variable | Ruby concurrency variables MVar and IVar | Functional Programming library

 by   mbj Ruby Version: Current License: MIT

kandi X-RAY | variable Summary

kandi X-RAY | variable Summary

variable is a Ruby library typically used in Programming Style, Functional Programming applications. variable has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Ruby concurrency variables inspired by Haskells IVar and MVar.
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            kandi-support Support

              variable has a low active ecosystem.
              It has 2 star(s) with 0 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              variable has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of variable is current.

            kandi-Quality Quality

              variable has 0 bugs and 0 code smells.

            kandi-Security Security

              variable has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              variable code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              variable is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              variable releases are not available. You will need to build from source code and install.
              It has 940 lines of code, 74 functions and 4 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

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            variable Key Features

            No Key Features are available at this moment for variable.

            variable Examples and Code Snippets

            No Code Snippets are available at this moment for variable.

            Community Discussions

            QUESTION

            Can a function and local variable have the same name?
            Asked 2022-Mar-31 at 08:41

            Here's an example of what I mean:

            ...

            ANSWER

            Answered 2021-Dec-16 at 10:38

            foo = 5 creates a local variable inside your function. def foo creates a global variable. That's why they can both have the same name.

            If you refer to foo inside your foo() function, you're referring to the local variable. If you refer to foo outside that function, you're referring to the global variable.

            Since it evidently causes confusion for people trying to follow the code, you probably shouldn't do this.

            Source https://stackoverflow.com/questions/70377512

            QUESTION

            Why is `np.sum(range(N))` very slow?
            Asked 2022-Mar-29 at 14:31

            I saw a video about speed of loops in python, where it was explained that doing sum(range(N)) is much faster than manually looping through range and adding the variables together, since the former runs in C due to built-in functions being used, while in the latter the summation is done in (slow) python. I was curious what happens when adding numpy to the mix. As I expected np.sum(np.arange(N)) is the fastest, but sum(np.arange(N)) and np.sum(range(N)) are even slower than doing the naive for loop.

            Why is this?

            Here's the script I used to test, some comments about the supposed cause of slowing done where I know (taken mostly from the video) and the results I got on my machine (python 3.10.0, numpy 1.21.2):

            updated script:

            ...

            ANSWER

            Answered 2021-Oct-16 at 17:42

            From the cpython source code for sum sum initially seems to attempt a fast path that assumes all inputs are the same type. If that fails it will just iterate:

            Source https://stackoverflow.com/questions/69584027

            QUESTION

            Good alternative to Pandas .append() method, now that it is being deprecated?
            Asked 2022-Mar-28 at 02:38

            I use the following method a lot to append a single row to a dataframe. One thing I really like about it is that it allows you to append a simple dict object. For example:

            ...

            ANSWER

            Answered 2022-Jan-24 at 16:57

            Create a list with your dictionaries, if they are needed, and then create a new dataframe with df = pd.DataFrame.from_records(your_list). List's "append" method are very efficient and won't be ever deprecated. Dataframes on the other hand, frequently have to be recreated and all data copied over on appends, due to their design - that is why they deprecated the method

            Source https://stackoverflow.com/questions/70837397

            QUESTION

            How to open emulators in different windows at Android Studio (Bumblebee | 2021.1.1)?
            Asked 2022-Feb-22 at 19:06

            I have two running emulators but they open together in different tabs and in one single window.

            How to open them in two different window?

            ...

            ANSWER

            Answered 2022-Feb-17 at 10:47

            File->Settings->Tools->Emulator, and uncheck Launch in a tool window Then they will open in their own stand alone windows again.

            Source https://stackoverflow.com/questions/70923189

            QUESTION

            Is it safe to bind an unsigned int to a signed int reference?
            Asked 2022-Feb-09 at 07:17

            After coming across something similar in a co-worker's code, I'm having trouble understanding why/how this code executes without compiler warnings or errors.

            ...

            ANSWER

            Answered 2022-Feb-09 at 07:17

            References can't bind to objects with different type directly. Given const int& s = u;, u is implicitly converted to int firstly, which is a temporary, a brand-new object and then s binds to the temporary int. (Lvalue-references to const (and rvalue-references) could bind to temporaries.) The lifetime of the temporary is prolonged to the lifetime of s, i.e. it'll be destroyed when get out of main.

            Source https://stackoverflow.com/questions/70712797

            QUESTION

            xcrun: error: SDK "iphoneos" cannot be located
            Asked 2021-Dec-15 at 20:35

            I'm not experienced so I can't really pinpoint what is the problem. Thanks for the help.

            I cloned this repo: https://github.com/flatlogic/react-native-starter.git

            And was trying to follow the steps below:

            Clone the repo

            git clone https://github.com/flatlogic/react-native-starter.git

            Navigate to clonned folder and Install dependencies

            cd react-native-starter && yarn install

            Install Pods

            cd ios && pod install

            When I got to the pod install I'm getting that error.

