Sushi | Automatic subtitle shifter based on audio | Video Utils library

by tp7 Python Version: 0.5.1 License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | Sushi Summary

Sushi is a Python library typically used in Video, Video Utils applications. Sushi has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can download it from GitHub.

Automatic shifter for SRT and ASS subtitle based on audio streams.

Support

Quality

Security

License

Reuse

Support

Sushi has a low active ecosystem.

It has 567 star(s) with 37 fork(s). There are 34 watchers for this library.

It had no major release in the last 12 months.

There are 19 open issues and 21 have been closed. On average issues are closed in 42 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of Sushi is 0.5.1

Quality

Sushi has 0 bugs and 28 code smells.

Security

Sushi has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Sushi code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Sushi is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

Sushi releases are available to install and integrate.

Build file is available. You can build the component from source.

Installation instructions are not available. Examples and code snippets are available.

Sushi saves you 932 person hours of effort in developing the same functionality from scratch.

It has 2126 lines of code, 222 functions and 15 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed Sushi and discovered the below as its top functions. This is intended to give you an instant insight into Sushi implemented functionality, and help decide if they suit your requirements.

Main function
Creates argument parser
Return a Timecode instance for the given fps
Parse a string into a Timecode object
Read the specified number of frames from the file
Parse command line arguments
Validate the arguments
Create SRTEvent objects from a file
Read a format chunk
Return a MediaInfo object
Return a list of SubtitlesStreamInfo objects
Extract MediaStreamInfo object from the info
Returns a list of MediaStreamInfo objects
Create a SRTEvent object from a string

Get all kandi verified functions for this library.

Sushi Key Features

No Key Features are available at this moment for Sushi.

Sushi Examples and Code Snippets

No Code Snippets are available at this moment for Sushi.

Community Discussions

Trending Discussions on Sushi

JavaScript: Comparing Two Arrays and Replacing Objects

How can I split a string into separate keys and values?

Transferring JavaScript objects to HTML table

Taking an object's element and turning it into a button's innerHTML

Posting array of objects to REST API with ReactJS

Get recursive rootID of parent-child-table with ef-core

I can't delete an item from a drop-down menu properly. It deletes more than one

select first order for each customer from two tables

R: Converting "tidyr/tidyverse" statements to "dplyr" and "reshape2"

R: Automatically Producing Histograms

QUESTION

JavaScript: Comparing Two Arrays and Replacing Objects

Asked 2021-Jun-06 at 00:27

I have two arrays that I would like to compare against each other based on the Username and create a new array that includes EmployeeName

...

ANSWER

Answered 2021-Jun-06 at 00:20

You can make a Map to store information about each employee such as EmployeeName at each key (being the Username). Then you can use .map() on your first array and use the OrderBy key to grab the associated employee data from the map you made, which you can then spread into the resulting new object:

Source https://stackoverflow.com/questions/67854852

QUESTION

How can I split a string into separate keys and values?

Asked 2021-Jun-03 at 21:47

I have the following string:

...

ANSWER

Answered 2021-Jun-03 at 19:49

Try this:

Source https://stackoverflow.com/questions/67827561

QUESTION

Transferring JavaScript objects to HTML table

Asked 2021-May-31 at 07:11

The object within an object contains variables such as "name", "amount", "amountType", and "cal". The strings on those variables should be transferred through loop as several row in the given HTML table. Each variable should be on its own cell.

I already made one row and made 4 cell for the name, amount, amount type, and calorie columns. Then, I tried to transfer the objects elements inside the cell using the index of the object.

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ANSWER

Answered 2021-May-31 at 07:11

You're treating the mealObj as an array while it's an object and also you're not looping, so your code only runs once.

Below you can find a code that works for the first Menu (Steak). You might need to account for multiple meals by creating multiple tables.

Source https://stackoverflow.com/questions/67768563

QUESTION

Taking an object's element and turning it into a button's innerHTML

Asked 2021-May-31 at 04:03

On the function "createIngrList", it should take all the ingredient names, such as "Butter", "Beef", "Onion", etc., and turn it into buttons. So each button should have a text with the name of an ingredient written on it. As of now, there is just 4 buttons with "undefined" written on it. If possible, all the repeating ingredients such as "Onion" should not be made into button twice. Once is enough.

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ANSWER

Answered 2021-May-31 at 00:33

I think this may be what you are looking for... Though you mention not parsing ingredients that are listed twice, though each food, only has an ingredient listed in your object once. Correct me if I am wrong I will refine answer.

You can use for/in loops to get the nested ingredients and their foods. Then use the obj.name to get the name. Through the first for/in loop the key -> i will be the name of the food, then use the second key along witht he first to get the actual .name => obj[i][k].name this will give you the ingredient name.

