rpub | an ePub generation library in Ruby | Media library
kandi X-RAY | rpub Summary
kandi X-RAY | rpub Summary
Rpub is a command-line tool that generates a collection of plain text input files into an eBook in ePub format. It provides several related functions to make working with ePub files a little easier:.
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Top functions reviewed by kandi - BETA
- Create a new manifest with the given manifest
- Write content to file
- Removes a filename from the file .
- Create an outline of the document
- Creates a new Context instance
- Get the title of the title
- Creates a chapter .
- Create a new zip file .
- Store the filename in the archive .
- Get the content from ERB file
rpub Key Features
rpub Examples and Code Snippets
Community Discussions
Trending Discussions on rpub
QUESTION
I'm trying to apply the solution for having titles in a plotly
subplot
to a plotly
grid
using this Subplots Using Grid example:
ANSWER
Answered 2022-Mar-18 at 10:02You can use this code:
QUESTION
I am using the lme4
package and running a linear mixed model but I am confused but the output and expect that I am encountering an error even though I do not get an error message.
The basic issue is when I fit a model like lmer(Values ~ stimuli + timeperiod + scale(poly(distance.code,3,raw=FALSE))*habitat + wind.speed + (1|location.code), data=df, REML=FALSE)
and then look at the results using something like summary
I see all the model fixed (and random) effects as I would expect however the habitat effect is always displayed as habitatForest. Like this:
ANSWER
Answered 2022-Feb-10 at 19:43note: although your question is about the lmer()
function, this answer also applies to lm()
and other R functions that fit linear models.
The way that coefficient estimates from linear models in R are presented can be confusing. To understand what's going on, you need to understand how R fits linear models when the predictor is a factor variable.
Coefficients on factor variables in R linear modelsBefore we look at factor variables, let's look at the more straightforward situation where the predictor is continuous. In your example dataset, one of the predictors is wind speed (continuous variable). The estimated coefficient is about -0.35. It's easy to interpret this: averaged across the other predictors, for every increase of 1 km/h in wind speed, your response value is predicted to decrease by 0.35.
But what about if the predictor is a factor? A categorical variable cannot increase or decrease by 1. Instead it can take several discrete values. So what the lmer()
or lm()
function does by default is automatically code your factor variable as a set of so-called "dummy variables." Dummy variables are binary (they can take values of 0 or 1). If the factor variable has n
levels, you need n-1
dummy variables to encode it. The reference level or control group acts like an intercept.
In the case of your habitat variable, there are only 2 levels so you have only 1 dummy variable which will be 0 if habitat is not Forest
and 1 if it is Forest
. Now we can interpret the coefficient estimate of -68.8: the average value of your response is expected to be 68.8 less in forest habitat relative to the reference level of grassland habitat. You don't need a second dummy variable for grassland because you only need to estimate the one coefficient to compare the two habitats.
If you had a third habitat, let's say wetland, there would be a second dummy variable that would be 0 if not wetland and 1 if wetland. The coefficient estimate there would be the expected difference between the value of the response variable in wetland habitat compared to grassland habitat. Grassland will be the reference level for all the coefficients.
Default setting of reference levelNow to directly address your question of why habitatForest
is the coefficient name.
Because by default no reference level or control group is specified, the first one in the factor level ordering becomes the reference level to which all other levels are compared. Then the coefficients are named by appending the variable's name to the name of the level being compared to the reference level. Your factor is ordered with grassland first and forest second. So the coefficient is the effect of the habitat being forest habitat, compared to the reference level, which is grassland in this case. If you switched the habitat factor level ordering, Forest
would be the reference level and you would get habitatGrassland
as the coefficient instead. (Note that default factor level ordering is alphabetical, so without specifically ordering the factor levels as you seem to have done, Forest
would be the reference level by default).
Incidentally, the two links you give in your question (guides to mixed models from Phillip Alday and Tufts) do in fact have the same kind of output as you are getting. For example in Alday's tutorial, the factor recipe
has 3 levels: A, B, and C. There are two coefficients in the fixed effects summary, recipeB
and recipeC
, just as you would expect from dummy coding using A as reference level. You may be confusing the fixed effects summary with the ANOVA table presented elsewhere in his post. The ANOVA table does only have a single line for recipe
which gives you the ratio of variance due to recipe
(across all its levels) and the total variance. So that would only be one ratio regardless of how many levels recipe
has.
This is not the place for a full discussion of contrast coding in linear models in R. The dummy coding (which you may also see called one-hot encoding) I described here is just one way to do it. These resources may be helpful:
QUESTION
I am using the following function (based on https://rpubs.com/sprishi/twitterIBM) to extract bigrams from text. However, I want to keep the hash symbol for analysis purposes. The function to clean text works fine, but the unnest tokens function removes special characters. Is there any way to run unnest tokens without removing special characters?
