simplification | fast LineString simplification using RDP | Map library
kandi X-RAY | simplification Summary
kandi X-RAY | simplification Summary
Simplify a LineString using the Ramer–Douglas–Peucker or Visvalingam-Whyatt algorithms.
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simplification Key Features
simplification Examples and Code Snippets
Lines of Code : 90License : Non-SPDX (Apache License 2.0)
Copydef sigmoid_cross_entropy_with_logits_v2( # pylint: disable=invalid-name
labels=None,
logits=None,
name=None):
r"""Computes sigmoid cross entropy given `logits`.
Measures the probability error in tasks with two outcomes in which eac def set_optimizer_experimental_options(options):
"""Set experimental optimizer options.
Note that optimizations are only applied in graph mode, (within tf.function).
In addition, as these are experimental options, the list is subject to change Community Discussions
Trending Discussions on simplification
QUESTION
This is a followup or more a simplification of this question Error: File header.tex not found in resource path in a rmarkdown generated pdf report from a shiny app
With this Rmarkdown code I can achieve what I want:
logo.png
report.Rmd
...ANSWER
Answered 2022-Apr-09 at 16:36Basically you already figured out what's the issue. Hence one approach to fix your issue would be to do copy both the report template and the logo to the same temporary directory.
QUESTION
I would like to generate a list of combinations. I will try to simplify my problem to make it understandable.
We have 3 variables :
- x : number of letters
- k : number of groups
- n : number of letters per group
I would like to generate using python a list of every possible combinations, without any duplicate knowing that : i don't care about the order of the groups and the order of the letters within a group.
As an example, with x = 4, k = 2, n = 2 :
...ANSWER
Answered 2022-Mar-31 at 18:01Firstly, you can use a list comprehension to give you all of the possible combinations (regardless of the duplicates):
QUESTION
I'm currently working on a codebase and struggling to find an optimal and clean solution. I've removed the context of the problem to help simplify it to its root components. The Scale property is a simplification for a more complex state of the class in the actual codebase. I have an idea (which I'll reference at the bottom) for how I could solve this issue - however the solution feels messy and just avoids the area I want to better understand.
Class Hierarchy
...ANSWER
Answered 2022-Apr-01 at 08:32The type hierarchy will be called in the order from most base type -> most derived.
As you do not have overriden methods in Parent then your Scale is not multiplied. That it is a reason why you got 16. It is better to debug and see order of execution of your code.
You can add override GetTrueScale() method of class Parent to have desired value 64. The whole code will look like this:
QUESTION
Imagine you have a fleet consisting of various vehicles, including electronic cars. Each vehicle has a tracking device to record its trips. The goal is to analyze these trips (after a month/year) whether all of the historic trips would have been possible if a fleet size was reduced. Can you point me to an algorithm, research paper, or a library that can do that? Heuristics for simplification are also possible and welcomed.
Unlike in typical vehicle routing problems, we are not trying to find the optimal route. The routes are already given, and cannot be changed. Re-Planning of future trips is not in the scope of this analysis. Unfortunately, I only found algorithms and libraries for minimizing trips that also optimize the routes.
As an example, let's assume that there are three locations A, B, and C. Each location is the home base for a set of vehicles V1, V2, …, VN from where the initial trip can be made. A recorded trip T has a starting and destination location and timestamps for when the trip started and ended. Let's say we are analyzing trips of just one day and the following trips are made:
7:00 - 9:00 Vehicle V1 made a trip from location A to B.
8:00 - 9:00 Vehicle V2 made a trip from location B to C.
10:00 - 11:00 Vehicle V3 made a trip from location B to C.
12:00 - 13:00 Vehicle V3 returned from location C to B.
14:00 - 15:00 Vehicle V1 returned from location B to A.
14:00 - 15:00 Vehicle V2 returned from location C to B.
15:00 - 16:00 Vehicle V4 made a trip from location C to A.
16:00 - 17:00 Vehicle V4 returned from location A to C.
In this example, vehicle V1 was idle at location B and could have replaced trips of vehicle V3. Vehicle V4 was also idle at that time but could not replace these trips because it was in another location.
In reality, we would also need to check whether electronic cars doing additional trips had enough time to recharge.
...ANSWER
Answered 2022-Mar-15 at 02:08Here’s an algorithm that assumes instantaneous recharging. Gather the list of arrivals and departures and sort them by time.
Time Location Δ 0700 A −1 0800 B −1 0900 B +1 0900 C +1 1000 B −1 1100 C +1 1200 C −1 1300 B +1 1400 B −1 1400 C −1 1500 A +1 1500 B +1 1500 C −1 1600 A +1 1600 A −1 1700 C +1Now compute the running sums for each location.
Time A B C 0 0 0 0700 −1 0 0 0800 −1 −1 0 0900 −1 0 1 1000 −1 −1 1 1100 −1 −1 2 1200 −1 −1 1 1300 −1 0 1 1400 −1 −1 0 1500 0 0 −1 1600 0 0 −1 1700 0 0 0Track the minimum value attained in each location. This is minus the number of vehicles required in that location at the start (one in each location here).
