dfs | Frequency Spectrum : Signatures of introgression | Video Utils library
kandi X-RAY | dfs Summary
kandi X-RAY | dfs Summary
DFS is a simple extension to the classic D statistic (AKA the ABBA BABA test). DFS partitions D according to the frequencies of derived alleles. Thus, it reveals how the overall D value is broken down across different allele frequency classes (or bins). DFS therefore carries information about the timing and direction of introgression. Check out this SHINY app that allows you to explore how DFS behavies over a range of model parameters.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of dfs
dfs Key Features
dfs Examples and Code Snippets
public static boolean doDFS(Project project, Stack stack) {
if (project.getState() == Project.State.PARTIAL) {
return false; // Cycle
}
if (project.getState() == Project.State.BLANK) {
project.setState(Project.State.PARTIAL);
ArrayL
private static Path dfs(int targetIdx, int curCity, int[] target, Map> graph, Path[][] dp) {
if (targetIdx == target.length) return new Path(0, new ArrayList<>());
if (dp[curCity][targetIdx] != null) return dp[curCity][target
function dfs(idx, level, graph) {
var str = '';
for(var i = 1; i <= level; i++) {
str += ' |';
}
var char = idxToChar(idx);
str += ('-->' + char);
console.log(str);
for(i = 0; i < graph[idx].length; i++) {
Community Discussions
Trending Discussions on dfs
QUESTION
I have 2 dfs (simplified example):
...ANSWER
Answered 2021-Jun-15 at 01:51You can do this by using the dplyr package:
QUESTION
I have two data frames. df1 and df2. both with c columns
using a clustering method, I ended up with 10 clusters. same clusters for each df is true. this means for example the 4th row of both df s go to the same cluster.
I added a cluster column to both dfs, showing the assigned cluster for each row.
I want to create a list.
this list contains 10 matrices, such that.
matrix 1, is a 2*c matrix. its first row is obtained by colmeans of those rows of df1 which are in cluster 1. and its 2nd row is obtained by colmeans of those rows of df2 which are in cluster 1.
and matrix 2 , colmeans of cluster 2 and so on.
this is what I ve done. but I get the 10th matrix only and not a list of matrices 1 to 10.
I would appreciate any help with this.
ANSWER
Answered 2021-Jun-14 at 17:39The Mean.list
should be initialized outside the loop and it can be a NULL list
of length k
QUESTION
I have the following dataset and I want to compute all possible combinations of cross-tabulations in the most efficient way, I have been able to calculate pairs against one master variable, but not for all possibilities (i have popped what i mean in below). Is there a way to get this all in loop that could handle any number of columns? Thanks so much!
data
...ANSWER
Answered 2021-Jun-10 at 15:09Try with the itertools recipe for a powerset
and modify to only keep combinations of length 2 or greater:
QUESTION
I am trying to scrape the NBA player names and projected fantasy score (not single stat DFS) using selenium. I've gotten as far as using selenium to automate clicking NBA, and selecting the fantasy score tab.
From there, I see the players in a grid where I will like to scrape the points and names for each player. I have attempted to loop through the grid but I don't think I'm doing it right
Can someone please take a look at my code and point me in the right direction ?
...ANSWER
Answered 2021-Jun-12 at 18:58See you are using
QUESTION
Working on a project that updates a database. New values (Rows) are updated from a folder containing Excel files. The values in the Excel files are provided by employees. Sometimes these employees are still working in the Excel file while trying to update the database. This results in a PermissionError.
To avoid PermissionErrors, I use the Try and Except statement. This works fine but situations can occur that Excel files are not closed for a while and multiple Excel files are opened during the day.
Thus, just one Try and Except statement wouldn't work. Therefore I used three Try and and Except statements which still doesn't guarantee that errors are handled properly.
To solve this, I think a While loop or a break statement within the for loop would work? Tried to add a break statement at the end of the (first) except block but this didn't work..
Is there any way to tackle this? Adding more Try and Except statements would work, but that just seems silly.
...ANSWER
Answered 2021-Jun-11 at 22:51This is clearly iterative code, not cascaded dependencies. Yes, use a loop.
