rambo | A Provider Agnostic Provisioning Framework | DevOps library

by terminal-labs Python Version: 0.4.0 License: Non-SPDX

X-Ray Key Features Code Snippets(1)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | rambo Summary

rambo is a Python library typically used in Devops, Docker applications. rambo has no bugs, it has no vulnerabilities, it has build file available and it has low support. However rambo has a Non-SPDX License. You can install using 'pip install rambo' or download it from GitHub, PyPI.

This project is for provisioning and configuring virtual machines (and containers) in a simple, predictable, and highly reproducible way. Just run one command and your VM is up, code is deployed, and your app is running, on any supported platform. At this time this repo allows you to create a Linux VM on multiple providers (AWS EC2, DigitalOcean, VirtualBox, LXC). Several Operating Systems are available on select providers. The base machine configuration is a Ubuntu 16.04 64bit OS with 1024MB RAM, and 30GB drive. One of the goals of this project is be able to run a simple command and have a new VM be created on your provider of choice. Once the VM is initialized SaltStack is used to deploy code to and provision your machine. The SaltStack machine configuration code (states) will run the same regardless of which provider is actually running the machine. You can easily cycle your VMs by destroying and rebuilding them. Another goal of this repo is to have the spawned VMs be maximally similar across providers. Usually, your configuration will not need to change at all and will simply run on all providers. By default Rambo offers a basic VM configuration with SaltStack, but you can customize this. See Customizing Rambo for that.

Support

Quality

Security

License

Reuse

Support

rambo has a low active ecosystem.

It has 23 star(s) with 4 fork(s). There are 6 watchers for this library.

It had no major release in the last 12 months.

There are 77 open issues and 179 have been closed. On average issues are closed in 710 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of rambo is 0.4.0

Quality

rambo has no bugs reported.

Security

rambo has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

rambo has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

rambo releases are available to install and integrate.

Deployable package is available in PyPI.

Build file is available. You can build the component from source.

Installation instructions, examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed rambo and discovered the below as its top functions. This is intended to give you an instant insight into rambo implemented functionality, and help decide if they suit your requirements.

Create a new virtual machine
Set vagrant variables
Invoke vagrant commands
Abort the given message
Create a new project directory
Set the working directory
Return a sensible size option
Set an environment variable
Destroy Vagrant
Invoke vagrant
Set machine - type option
Return vm_name option
Set command option
Get project directory
Return the CPU option
Get sync type
Configure EC2
Set the hostname option
Set up DigitalOcean
Get provider option
Start vagrant ssh
Get the guest OS option
Install all plugins
Wrapper for scp
Set the ports option
Return sync_dirs option

Get all kandi verified functions for this library.

rambo Key Features

No Key Features are available at this moment for rambo.

rambo Examples and Code Snippets

README,Basic Usage

Python

Lines of Code : 10

License : Non-SPDX (NOASSERTION)

Copy

$ rambo up
$ rambo ssh

$ rambo up -p ec2
$ rambo ssh

$ rambo up -p digitalocean
$ rambo ssh

$ rambo up -p docker
$ rambo ssh

$ rambo up -p lxc
$ rambo ssh

Community Discussions

Trending Discussions on rambo

MongoDB, counting the occurrences of EACH item in several arrays

Expanding dimension of numpy array by slicing

Insert data on OneToOneField using django-rest-framework

Why .forEach is returning undefined once called in my controller in express.js?

reverse() in a test only returns relative URL in a test for django-rest-framework and that causes a 404

different colors of the bars from directly plotting dataset

springboot mongodb crud update only changed fields

Conditional Copy of one element from one column and apply to respective rows in python

Conditional copy element of one column and apply to all satisfied rows Python dataframe

How to order an array by keeping certain elements always on top

QUESTION

MongoDB, counting the occurrences of EACH item in several arrays

Asked 2021-May-21 at 16:27

I'm fairly new to Mongo, sorry if this has some simple answer I've not grasped.

I want to be able to count the number of times each number(genre id) appears in all of the 'movie_genres' arrays and get back counts for each number. My end-goal is to tally how many times a certain genre number appears in the user's account (includes all movies).

I hope to get back that this user has 2 28's, 2 53's, 1 18

Movies can be added all the time to the user's 'movies_watched' array.

...

ANSWER

Answered 2021-May-21 at 16:27

you need to use aggregation and set (only unique values)

query:

Source https://stackoverflow.com/questions/67638588

QUESTION

Expanding dimension of numpy array by slicing

Asked 2021-Mar-20 at 01:36

I have a huge numpy array X of dimensions (28000, 96, 96, 4). In addition, I have an 1D array users of size 28000 which contains 28000 string entries, each string entry is denoting a specific users. For example:

...

