kalk | expression evaluator written in rust that supports variables | Apps library
kandi X-RAY | kalk Summary
kandi X-RAY | kalk Summary
Kalk is a calculator (both program and library) that supports user-defined variables, functions, derivation, and integration. It runs on Windows, macOS, Linux, Android, and in web browsers (with WebAssembly).
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Trending Discussions on kalk
QUESTION
I want to pass all values in a dataframe as condition to dplyr::case_when() with stringr::str_detect() while using the respective column title als replacement value.
I have these two data frames:
...ANSWER
Answered 2021-Nov-25 at 20:38I'm not 100% sure the output you're looking for. However, I believe this is a step in the right direction. Rather than looping over the district values and checking for matches, I propose melting the district_stack
data and joining that new df
to the city names using a fuzzy string match.
That is what I understand is happening in the loop. You then have a dataframe in which you can replace the city
value using if_else
more easily.
I drew inspiration from this thread: dplyr: inner_join with a partial string match
QUESTION
I have a dataframe that I would like to transpose in a certain way, in which the "attr" column values become columns instead of values, while price stays as a column.
I have tried to group the columns and transpose it, but haven't found a way to get where I wanted. This is my dataset:
...ANSWER
Answered 2021-Oct-25 at 08:35# produce data
df = pd.DataFrame(data=[
("Mærke", "Knauf Insulation", 24.95),
("Produkttype", "Bygningsisolering", 24.95),
("Serie", "SPACE", 24.95),
("Mærke", "Bromiflex", 20.00),
("Produkttype", "Rørskål", 20.00),
("Materiale", "Opskummet polyethylen", 20.00),
("Størrelse", "Ø18 MM", 20.00),
],
columns = ("attr", "values", "price")
)
# display data
df.head()
# output
attr values price
0 Mærke Knauf Insulation 24.95
1 Produkttype Bygningsisolering 24.95
2 Serie SPACE 24.95
3 Mærke Bromiflex 20.00
4 Produkttype Rørskål 20.00
# transform data using *pivot* method
df = df.pivot(columns="attr", values="values", index="price").reset_index()
df.columns.name = None
# show results
df.head()
# output
price Materiale Mærke Produkttype Serie Størrelse
0 20.00 Opskummet polyethylen Bromiflex Rørskål NaN Ø18 MM
1 24.95 NaN Knauf Insulation Bygningsisolering SPACE NaN
QUESTION
I need to calculate the "hierarchy" column based on NR and NR_FROM-NR_TO, I'm not sure how to create a CTE/VIEW with such hierarchy column. This is what the result should look like:
...ANSWER
Answered 2020-Sep-17 at 15:34Looks like this solution gives you what you need.
Sample data
QUESTION
Why cant i acsess the dict that i am making here:
...ANSWER
Answered 2020-Aug-24 at 12:00For what you seem to achieve, you need a list
instead of a dict
QUESTION
I am trying to group a List, with inner Lists, to a smaller result using C# lambda but sadly without success.
I got the following query which returns 8 records:
...ANSWER
Answered 2020-Jun-17 at 14:36I usually do it like this
QUESTION
Now I have named every name object in the var but the map still not working.
I want to map custom icons, which are defined in a json data object by the property name. I have multiple Icons. I wrote this code, but it's not working and my console says the error is in line 266,
..."Uncaught TypeError: Cannot read property 'createIcon' of undefined" but I can't figure out the error.
ANSWER
Answered 2020-Apr-06 at 17:22You get this error because in your jsonDataObject
you only have as name Lidl
and not REWE
and Netto Filiale
. Moreover there is not an object for Lidl
in your markerIcons
dictionary. If you include in your markerIcons
an object for Lidl
you should be good and not get the error.
QUESTION
In google data studio I would like to make a REGEXP_EXTRACT
for getting the string after the first |
symbol (https://regex101.com/r/w3BqW4/2). I've tried the regex:
ANSWER
Answered 2020-Mar-02 at 16:36If you want to capture every character after the first vertical bar, that would look like this
\\|(.*)$
You don't need question mark after a .*
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