lizard | simple code complexity analyser
kandi X-RAY | lizard Summary
kandi X-RAY | lizard Summary
A simple code complexity analyser without caring about the C/C++ header files or Java imports, supports most of the popular languages.
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Top functions reviewed by kandi - BETA
- Create an argument parser .
- Print CSV output .
- Parse command line arguments .
- Creates a FileMeasure element .
- Return a dict with whitelist .
- Get all source files in paths .
- Main entry point .
- Create a function measure .
- Render the result of the wizard complexity code .
- Implements the grammar .
lizard Key Features
lizard Examples and Code Snippets
Lines of Code : 43License : Permissive (BSD-3-Clause)
Copy$ lizard-sim -h
usage: lizard-sim [-h] [--trace] [--vcd] [--verilate] [--use-cached]
[--maxcycles MAXCYCLES] [--imem-delay IMEM_DELAY]
[--dmem-delay DMEM_DELAY]
elf_file
Simulate the Lizard Core @SPI // @SPI注解标明该接口的实现类是SPI扩展
public interface Filter {
/**
* 模拟执行方法
*/
String doFilter();
}
@Extensions // @Extensions注解标明该类是一个SPI扩展，默认为单例
public class SimpleFilterImpl implements Filter {
@Override
image = Lizard::Image.new(image_data)
image.type #=> "JPEG"
image.width #=> 200
image.height #=> 400
# Resize the image
resized_image = image.resize(200, 200)
resized_image = image.resize(200, 200, :ignore_aspect_ratio)
re class ModifiedBaseModel(BaseModel):
def __init__(__pydantic_self__, **data: Any) -> None:
registered, not_registered = __pydantic_self__.filter_data(data)
super().__init__(**registered)
for k, v in not_registdf # you already have it
df_excel = pd.read_excel('Aged Data.xlsx', sheet_name='Sheet1')
pd.concat([df, df_excel], axis=0).to_excel('output.xlsx')
def jokes():
jokes = pyjokes.get_jokes()
jokes_final = "
".join(jokes)
return f'{jokes_final}'
keyboard.wait('enter')
while True:
if keyboard.read_key() == 'enter':
break
elif event.event_type == keyboard.KEY_DOWN:
print('Please press ENTER!')
import random
choices = ['rock', 'paper', 'scissors']
wins = {'rock': 'scissors',
'paper': 'rock',
'scissors': 'paper'}
result1 = random.choice(choices)
result2 = random.choice(choices)
print('player one has chosen ' + rfrom enum import Enum, auto
class MoveChoice(Enum):
ROCK = auto()
PAPER = auto()
SCISSORS = auto()
class Outcome(Enum):
WIN = auto()
LOSE = auto()
DRAW = auto()
WIN_MAPPING = {
MoveChoice.ROCK: MoveChoice.SCIdef get_books_by_rate(rate: int, book_dictionary) -> list:
ratings = []
for category in book_dictionary.keys():
books = book_dictionary[category]
for book in books:
x = 0
Community Discussions
Trending Discussions on lizard
QUESTION
I have a table in postgres with a value column that contains string arrays. My objective is to find all arrays that contain any of the following strings: {'cat', 'dog'}
ANSWER
Answered 2021-Jun-08 at 17:51You can use && operator to find out whether two array has been overlapped or not. It will return true only if at least one element from each array match.
QUESTION
I have been working on trying to convert the following SQL-Server code to achieve a similar result in MS Access.
...ANSWER
Answered 2021-Jun-01 at 21:41From what I can gather, you have two tables that have unique rows. You want to return rows that are present in one table but not the other.
I would suggest aggregation and HAVING for this -- in either database:
QUESTION
I have a MongoDB (running on Cosmos DB), and am trying to filter out sub-documents in an array, based on a list. I have had some success in the Mongo Shell but I did not achieve my goal, and no success in C# with the MongoDriver.
What I want to do is e.g. given these two documents in my database:
...ANSWER
Answered 2021-May-19 at 15:09first of all, you need to make the pet property IEnumerable like so:
QUESTION
My code is not changing the text color of the label element to #ffffff. No errors are logged.
JS Code
...ANSWER
Answered 2021-May-19 at 12:54You can not use this in an anonymous function to refer to the local instance. Change the arrow function to a "function" and your code will work as expected:
QUESTION
I wonder if it is possible to run code provided by users in a webpage in a safe way.
I would like to add code that users can dynamically change to change some of the page behaviour, but I don´t want them to use exploits.
For example, I would like to let the users write a method returning a boolean in a safe way so they do not inject malicious code in the page and alter the dom nor steal info of the rest of the components in the page.
...ANSWER
Answered 2021-May-12 at 11:11As long as users only run their own code, there's no need for any security measures. If they break the site, they break it only for themselves.
If these codes are going to be shared, the only reliable way is to have an sandboxed IFRAME and run everything in there (look at how SO snippets, JS fiddle and similar sites work). In this case, user scripts won't be able to interact with the main page though. Here's a good article on the topic: https://www.html5rocks.com/en/tutorials/security/sandboxed-iframes/
If you need userscripts that 1) can interact with the main page AND 2) can be shared between users, then you have to invent your own programming language and compile it to javascript on the fly. There's no option in JS to sandbox the built-in eval.
QUESTION
I'm using material-ui library to create card like items. I have the list of items stored in a js file like this:-
...ANSWER
Answered 2021-May-09 at 22:24You could try this, you have to loop at every item and render a component.
QUESTION
I want to separate this list into two different list. The pattern that I saw the fruit is the number 1. always followed by fruit, while animal placed between whitespace except the last one.
ANSWER
Answered 2021-May-04 at 07:59text = ['1.banana dog 2.apple cat 3.grape tiger 4.orange snake']
textlist = text[0].split()
fruitlist = []
animallist = []
for word in textlist:
if "." in word:
fruitlist.append(word.split(".")[1])
else:
animallist.append(word)
fruit = " ".join(fruitlist)
animal= " ".join(animallist)
QUESTION
I have an array of objects
...ANSWER
Answered 2021-Apr-28 at 03:43You need to return true only after the loop finishes, else you're returning inside the first iteration regardless.
You also need to make sure that the item after the one you're iterating over exists before comparing, so don't iterate to the very end, iterate to one before the very end.
QUESTION
I'm trying to solve this simple riddle at codingames and I thought i will exercise in OOP However, it seems I've forgotten how CPP works in this field and I got an error I do not comprehend.
...ANSWER
Answered 2021-Apr-25 at 21:45You are sufferring from object slicing, both in your return type from from_str and in your vector .
Like it or not, you are going to have to use pointers, but if you use smart pointers then the pain will go away. So, first change your from_str function like so:
QUESTION
I could not build up the solution how to find the previous element without specific pattern.
Description: In the select option below is a simple Select box. The parent items have no - or dash, and the parents are created, then the children option values, so always, the children option values have greater value than parent value.
I am trying to find the parent value if a element is selected, if the element selected is parent, then return the parent value.
This is simple and obvious problem but I could not figure out the problem, if anyone could show how to get the above.
The html is from CMS - Drupal the html can not be changed
...ANSWER
Answered 2021-Apr-23 at 14:47This code will get you the parent value on child options if that's what you wanted.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install lizard
You can use lizard like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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