I also created a couple of divs to palce the food and its buttons wrapped in divs for styling, etc...

You can use conditionals to filter by food if you want to only show a certain type of foods ingredients as buttons.

NOTE: your obj key for the first value is uppercase, this will cause issues when parsing obj[index][key].name, likely that is just a typo...

Source https://stackoverflow.com/questions/67766627

QUESTION

Posting array of objects to REST API with ReactJS

Asked 2021-May-28 at 07:30

I am working on a project in which I need to post a new Course to my API. I tested this with POSTMAN and API works just fine, however when I try to post data using react fetch data is corrupted. While sending single strings like dishName: "pizza" works just fine and is shown in database I cannot manage to send an array of objects. I tried to do it in many ways like:

...

ANSWER

Answered 2021-May-27 at 21:44

You are setting the ingredients state as a string, so you are basically 'stringify' a string which will result in JSON SyntaxError. If you want to send an array that way you must specify the array bracket [ and ] in order to make it a valid array.

To solve it just change:

Source https://stackoverflow.com/questions/67730171

QUESTION

Get recursive rootID of parent-child-table with ef-core

Asked 2021-May-21 at 20:26

I have an SQL-Table which is build like a tree list (parent child). Means you have rootId's and childId's. Each entity has a ParentId. If the ParentId is null then that element is a root item.

Here an example of the hierarchical architecture

...

ANSWER

Answered 2021-May-21 at 20:26

If you don't interest to load all records from database then process them, you have two choices :

Solution 1 : Write a StoreProcedure and processing in database.

Solution 2 : Write a recursive function that send multiple requests to database (In the amount of root depth)

Here is a function for solution 2 :

Source https://stackoverflow.com/questions/66242101

QUESTION

I can't delete an item from a drop-down menu properly. It deletes more than one

Asked 2021-May-19 at 13:28

The HTML create two drop-down menu and one delete button. One JavaScript, I made a code to fill those drop-down box with arrays. And, every time I change the item on the first drop-down menu, a new set of options appears on the second drop-down menu. The goal is, whenever I clicked the delete button, I should be able to delete an item on the second drop-down and when I changed the item on the first drop-down menu, hence another set of option will appear on the second drop-down menu, I should be able to delete an item from there as well.

The problem is, once the set of items on the second drop-down menu has been changed, a bunch of unwanted results occurs, such as deleting more than one items or deleting on another set of items. For example, if I delete something from "meal", it'll delete one item. Then if I go over to "dessert" and delete something from there, it'll delete one item. But if I go back to "meal" again, a bunch of items are now deleted. Just try it out yourself to see what I mean

...

ANSWER

Answered 2021-May-19 at 13:28

What were you doing wrong?
In practice your code stored in the variable menuOption the first menu, doing so every time you tried to delete something it was removed from the first menu

Solution

Call up the menu variable as often as needed
Store index before remove it
Extra:
- Use menuList.selectedIndex instead of drinkListArr.indexOf(subMenuOption)
- Use menuType.value instead of menuType.options[menuType.selectedIndex].text

Source https://stackoverflow.com/questions/67603885

QUESTION

select first order for each customer from two tables

Asked 2021-May-18 at 11:39

Hi guys I have two tables dbo.Sales (customer_id, order_date, product_id) and dbo.Menu (Product_id, product_name, price). The question is What was the first item from the menu purchased by each customer?

My solution is

...

ANSWER

Answered 2021-May-18 at 11:39

You could use a ROW_NUMBER() window function to get the earliest product_id per customer and then join to the Menu table to get your product details.

Edit: Updated ORDER to ASC.

Source https://stackoverflow.com/questions/67561322

QUESTION

R: Converting "tidyr/tidyverse" statements to "dplyr" and "reshape2"

Asked 2021-Apr-29 at 18:33

I am working with the R programming language. In a previous post (R: converting tidyverse to dplyr/reshape2 for plots), I learned how to make automatic histograms for all categorical variables in my dataset:

...

ANSWER

Answered 2021-Apr-29 at 18:33

With reshape2::melt, specify the id columns in id.vars i.e. deselect_not_factors, and the corresponding arguments for names_to and values_to are variable.name and value.name

Source https://stackoverflow.com/questions/67322709

QUESTION

R: Automatically Producing Histograms

Asked 2021-Apr-29 at 04:41

I am using the R programming language. I created the following data set for this example:

...

ANSWER

Answered 2021-Apr-29 at 04:30

A ggplot2/tidyverse solution is to lengthen each column into data and then use faceting to plot them all in the same page:

(with edit to plot only factor variables)

Source https://stackoverflow.com/questions/67310844

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Sushi

You can download it from GitHub.
You can use Sushi like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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