variable | Ruby concurrency variables MVar and IVar | Functional Programming library
kandi X-RAY | variable Summary
kandi X-RAY | variable Summary
Ruby concurrency variables inspired by Haskells IVar and MVar.
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QUESTION
Here's an example of what I mean:
...ANSWER
Answered 2021-Dec-16 at 10:38foo = 5
creates a local variable inside your function. def foo
creates a global variable. That's why they can both have the same name.
If you refer to foo
inside your foo()
function, you're referring to the local variable. If you refer to foo
outside that function, you're referring to the global variable.
Since it evidently causes confusion for people trying to follow the code, you probably shouldn't do this.
QUESTION
I saw a video about speed of loops in python, where it was explained that doing sum(range(N))
is much faster than manually looping through range
and adding the variables together, since the former runs in C due to built-in functions being used, while in the latter the summation is done in (slow) python. I was curious what happens when adding numpy
to the mix. As I expected np.sum(np.arange(N))
is the fastest, but sum(np.arange(N))
and np.sum(range(N))
are even slower than doing the naive for loop.
Why is this?
Here's the script I used to test, some comments about the supposed cause of slowing done where I know (taken mostly from the video) and the results I got on my machine (python 3.10.0, numpy 1.21.2):
updated script:
...ANSWER
Answered 2021-Oct-16 at 17:42From the cpython source code for sum
sum initially seems to attempt a fast path that assumes all inputs are the same type. If that fails it will just iterate:
QUESTION
I use the following method a lot to append a single row to a dataframe. One thing I really like about it is that it allows you to append a simple dict object. For example:
...ANSWER
Answered 2022-Jan-24 at 16:57Create a list with your dictionaries, if they are needed, and then create a new dataframe with df = pd.DataFrame.from_records(your_list)
. List's "append" method are very efficient and won't be ever deprecated. Dataframes on the other hand, frequently have to be recreated and all data copied over on appends, due to their design - that is why they deprecated the method
QUESTION
ANSWER
Answered 2022-Feb-17 at 10:47File->Settings->Tools->Emulator, and uncheck Launch in a tool window Then they will open in their own stand alone windows again.
QUESTION
After coming across something similar in a co-worker's code, I'm having trouble understanding why/how this code executes without compiler warnings or errors.
...ANSWER
Answered 2022-Feb-09 at 07:17References can't bind to objects with different type directly. Given const int& s = u;
, u
is implicitly converted to int
firstly, which is a temporary, a brand-new object and then s
binds to the temporary int
. (Lvalue-references to const
(and rvalue-references) could bind to temporaries.) The lifetime of the temporary is prolonged to the lifetime of s
, i.e. it'll be destroyed when get out of main
.
QUESTION
I'm not experienced so I can't really pinpoint what is the problem. Thanks for the help.
I cloned this repo: https://github.com/flatlogic/react-native-starter.git
And was trying to follow the steps below:
Clone the repogit clone https://github.com/flatlogic/react-native-starter.git
Navigate to clonned folder and Install dependenciescd react-native-starter && yarn install
Install Podscd ios && pod install
When I got to the pod install I'm getting that error.
...ANSWER
Answered 2021-Jul-28 at 18:31I think your pod install
working fine and has done its job. You need to set up iPhone SDK on your mac then try to run cd ../ && react-native run-ios
.
Follow this guide : React Native Environment set up on Mac OS with Xcode and Android Studio
QUESTION
In C++20, we are now able to constrain the auto
keyword to only be of a specific type. So if I had some code that looked like the following without any constraints:
ANSWER
Answered 2021-Nov-01 at 18:38A constraint on the deduced auto
type doesn't mean it needs to be a specific type, it means it needs to be one of a set of types that satisfy the constraint. Note that a constraint and a type are not the same thing, and they're not interchangeable.
e.g. a concept like std::integral constrains the deduced type to be an integral type, such as int
or long
, but not float
, or std::string
.
If I really need a
std::integral
datatype, couldn't I just omit theauto
completely?
In principle, I suppose you could, but this would at the minimum lead to parsing difficulties. e.g. in a declaration like
QUESTION
If one defines a new variable in C++, then the name of the variable can be used in the initialization expression, for example:
...ANSWER
Answered 2021-Oct-06 at 22:12According to the C++17 standard (11.3.6 Default arguments)
9 A default argument is evaluated each time the function is called with no argument for the corresponding parameter. A parameter shall not appear as a potentially-evaluated expression in a default argument. Parameters of a function declared before a default argument are in scope and can hide namespace and class member name
It provides the following example:
QUESTION
Consider the following C++17 code:
...ANSWER
Answered 2021-Oct-03 at 12:09The code shown is valid (all C++ Standard versions, I believe). The similar restrictions are all listed in [reserved.names]. Since read
is not declared in the C++ standard library, nor in the C standard library, nor in older versions of the standard libraries, and is not otherwise listed there, it's fair game as a name in the global namespace.
So is it an implementation defect that it won't link with -static
? (Not a "compiler bug" - the compiler piece of the toolchain is fine, and there's nothing forbidding a warning on valid code.) It does at least work with default settings (though because of how the GNU linker doesn't mind duplicated symbols in an unused object of a dynamic library), and one could argue that's all that's needed for Standard compliance.
We also have at [intro.compliance]/8
A conforming implementation may have extensions (including additional library functions), provided they do not alter the behavior of any well-formed program. Implementations are required to diagnose programs that use such extensions that are ill-formed according to this International Standard. Having done so, however, they can compile and execute such programs.
We can consider POSIX functions such an extension. This is intentionally vague on when or how such extensions are enabled. The g++ driver of the GCC toolset links a number of libraries by default, and we can consider that as adding not only the availability of non-standard #include
headers but also adding additional translation units to the program. In theory, different arguments to the g++ driver might make it work without the underlying link step using libc.so
. But good luck - one could argue it's a problem that there's no simple way to link only names from the C++ and C standard libraries without including other unreserved names.
(Does not altering a well-formed program even mean that an implementation extension can't use non-reserved names for the additional libraries? I hope not, but I could see a strict reading implying that.)
So I haven't claimed a definitive answer to the question, but the practical situation is unlikely to change, and a Standard Defect Report would in my opinion be more nit-picking than a useful clarification.
QUESTION
I'm trying to figure out how alloca()
actually works on a memory level. From the linux man page:
The alloca() function allocates size bytes of space in the stack frame of the caller. This temporary space is automatically freed when the function that called alloca() returns to its caller.
Does this mean alloca()
will forward the stack pointer by n
bytes? Or where exactly is the newly created memory allocated?
And isn't this exactly the same as variable length arrays?
I know the implementation details are probably left to the OS and stuff. But I want to know how in general this is accomplished.
...ANSWER
Answered 2021-Oct-02 at 00:31Yes, alloca
is functionally equivalent to a local variable length array, i.e. this:
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