bvec | Fast Vector Operations on Pretty Big Data
kandi X-RAY | bvec Summary
kandi X-RAY | bvec Summary
Fast Vector Operations on Pretty Big Data
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Top functions reviewed by kandi - BETA
- Generate a 32 - bit memory matrix
- Compute the dot product of a matrix
- Create an empty buffer
- Create a copy of a matrix
- Print an error message and exit
- Print an alarm
- Generate a random time matrix
- Print a warning message
bvec Key Features
bvec Examples and Code Snippets
Community Discussions
Trending Discussions on bvec
QUESTION
I am having trouble with the scala .getorElse
command. I want to generate AVec
at all times, but I only want AVec
and BVec
when elemA >= 50
, and lastly, I want all of them to be generated when elemA >= 100
. I have tried .get
with no luck and below you can see the implementation with .getorElse
.
Any advice on how to implement this correctly would be greatly appreciated. Thanks!
...ANSWER
Answered 2021-Mar-18 at 19:50Given the style of what you're writing, why not do?
QUESTION
If I have a Vec
I can't convert it into Vec
directly using .into()
even if I can convert T
into U
using .into()
. For example this code does not compile:
ANSWER
Answered 2021-Feb-24 at 13:27The issue (currently) with having a blanket implementation for converting containers, is that it conflicts with the existing blanket implementation impl From for T
.
To be able to get around that, it would in short require specialization (Issue #31844).
QUESTION
I have the following model.
...ANSWER
Answered 2020-Dec-04 at 18:47To concatenate two tensors use the layer Concatenate
with the axis properly set which in your case is 2.
QUESTION
I want to solve an optimization problem regarding a minimum variance portfolio using R as shortly described on this website: http://enricoschumann.net/R/minvar.htm
The problem is: the matrix I want to use has more columns (=assets) than rows (=observations), which is why it is not positive definite and non-invertible.
You can recreate this problem by taking the opposite values for the variables as on the website, which results in the following:
...ANSWER
Answered 2020-Sep-30 at 12:20You can try:
QUESTION
I have a .txt file with numeric indices of certain 'outlier' data points, each on their own line, called by $outlier_file:
...ANSWER
Answered 2020-Jul-23 at 03:36To delete the outliers from bvec_file after the loop and only delete the ones where the associated file was successfully removed:
QUESTION
I would like to include "signs" in my constraints regarding an LP problem.
For example,
Maximize 120X1 + 230X2 + 410X3 + 100X4
580X1 + 600X2 + 800X3 + 300X4 ≤ 1000
0 ≤ X1 ≤ 10
6 ≤ X2 ≤ 10
5 ≤ X3 ≤ 12
0 ≤ X4 ≤ 10
The code is as follows,
library(lpSolve)
...ANSWER
Answered 2020-May-29 at 17:18Note that 580X1 + 600X2 + 800X3 + 300X4 ≤ 1000 makes the model infeasible. This is a very simple textbook LP solver, and does not seem to handle that very gracefully.
QUESTION
I am struggling with Solve.QP to get a solution to minimize tracking error. I have a benchmark consisting of 6 assets (asset_a to asset_f). For my portfolio I have upper and lower bounds (I cannot have a position in asset_f). The cov matrix is also given. I want to get the portfolio weights for the 6 assets that minimizes tracking error vs the benchmark (with position in asset_f equal to zero).
benchmark:
- asset_a: 0.3
- asset_b: 0.3
- asset_c: 0.1
- asset_d: 0.1
- asset_e: 0.1
- asset_f: 0.1
lowerbounds:
- asset_a: 0.166
- asset_b: 0.133
- asset_c: 0.037
- asset_d: 0.035
- asset_e: 0.039
- asset_f: 0
upperbounds:
- asset_a: 1
- asset_b: 1
- asset_c: 1
- asset_d: 1
- asset_e: 1
- asset_f: 0
benchmark weights and bounds:
...ANSWER
Answered 2020-May-19 at 00:33Seems like there is something wrong with your Amat
and bvec
, i.e. you need not have to pass in both sum of weights on first 5 assets equal to 1 and sum of 6 assets equal 1 and also benchmark weights are not constraints but the bounds are:
QUESTION
I am trying to make Scipy's ODE solver solve the Lorentz Force differential equations. It does not solve the equations correctly with the B-field component because it completely ignores the E-field no matter how large I make it (Which is also why I know it is ignoring it). Why is this? I have already tried modifying the sign on the E-field function too.
Code:
...ANSWER
Answered 2020-Feb-25 at 20:47You define P0[2] = 0.
. The electric field function computes Ez = 2.8E8*z**4
. Hence, python is not ignoring the E-field function, you are putting its z component to zero yourself: z = P0[2] = 0
.
QUESTION
I have three structs:
...ANSWER
Answered 2020-Feb-16 at 17:05You can:
- Find the index of the element satisfying
predicate
. (I would useIterator::position
.) remove
orswap_remove
the element at the position obtained by the previous step.push
the previously removed element into result.
In code:
QUESTION
I have a file with data formatted as follows:
a 1.000 -1.000 1.000
b 7.89 4.56 2.46
c 50 20 10
I started writing some code to parse the file and store the data in a vector of structs, but I'm unsure of how to finish this.
...ANSWER
Answered 2019-Mar-15 at 04:15Instead of using
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