rDrop | Programmatic interface to Dropbox | Content Management System library
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Programmatic interface to Dropbox
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QUESTION
I'm new to Forth and I'm using SwiftForth. I am looking for a way to read a matrix from file as described here Writing a text file into an array on Forth, but rdrop
is not recognised. Is this exclusive to Gforth or is it part of a library? If it's a library, what are the steps needed to use it?
ANSWER
Answered 2021-Jan-30 at 11:23RDROP
is a well known but not standardized word.
This word can be defined in the following way:
QUESTION
From very nice Paper and article about memory reordering.
Q1: I understand that cache-coherence, store buffer and invalidation queue is root cause of memory reordering ?
Store release is quite understandable, have to wait for all load and store are completed before set flag to true.
About load acquire, typical use of atomic load is waiting for a flag. Suppose we have 2 threads:
...ANSWER
Answered 2019-Nov-11 at 18:05The C++ standard doesn't specify the code generated by any particular construct; only correct combinations of thread communication tools product a guaranteed result.
You don't get guarantees from the CPU in C++ because C++ is not a kind of (macro) assembly, not even a "high level assembly", at least not when not all objects have a volatile type.
Atomic objects are communication tools to exchange data between threads. The correct use, for correct visibility of memory operations, is either a store operation with (at least) release followed by a load with acquire, the same with RMW in between, either the store (resp. the load) replaced by RMW with (at least) a release (resp. acquire), on any variant with a relaxed operation and a separate fence.
In all cases:
- the thread "publishing" the "done" flag must use a memory ordering at least release (that is: release, release+acquire or sequential consistency),
- and the "subscribing" thread, the one acting on the flag must use at least acquire (that is: acquire, release+acquire or sequential consistency).
In practice with separately compiled code other modes might work, depending on the CPU.
QUESTION
Even though Memory barriers: a hardware view for software hackers book is considered extremely old (by it's author, seems like Paul himself answered this question) I find it as an excellent helper to build a mental model around memory ordering.
There is a little thing though that I don't understand:
Let's consider the page with a memory barrier:
Step 4 states that "b=1" is written to a store buffer because "a=1" is not written to the cache yet.
The thing that I can't get is why on the next page:
on step 3 "b=1" is written to the cache line, even though there is a memory barrier after "a=1" and "a=1" is not yet written to the cache? Following the previous page reasoning "b=1" should be written to the cache only after (or within) step 10, when a store buffer, containing "a=1" is written to the cache.
...ANSWER
Answered 2018-Jul-12 at 10:22The pdf that you posted is different from the screenshot in your question, so I am presuming the old version was incorrect (or at least not precise enough).
Chapter 4.3. actually starts with the following remark:
Let us suppose that CPUs queue invalidation requests, but respond to them immediately. This approach minimizes the cache-invalidation latency seen by CPUs doing stores, but can defeat memory barriers, as seen in the following example.
The sequence is also a bit different than what you posted:
CPU 0 executes
a=1
. The corresponding cache line is read-only in CPU 0’s cache, so CPU 0 places the new value of "a" in its store buffer and transmits an "invalidate" message in order to flush the corresponding cache line from CPU 1's cache.CPU 1 executes
while (b==0) continue;
, but the cache line containing "b" is not in its cache. It therefore transmits a "read" message.CPU 1 receives CPU 0's "invalidate" message, queues it, and immediately responds to it.
CPU 0 receives the response from CPU 1, and is therefore free to proceed past the
smp_mb()
on line 4 above, moving the value of "a" from its store buffer to its cache line.
I believe this is a hypothetical scenario, but when you take this into account, the obviously problematic part is CPU 1 acknowledging an "invalidate" message before actually invalidating its cache, which makes CPU 0 think it can proceed.
QUESTION
I'm using mutt with GnuPG on Ubuntu. I have these general settings for GnuPG:
...ANSWER
Answered 2018-Mar-29 at 15:18The answer is use GPGME. The GPGME library encapsulates most, if not all, commonly used GnuPG functions. With just a few configuration lines everything GnuPG related "just works." This posting is a good guide: https://sanctum.geek.nz/arabesque/gnu-linux-crypto-email/
In the end my setup now looks like:
QUESTION
I am copying the text for that figure from the original paper, Memory Barriers: a Hardware View for Software Hackers.
Table 4 shows three code fragments, executed concurrently by CPUs 0, 1, and 2. All variables are initially zero.
Note that neither CPU 1 nor CPU 2 can proceed to line 5 until they see CPU 0’s assignment to “b” on line 3. Once CPU 1 and 2 have executed their memory barriers on line 4, they are both guaranteed to see all assignments by CPU 0 preceding its memory barrier on line 2. Similarly, CPU 0’s memory barrier on line 8 pairs with those of CPUs 1 and 2 on line 4, so that CPU 0 will not execute the assignment to “e” on line 9 until after its assignment to “a” is visible to both of the other CPUs. Therefore, CPU 2’s assertion on line 9 is guaranteed not to fire.
To me, Line 6-9 on CPU0 seems unnecessary at all, because the memory barrier on Line 2 for CPU 0 and memory barrier on Line 4 for CPU 1&2 guarantees that the effect of b=1
is picked up, and all stores before as well, aka a=1
. Then, the assert e == 0 || a == 1
succeeds always.
I don't know if I overlooked anything. Any clarification is appreciated.
...ANSWER
Answered 2017-Oct-11 at 02:47Leaving lines 6-9 out of CPU 0 would definitely prevent the assert() from firing. Then again, so would removing all the code other than the assert, given that e
is initialized to zero. However, both modifications are unhelpful. Instead, the key point of the assertion is the question "Is it possible for CPU 2 to see the state e==1&&a==0
at the end of its execution?" Looking at it this way should force you to think in terms of what values propagate where in what order.
But the main thing you overlooked is that this paper is extremely old, and there has been a huge amount of progress in understanding and formalizing memory ordering since then. I am in the process of adding a new memory-ordering chapter to Is Parallel Programming Hard, And, If So, What Can You Do About It? In the meantime, the pair of LWN articles here and here may be helpful.
Or if you want to see the current state of the book, git clone git://git.kernel.org/pub/scm/linux/kernel/git/paulmck/perfbook.git
.
QUESTION
I know that there is a package (rDrop) to upload R objects into Dropbox.
I'm using stargazer to consolidate my regressions in clean HTML tables.
Is there a way to upload these into Dropbox as well? So not R objects? Or is there a workaround to get the job done - maybe by defining a working directory?
The main problem I'm facing is that I'm working from a cloud instance and cannot install Dropbox there. So I am looking for a way to upload to Dropbox without having a local Dropbox directory.
...ANSWER
Answered 2017-Aug-23 at 17:35You can use the rDrop2
package to upload ANY file into Dropbox - it's just an API wrapper for the Dropbox service.
Below is some pseudocode which should work once you authenticate on your own machine using the package:
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Install rDrop
To begin, create an App on Dropbox from the Dropbox developer site. You will need to log in with your Dropbox username and password.Then, click Create An App.
Next, provide a unique (in the universe of Dropbox apps) name to your personal app. Dropbox branding guidelines prohibit the use of the word "Dropbox" or names that begin with "Drop". We recommend that you name the app "Your_first_name_last_name_rDrop" to avoid naming conflicts but feel free to call it whatever you like. You won't have to deal with the app name after this step.
Once you click create, be sure to copy your App key and App secret and store it somewhere safe. If you forget it, you can always find it here (Just click on options next to your App name). If you use your .rprofile and no one else uses your computer, then we recommend you save your keys there by adding the following lines:
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