QUESTION
I am trying to pick samples within each group:
...ANSWER
Answered 2021-Jun-11 at 15:48library(tidyverse)
set.seed(1)
n_repeat <- 2
n_sample <- 2
df <- data.frame(ID=c(1,1,1,2,2,2), score=c(10,20,30,40,50,60))
df %>%
group_nest(ID) %>%
transmute(ID,
Score = map(data, ~as.vector(replicate(n_repeat, sample(.x$score, 2))))) %>%
unnest(Score) %>%
group_by(ID) %>%
mutate(sample_no = rep(seq(n_repeat), each = n_sample)) %>%
ungroup()
#> # A tibble: 8 x 3
#> ID Score sample_no
#>
#> 1 1 10 1
#> 2 1 20 1
#> 3 1 30 2
#> 4 1 10 2
#> 5 2 50 1
#> 6 2 40 1
#> 7 2 60 2
#> 8 2 40 2
QUESTION
I'm going to explain what my code is supposed to do:
First I import an arbitrary number of dataframes of the same number of columns and somewhat similar names (they're stock tickers).
Second, I create a function that changes the data type of the first column (from factor to date), deletes one column and finally adds an arbitrary number of columns as functions of the other columns (like returns, moving average, etc.)
Finally, since I'm working with plenty of dataframes, I want to apply this said function to all of them through a loop.
Now, as simple as this sounds, I've encountered many issues with the third step.
What I found online was this, to get all names of the dataframes in my environment:
...ANSWER
Answered 2021-Jun-11 at 03:54Keeping your original formatear
function
QUESTION
I have the following two dummy dfs:
...ANSWER
Answered 2021-Jun-09 at 18:27I assume that you simply want to rotate the plot, add
orientation="horizontal"
.You can share the axis of subplots by setting
sharex=True
orsharey=True
.To share the range simply specify the limits of either axis:
plt.xlim(0,4)
andplt.ylim(-100,700)
QUESTION
I have 3 remote computers (servers):
- computer 1 has internal IP: 10.1.7.245
- computer 2 has internal IP: 10.1.7.246
- computer 3 has internal IP: 10.1.7.247
(The 3 computers above are in the same network, these 3 computers are all using Ubuntu 18.04.5 LTS Operating System)
(My personal laptop is in another different network, my laptop also uses Ubuntu 18.04.5 LTS Operating System)
I use my personal laptop to connect to the 3 remote computers using SSH protocol and using user root : (Below ABC is a name)
- computer 1:
ssh root@ABC.University.edu.vn -p 12001
- computer 2:
ssh root@ABC.University.edu.vn -p 12002
- computer 3:
ssh root@ABC.University.edu.vn -p 12003
I have successfully set up a Hadoop Cluster which contains 3 above computer:
- computer 1 is the Hadoop Master
- computer 2 is the Hadoop Slave 1
- computer 3 is the Hadoop Slave 2
======================================================
I starts HDFS of the Hadoop Cluster by using the below command on Computer 1: start-dfs.sh
Everything is successful:
- computer 1 (the Master) is running the NameNode
- computer 2 (the Slave 1) is running the DataNode
- computer 3 (the Slave 2) is running the DataNode
I know that the the Web Interface for the NameNode is running on Computer 1, on IP 0.0.0.0 and on port 9870 . Therefore, if I open the web browser on computer 1 (or on computer 2, or on computer 3), I will enter the 10.1.7.245:9870 on the URL bar (address bar) of the web browser to see the Web Interface of the NameNode.
======================================================
Now, I am using the web browser of my personal laptop.
How could I access to the Web Interface of the NameNode ?
...ANSWER
Answered 2021-Jun-08 at 17:56Unless you expose port 9870, your personal laptop on another network will not be able to access the web interface.
You can check to see if it is exposed by trying :9870 to see if it is exposed. IP-address here has to be the global IP-address, not the local (10.* ) address.
To get the NameNode's IP address, ssh into the NameNode server, and type ifconfig (sudo apt install ifconfig if not already installed - I'm assuming Ubuntu/Linux here). ifconfig should give you a global IP address (not the 255.* - that is a mask).
QUESTION
I am trying to use DFS in my answer.
Problem:
An Customer wants to buy a pair of jeans, shoes, skirt, and a top but has a limited budget in dollars. Given different pricing options for each product, determine how many options customer has to buy 1 of each product. You can not spend more money than budgeted amount.
Example
...ANSWER
Answered 2021-Jun-09 at 13:37Sorry it took me so long to get back to this - I was busy with the day job :-).
You weren't very far wrong. The only changes that need to be made are in GetShoppingItem, which I show in full below. I have deliberately kept the changes to a minimum, in order to preserve as much of your logic as possible, so that you will better understand what is happening.
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