...ANSWER
Answered 2022-Jan-09 at 06:43Here is a solution that involving create a custom n-grams function
SetupQUESTION
I have the following URL which I want to post the form:
...ANSWER
Answered 2021-Nov-13 at 14:16The RSelenium
package enables to remote control the comon web browsers from R
. The following code opens a remote browser session in mozilla firefox
(chrome
should work as well) and works the login screen - with the correct usr and pw the next page will open. As I do not have access to the closed part I can not try nor debug my code after the login screen click so I just showed one upload:
QUESTION
I am learning to work with bnlearn
and I keep running into the following error in the last line of my code below:
Error in custom.fit(dag, cpt) : wrong number of conditional probability distributions
What am I doing wrong?
...ANSWER
Answered 2021-Oct-10 at 19:29You have several errors in your CPT definitions. Primarily, you need to make sure that:
- the number of probabilities supplied are equal to the product of the number of states in the child and parent nodes,
- that the number of dimensions of the matrix/array is equal to the number of parent nodes plus one, for the child node,
- the child node should be given in the first dimension when the node dimension is greater than one.
- the names given in the
dimnames
arguments (e.g. the names indimnames=list(ThisName = ...)
) should match the names that were defined in the DAG, in your case withmodelstring
and in my answer withmodel2network
. (So my earlier suggestion of usingdimnames=list(cptNBLW = ...)
should bedimnames=list(nblw = ...)
to match how nodenblw
was declared in the model string)
You also did not add node f
into your cpt list.
Below is your code with comments where things have been changed. (I have commented out the offending lines and added ones straight after)
QUESTION
I am working with R. I am learning about optimization and trying to follow the instructions from the following references: https://www.rdocumentation.org/packages/pso/versions/1.0.3/topics/psoptim and https://rpubs.com/Argaadya/intro-PSO
For this example, I first generate some random data:
...ANSWER
Answered 2021-Jul-08 at 07:50As pointed out in the comments, if you name arguments, you need to name them according to the function definition. Also, the lower and upper bounds are not expressions, but must be constants (i.e. numbers, not names such as random_1
).
Such constraints could be handled for instance through penalties: in the objective function, compute whether a variable is outside its range; if it is, subtract a penalty from the objective function (if you maximise) or add a penalty (if you minimise).
There are optimisation methods in which you could handle such constraints directly when creating new solutions. One such method is Local Search. Here is a (rough) example, in which I assume that you want to maximise. I use the implementation in package NMOF (which I maintain). The algorithm expects minimisation, but that is no problem: just multiply the objective function value by -1. (Note that many optimisation algorithms expect minimisation models.)
The key ingredient to Local Search is the neighbourhood function. It takes a given solution as input and produces a slightly changed solution (a neighbour solution). Local Search then takes a random walk through the space of possible solutions (with steps as defined in the neighbourhood function), accepting better solutions, but rejecting solutions that lead to worse objective function values.
QUESTION
I am working with R. I am trying to follow this tutorial over here on function optimization: https://rpubs.com/Argaadya/bayesian-optimization
For this example, I first generate some random data:
...ANSWER
Answered 2021-Jul-07 at 23:48There appear to be a few bugs in your code, e.g. I don't think your fitness function was returning data in the required format and some of your vectors were being used before they were defined.
I made some changes so your code was more inline with the tutorial, and it seems to complete without error, but I can't say whether the outcome is "correct" or whether it will be suitable for your use-case:
QUESTION
I'm running a code to format data, which goes into a rake weighting analysis. I started to run the lines but when I get to the parts "tibble::enframe" they don't run. What does tibble do in this code? The strange thing was it did run once upon a time in past but no longer does.
the code
...ANSWER
Answered 2021-Jun-30 at 00:36It appears that you have not loaded the library for select. After adding library(tidyverse)
before your code, it worked on my machine.
QUESTION
I am working with the R programming language. I am trying to recreate the graphs shown in this tutorial over here : https://www.rpubs.com/cboettig/greta-gp
This tutorial shows how to make a special type of regression model for 2 variables. I am able to copy and paste the code from this tutorial and successfully make the desired graphs:
...ANSWER
Answered 2021-Jun-04 at 21:55I think I got the problem. First of all below is the way by which we can reproduce the error & the way you have proceed :
QUESTION
So my end goal is to have a plot with multiple 95% confidence intervals plotted vertically in 2 groups like this example:
I have found this code: https://rpubs.com/nati147/703463
But how can I add groupwise comparison in the plot?
...Write a function ‘CI_95’ that takes input a vector of sample values, and outputs the 95% confidence interval for this sample. You can use the ‘margin_error_95’ function.
ANSWER
Answered 2021-May-17 at 13:59Here is a solution, although it might require some further refinement based on your preferences. I kept the general structure of your plot_CI_95
function, but added a loop over the different groups. This meant that the mu
and sig
variables now must have multiple values, one for each group if you are going to show group-wise differences. There are also some colors and other graphical parameters. The result is shown below.
To avoid the intervals for the two groups overlapping, there are a few parameters to tweak. 1) figure height
in png
(increasing value makes more space between groups, 2) offset
parameter (can increase up to about 0.3), or 3) lwd
in the segments
functions (smaller values mean thinner lines). Using png
or similar function to directly save the figure will allow fine tuning of the desired look.
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