rehash | Ruby on Rails blog app | Blog library
kandi X-RAY | rehash Summary
kandi X-RAY | rehash Summary
Rehash is a Ruby on Rails app that can host a personal blog. Articles are composed using Markdown syntax in a text editor and a generator script is run to turn them into HTML and insert them into a local database. Images that are added to articles must be linkable in development and production. Uploading images manually to S3 is the approach at this time. When a article has been previewed locally and the author is happy with it, the entire database can be pushed to production. Visitors may leave comments on articles for a period of time after the article is published. Authors of comments may edit and delete their comments for a period of time after the comment has been created. This is implemented with cookies so that visitors are not required to create an account or log in.
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rehash Examples and Code Snippets
Lines of Code : 48License : Permissive (MIT License)
Copypublic void insertKey2HashTable(int key) {
Integer wrappedInt = key, temp;
int hash, loopCounter = 0;
if (isFull()) {
System.out.println("Hash table is full, lengthening & rehashing table");
reHash private void reHash() {
ArrayList> old = buckets;
buckets = new ArrayList<>();
size = 0;
for (int i = 0; i < old.size() * 2; i++) {
buckets.add(new LinkedList<>());
}
for ( Community Discussions
Trending Discussions on rehash
QUESTION
I'm comparing MariaDB 10.6 vs PostgreSQL 14 in INSERT operation.
I created a table in both databases, then I tried to insert 1 Million rows in both.
In PostgreSQL, it takes only 2 seconds to INSERT 1 million rows.
But in MariaDB, it takes 9 seconds to INSERT 1 million rows.
But I want to work with MariaDB, so I tried to improve the my.ini but still PostgreSQL is about 2-4 times faster than MariaDB.
This is my table in both databases (no index in both, except the primary key with autoincrement)
ANSWER
Answered 2022-Feb-06 at 13:40You should try a (slightly) more comparable method, for example a set-based insert in MariaDB using a cross join to create a set:
QUESTION
I am wondering why the wrong version is selected here. Here is some information:
...ANSWER
Answered 2022-Jan-17 at 23:17Aliasing pyenv did it
QUESTION
So first I installed pyenv with brew install pyenv. After trying to install virtualenvs unsuccessfully I installed virtualenv with brew install pyenv-virtualenv. I noticed that there was no folder named ~/.virtualenvs so I made one and ran the command export WORKON_HOME=~/.virtualenvs.
I ran the steps:
export PATH=/Users//.pyenv/shims:$PATH
pyenv install 3.10.1
pyenv global 3.10.1
pyenv rehash
pyenv virtualenv 3.10.1 test1 (which gave no output, and the folder .virtualenvs remained empty)
export WORKON_HOME=~/.virtualenvs
source ~/.pyenv/shims/virtualenvwrapper.sh
The terminal then crashes and vanishes. I had to do a screen recording to get the error. This still is from a video of the vscode terminal crashing.
I am using a 2021 MacBook M1 Pro running Monterey
What's the problem here?
...ANSWER
Answered 2022-Jan-08 at 21:22I figured out how to run this environment, some of my steps were correct but I missed a few things.
So these are the correct install steps:
brew install pyenv
brew install virtualenv
brew install virtualenvwrapper
Then install the python version in pyenv, set it to global, and make sure your path sees this version of python first:
pyenv install 3.10.1
pyenv global 3.10.1
export PATH=/Users/myusername/.pyenv/shims:$PATH (keep in mind that you need to do this last command every time you start up another shell if you want your path to see the pyenv version of python first, unless you add the command to your .zshrc file)
Then
pyenv virtualenvwrapper (this is required for your terminal to see the virtualenvwrapper based commands)
mkvirtualenv my_venv
That should create the virtualenv in a way that is familiar with what you're used to using virtualenvwrapper. To activate this virtualenv in future sessions do:
pyenv virtualenvwrapper
workon my_venv
and to deactivate this environment simply type deativate
QUESTION
This is a basic question, but I've been banging my head against a wall trying to fix this and I'm stuck.
I'm cloning a rails project.
When I run bundle install I get:
ANSWER
Answered 2021-Dec-21 at 02:10It looks like you don't have rbenv set up in your shell. You can find the instructions on how to do this in the rbenv docs here.
QUESTION
I have a ROR app (version 6.1.4.1) with Ruby 2.7.4 on a Raspberry Pi 4 with 4 GB RAM and a 32 GB SD card. I installed Passenger 6.0.12 using the tarball installation and am running it with nginx. passenger start in the app directory works successfully, but when I try running it as with nginx (/opt/nginx/sbin/nginx) on port 80, I get the above error when visiting the site.
I'm accessing the app via IP address, which is configured in the nginx.conf and the app is installed in /home/pi/src/bogie_can. There is a .bundle directory with a config file in the app directory, and that's where the gems are installed. I'm running the app in "development" mode, which is configured in the server section of the nginx.conf file using passenger_app_env.