ANSWER

Answered 2021-Mar-20 at 01:36

X = np.random.rand(28000,96,96,4)

Y = np.zeros((28000,2,96,96,4))
for i in range(28000):
    Y[i] = X[i:i+2]

strides = X.strides
strides = (strides[0],)+strides
Z = np.lib.stride_tricks.as_strides(X, Y.shape, strides=strides)

Source https://stackoverflow.com/questions/66714974

QUESTION

Insert data on OneToOneField using django-rest-framework

Asked 2021-Feb-11 at 09:21

I am new to this django-rest-framework, my problem is how am I going to insert a data with one-to-one relationship in the views.py. I can do the normal way of inserting data like the one below,

...

ANSWER

Answered 2021-Feb-11 at 09:21

You can override the create method of the PersonSer to achieve this.

Source https://stackoverflow.com/questions/66150872

QUESTION

Why .forEach is returning undefined once called in my controller in express.js?

Asked 2021-Jan-09 at 10:24

I have an array movies that holds objects and each object has a property called avgRating with a float or integer number. Example:

...

ANSWER

Answered 2021-Jan-09 at 09:58

You want to map your movies, and you should return movie each time in loop. like this:

Source https://stackoverflow.com/questions/65641196

QUESTION

reverse() in a test only returns relative URL in a test for django-rest-framework and that causes a 404

Asked 2020-Dec-21 at 12:41

I am trying to test the endpoints for my API by using this guide. Specifically, this block is supposed to test the get request:

...

ANSWER

Answered 2020-Dec-21 at 12:08

In get_queryset() method of DemanderFeatureCollectionViewSet class you are filtering the model instances with owner field against the logged-in user.

In your test-cases, you are creating the DemanderFeatureCollection instances without linking the user and hence DRF raising an HTTP 404 error. So, attaching the user to the instance and making the request with the same user will give you a proper response from the API.

Source https://stackoverflow.com/questions/65391910

QUESTION

different colors of the bars from directly plotting dataset

Asked 2020-Dec-04 at 17:02

I it possible to have different colors on my barplot straight from pandas plot without specifying them. Here is what I am referring about: I have this dataframe:

...

ANSWER

Answered 2020-Dec-04 at 17:02

Are you open to seaborn:

Source https://stackoverflow.com/questions/65147516

QUESTION

springboot mongodb crud update only changed fields

Asked 2020-Dec-04 at 09:47

Hello i have springboot with mongodb (spring-boot-starter-data-mongodb)

My problem is if I send only one or only the fields I want to change so the other values are set to null. I found something on the internet like @DynamicUpdate but not working on mongodb can you help me with this problem. I'm a beginner, I don't know how to help and it's quite important for me, if you need more code or more information, I'll write in the comment. I hope I have described the problem sufficiently. :)

MY POJO:

...

ANSWER

Answered 2020-Dec-04 at 09:47

You are inserting a new collection instead of updating. First, you need to get the old value from mongodb, then you need to update the collection, then save to DB.

Use the below code in @putmapping.

Source https://stackoverflow.com/questions/65141202

QUESTION

Conditional Copy of one element from one column and apply to respective rows in python

Asked 2020-Sep-09 at 15:41

In my following data frame, I want to create a new column 'refer' with code_num for its associated primary_fruit, if it is not associated with priamry_fruit it should be left blank.

...

ANSWER

Answered 2020-Sep-09 at 01:55

Try this:

Source https://stackoverflow.com/questions/63801304

QUESTION

Conditional copy element of one column and apply to all satisfied rows Python dataframe

Asked 2020-Sep-04 at 02:53

This is very very simple, not sure what I am missing out. I have to copy 'code_num' of 'primary_fruit' and apply it to all reference rows based on 'fruit_list'. if df[fruit] is not present in fruit_list then copy self 'code_num'

...

ANSWER

Answered 2020-Sep-04 at 00:21

Check with

Source https://stackoverflow.com/questions/63733102

QUESTION

How to order an array by keeping certain elements always on top

Asked 2020-Sep-03 at 06:44

I have an array where I want to place certain items always on top. I am getting the response from API as below.

...

ANSWER

Answered 2020-Sep-03 at 06:44

You could do something like this:

Source https://stackoverflow.com/questions/63717691

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install rambo

To get started fast, see: Quickstart, or go to our docs homepage.

Support

We heartily welcome any contirubtions to this project, whether in the form of commenting on or posting an issue, or development. If you would like to submit a pull request, you might first want to look at our development guidelines for this project.

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