Charging does seem make this problem harder. You could get a guaranteed overestimate by pushing out each vehicle arrival by the amount of time it would have taken to fully recharge. Maybe that’s good enough for forecasting purposes?
QUESTION
I have an Rmarkdown with a simple scatter plot (a map for instance), and I would like users to be able to provide some arbitrary x and y coordinates via an input and have those plotted on the graph (in red in the example below). The problem is, I don't have a shiny server so I cannot rely on that option. Is there a implement this, for instance, via javascript or something?
This is what I have:
...ANSWER
Answered 2022-Mar-04 at 19:18This may not be what you want but you can do this by adding a runtime of shiny in your yaml
QUESTION
I have two objects, from same class type. They both have a property (and its private field). Conditionally, I would like to assign this property/field as a reference to the same property/field of another instance of the same class.
It's important to note that my requirement is to read the referenced field. Write to it would be a bonus, not a problem, and not necessary.
I would like to know if it would be possible to use a ref field, and do some logic inside the property getter.
Also, I know there has been some questions about this here on StackOverflow (here, here, here, here), but they are all pretty old (so the idea of duplicate does not seem to apply here).
Now we are on C# 10.0, and a lot of different ref capabilities had been implemented, like ref locals. I tried to use some of them, but I failed. Hope someone with more knowledge could help me to see a way to do it.
So, is it possible, without using a wrapper to link one instance's property to another?? (which is my current approach, detailed below)
More details:
That's my class (actually it's a huge simplification of it):
...ANSWER
Answered 2022-Mar-04 at 14:52I'm not familiar with all of the new features of C# 10.0, but you can achieve the desired behaviour by treating the name as an object in it's own right, and referencing the Name object in each of your Person instances. i.e. just treat it as a composition
QUESTION
I came across this error when modifying a DB first project (using fluent migrator) and scaffolding the EF context to generate models. I have reproduced it by making a code-first simplification. This means that I can't accept answers that suggest modifying the annotations or fluent configuration, because this will be deleted and recreated on the next migration and scaffold.
The simplified idea is that a device has:
- many attributes
- many histories representing changes to the device over time
- each history entry has an optional location
IOW you can move a device around to locations (or no location) and keep track of that over time.
The code-first model I came up with to simulate this is as follows:
...ANSWER
Answered 2021-Nov-10 at 06:20Update: The bug is fixed in EF Core 6.0, so the next applies to EF Core 5.0 only.
Looks like you have hit EF Core 5.0 query translation bug, so I would suggest to seek/report it to EF Core GitHub issue tracker.
From what I can tell, it's caused by "pushing down" the root query as subquery because of the Take operator (which is basically what First method is using in the second case). This somehow messes up the generated subquery aliases and leads to invalid SQL.
It can be seen by comparing the generated SQL for the first query
QUESTION
Suppose we have the following code:
...ANSWER
Answered 2022-Jan-24 at 14:51You can disable the simplifier with:
QUESTION
I have to simplify custom regex expressions parsed to a certain data type. With "simplify" I mean the following (emphasis mine):
Given the rules:
- lowercase letters match themselves, eg.:
amatchesaand nothing else- parens enclosing only letters match their full sequence, eg.:
(abc)matchesabcand nothing else- square brackets enclosing only letters match every letters inside, eg.:
[abc]matchesaandbandcand nothing elseThe following are all valid:
(a[bc])matchesabandacand nothing else[a(bc)]matchesaandbcand nothing else(a(bc))is the same as(abc)and matchesabcand nothing else[a[bc]]is the same as[abc]and matchesaandbandcand nothing elseRegexes can be simplified. For example
[a[[bb]b[[b]]](c)(d)]is really just the same as[abcd]which matchesa,b,candd.
I have implemented a simple parser combinator in Haskell using attoparsec and the following destination data type:
ANSWER
Answered 2022-Jan-23 at 04:19You are missing a couple simple improvements, for starters. simplify (Concat [x]) = x and likewise for Union: there's no need for the wrapped regex to be specifically a symbol.
Then you need to start looking at Concats containing other Concats, and likewise for Union. Sure, you start by simplifying the elements of the wrapped list, but before jamming the result back into a wrapper, you lift up any elements using the same wrapper. Something like:
QUESTION
I'm trying to simplifying the following in maxima:
...ANSWER
Answered 2022-Jan-11 at 16:03I sent this through the maxima mailing list and got a response from Barton Willis (willisb@unk.edu). I'm posting the answer here so it will be useful for others:
Try using scanmap('factor,%); thus:
(%i10)
(6Cb3mω+(8%iR0^3b^3-24*%iR0^3ab^2+24%iR0^3a^2b-8%iR0^3a^3)Γ+3AEa3pk+2%iKb3m)/(6Cω+3AEk+2%i*K)$(%i11) scanmap('factor,%);
(%o11) (6Cb3mω+8%iR0^3(b-a)^3Γ+3AEa3pk+2%iKb3m)/(6Cω+3AEk+2%i*K)
--Barton
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