            ...

            ANSWER

            Answered 2021-Jul-28 at 18:31

            I think your pod install working fine and has done its job. You need to set up iPhone SDK on your mac then try to run cd ../ && react-native run-ios.

            Follow this guide : React Native Environment set up on Mac OS with Xcode and Android Studio

            Source https://stackoverflow.com/questions/68565356

            QUESTION

            Doesn't constraining the "auto" in C++ defeat the purpose of it?
            Asked 2021-Nov-15 at 02:21

            In C++20, we are now able to constrain the auto keyword to only be of a specific type. So if I had some code that looked like the following without any constraints:

            ...

            ANSWER

            Answered 2021-Nov-01 at 18:38

            A constraint on the deduced auto type doesn't mean it needs to be a specific type, it means it needs to be one of a set of types that satisfy the constraint. Note that a constraint and a type are not the same thing, and they're not interchangeable.

            e.g. a concept like std::integral constrains the deduced type to be an integral type, such as int or long, but not float, or std::string.

            If I really need a std::integral datatype, couldn't I just omit the auto completely?

            In principle, I suppose you could, but this would at the minimum lead to parsing difficulties. e.g. in a declaration like

            Source https://stackoverflow.com/questions/69801126

            QUESTION

            Function default argument value depending on argument name in C++
            Asked 2021-Oct-06 at 22:12

            If one defines a new variable in C++, then the name of the variable can be used in the initialization expression, for example:

            ...

            ANSWER

            Answered 2021-Oct-06 at 22:12

            According to the C++17 standard (11.3.6 Default arguments)

            9 A default argument is evaluated each time the function is called with no argument for the corresponding parameter. A parameter shall not appear as a potentially-evaluated expression in a default argument. Parameters of a function declared before a default argument are in scope and can hide namespace and class member name

            It provides the following example:

            Source https://stackoverflow.com/questions/69461415

            QUESTION

            Is it allowed to name a global variable `read` or `malloc` in C++?
            Asked 2021-Oct-04 at 09:43

            Consider the following C++17 code:

            ...

            ANSWER

            Answered 2021-Oct-03 at 12:09

            The code shown is valid (all C++ Standard versions, I believe). The similar restrictions are all listed in [reserved.names]. Since read is not declared in the C++ standard library, nor in the C standard library, nor in older versions of the standard libraries, and is not otherwise listed there, it's fair game as a name in the global namespace.

            So is it an implementation defect that it won't link with -static? (Not a "compiler bug" - the compiler piece of the toolchain is fine, and there's nothing forbidding a warning on valid code.) It does at least work with default settings (though because of how the GNU linker doesn't mind duplicated symbols in an unused object of a dynamic library), and one could argue that's all that's needed for Standard compliance.

            We also have at [intro.compliance]/8

            A conforming implementation may have extensions (including additional library functions), provided they do not alter the behavior of any well-formed program. Implementations are required to diagnose programs that use such extensions that are ill-formed according to this International Standard. Having done so, however, they can compile and execute such programs.

            We can consider POSIX functions such an extension. This is intentionally vague on when or how such extensions are enabled. The g++ driver of the GCC toolset links a number of libraries by default, and we can consider that as adding not only the availability of non-standard #include headers but also adding additional translation units to the program. In theory, different arguments to the g++ driver might make it work without the underlying link step using libc.so. But good luck - one could argue it's a problem that there's no simple way to link only names from the C++ and C standard libraries without including other unreserved names.

            (Does not altering a well-formed program even mean that an implementation extension can't use non-reserved names for the additional libraries? I hope not, but I could see a strict reading implying that.)

            So I haven't claimed a definitive answer to the question, but the practical situation is unlikely to change, and a Standard Defect Report would in my opinion be more nit-picking than a useful clarification.

            Source https://stackoverflow.com/questions/69424363

            QUESTION

            How does alloca() work on a memory level?
            Asked 2021-Oct-03 at 07:41

            I'm trying to figure out how alloca() actually works on a memory level. From the linux man page:

            The alloca() function allocates size bytes of space in the stack frame of the caller. This temporary space is automatically freed when the function that called alloca() returns to its caller.

            Does this mean alloca() will forward the stack pointer by n bytes? Or where exactly is the newly created memory allocated?

            And isn't this exactly the same as variable length arrays?

            I know the implementation details are probably left to the OS and stuff. But I want to know how in general this is accomplished.

            ...

            ANSWER

            Answered 2021-Oct-02 at 00:31

            Yes, alloca is functionally equivalent to a local variable length array, i.e. this:

            Source https://stackoverflow.com/questions/69406966

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install variable

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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