The specific error is that the app cannot find racc-1.5.2. The Bundler info is #.. So, we note that the .bundle path is correct and in the .bundle/ruby/2.7.0/gems/ directory, racc-1.5.2 is indeed installed and owned by the user "pi".
I've cleared out old bundle installations and tried switching the app user from pi to root (which was nobody) and back. Also, I'm using rbenv, so I also ran rbenv rehash after the fresh bundle install. I've also carefully reviewed the "Detailed diagnostics" from the Passenger error page (which is super helpful!) and do not see anything that is obviously wrong.
Using the Passenger error page as a guide, it seems that:
- The gems are indeed installed as needed
- The user, either root or pi, have permissions to access the gems
piis a reasonable user to run the app- The
passenger_rootandpassenger_rubyare coming from thepassenger-config aboutsubcommands and are verified as well.
At this point, there must be some configuration I've overlooked or gotten wrong and I would greatly appreciate some questions and pointers.
...ANSWER
Answered 2021-Dec-18 at 16:41I found the root cause of the problem.
I had set passenger_ruby to the result of passenger-command about ruby-command, which gave me:
QUESTION
I have a test container for Mysql and I need to import the dump file after the container started. I've tried two options below.
...ANSWER
Answered 2021-Dec-06 at 09:56You need an applications.properties suitable for MySql, something like:
QUESTION
I suppose there is something wrong with my bash init scripts (like .bashrc or .bash_profile). But let's start from beginning.
I can create and activate pyenv environment, but when I try to use python, I get error: -bash: python: command not found.
It looks like pyenv understands creation and swapping envorinments. I mean, it's probably not malformed. There is preview of my tries:
ANSWER
Answered 2021-Aug-05 at 08:06READ THE PYENV GUIDE CAREFULLY.
You didn't follow pyenv's README guide correctly. The guide tells you put PATH related operation in .bash_profile or .profile. But eval "$(pyenv init -)" in .bashrc.
Move pyenv init script from .bash_profile to .bashrc.
QUESTION
struct table
{
int size;
key_value *array[];
};
struct table *create_table(int size)
{
struct table *table = calloc(1, sizeof(struct table));
table->size = size;
return table;
}
void resize_table(struct table *table, int new_size)
{
struct table *new_table = create_table(new_size);
for(int i = 0; i < table->size; i++)
{
key_value *p = table->array[i]->next;
while(has_next(p))
{
insert(new_table, p->key, p->value);
p = p->next;
}
}
*table = *new_table;
}
ANSWER
Answered 2021-Oct-20 at 11:31There are a lot of misconceptions here.
key_value *array[];is a so-called flexible array member, a special feature. Specifically it is an array ofkey_valuepointers, of a size unknown at the point of declaration. It is an array, not a pointer.Therefore
table->array = new_table->array;tries to assign an array to another array, which isn't allowed in C. Arrays must be copied withmemcpyor similar.Flexible array members mostly make sense when you need to allocate adjacent memory directly following the struct. A hash table isn't an obvious use-case for such, but it can be made to work (and gives good cache performance). What you need to do when allocating a flex array member is to allocate room for the struct and the array in one go, like this:
QUESTION
It's been hours that I'm trying to understand the error but I don't get it.
I have tried to upgrade my ruby version from 2.5 to 2.7.4
I first update rbenv from brew then install the 2.7.4 version and used rbenv rehash
But now whenever I launch rails c or rails s, I've got the following errors:
ANSWER
Answered 2021-Oct-12 at 13:24Some dependencies of your existing gems may have been updated during an (implicit) brew upgrade run as you installed additional software.
When installing gems which use library dependencies (such as libgdal in your case), those gems may sometimes need to be re-compiled if the underlying library has changed in incompatible ways.
As such, a common first attempt to fix this to re-install the affected gem. If you use bundler, you can re-install all gems of your project by running
QUESTION
We have a PHP class that reads the database on user credentials, rehash SHA1 => BCrypt as needed. Works great, however these days we are developing a WinForms app, and using Chilkat BCrypt assembly we are noticing weird effects to the rehashing procedure.
Account class:
Username/Password sent. Checks existing row if user has SHA1, if so we rehash to BCrypt, otherwise we ignore and log them in (hash verification successful).
Now that is all fine, however Chilkat uses "2a" while our classes writes "2y" for the revisions in the final hashes. This prevents logging into both App & Website! Its one or the other due to the rehashing (both bcrypt hashes, never SHA1 found for our test account).
So we learned this was the case by generating hashes using public "generator" sites.
Is there a problem with our code?!
...ANSWER
Answered 2021-Sep-19 at 03:06Went with the VB replace instead. This simply acts as a middle "passover", only it is passing the substituted identifiers. It works as expected, and avoids updating user passwords on the PHP login side.
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