSWER
Answered 2021-May-15 at 02:47You need to create a deep copy of your objects like so
QUESTION
function Dog(name){
this.name=name;
}
let dogA=new Dog('Paul');
Dog.prototype.eat=true;
dogA.eat; //true
...ANSWER
Answered 2021-Apr-04 at 08:58The property eat
is stored in dogA.__proto__
. When you use new
operator to create an instance dogA
of Dog
, javascript will do dogA.__proto__ = Dog.prototype = someObject
. Now you make Dog.prototype = null
, but dogA.__proto__
still equals to someObject
. So dogA.eat
still be true
. If you make dogA.__proto__ = null
, then dogA.eat
will be undefined
.
QUESTION
This code returns: TypeError: data.map is not a function, at Orders.js:18
I import this component to my app.js
and use it to get data from OData servers.
ANSWER
Answered 2021-Mar-14 at 13:13That's because you are trying to map over an object.
.map()
is an array method.
maybe you want to loop over the results
array (data.results
)?
QUESTION
My Input:
...ANSWER
Answered 2019-Nov-13 at 12:05Let's not fix your code, let's fix the model and make things easy. No fancy-pansy use of streams, sorry.
QUESTION
These are my JSON
data:
ANSWER
Answered 2019-Apr-26 at 12:34JSONArray jsonarray = new JSONArray(s);
for (int i = 0; i < jsonarray.length(); i++) {
JSONObject jsonobject = jsonarray.getJSONObject(i);
String Haberbaslik = jsonobject.getString("haberBaslik");
tv1.setText(tv1.getText()+ " "+Haberbaslik);
}
QUESTION
I'm currently trying to make a sort of "word mixer": for two given words and the desired length specified, the program should return the "mix" of the two words. However, it can be any sort of mix: it can be the first half of the first word combined with the second half of the second word, it can be a random mix, anything really.
Examples:
fish + cake, length 5: fiske
dog + cat, length 4: doga
late + cross, length 6: losste
I've written a very sloppy code (as seen below), and I'd appreciate some tips on what am I doing wrong (since my outputs aren't really good) and if there's anything that can be improved.
...ANSWER
Answered 2019-Mar-04 at 05:39Here's one way to do it.
QUESTION
I've got a heterogeneous collection of different types that all conform to the same protocol. I want to sort the array by type and then the name attribute. For example I want this array of animals to be sorted by type in this order: Dog, Bird and then Fish, and if they are of the same type I want to sort by name. Here's the code:
...ANSWER
Answered 2019-Feb-08 at 21:57Use an [Animal.Type]
to establish the ordering, and then compare the types for equality first to decide if you need to sort by name
or by type
.
QUESTION
I have a df in this format, but with many more rows:
...ANSWER
Answered 2019-Jan-23 at 08:35You can remove the last letter from col2
, group by the new string and count the unique col1
, i.e.
QUESTION
Here I created Hashmap array in PHP. I gave input as $keys = str_split('cat1hen')
which give output 'doga@nt
'.
ANSWER
Answered 2018-Dec-13 at 11:08As another solution without regexps, you can wrap your array_walk
into a function and map it to each element of array:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
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