archon | content addressable image store | Computer Vision library

In simple terms, you can use a small function to do this:

You have to get the text you want to display from somewhere. Storing it in a data-* attribute makes the most sense. Beyond that, you'll set up a click event handler on the parent div of all the images and then just set the text within that callback.

I have stolen an image grid on codepen and added the js for adding the highlight function. I've used the event argument 'e' to access target (element generating the click event) and setting the style directly to it. Probably you can consider a better approach with css classes, at least.

This is happening because "Produced" column contains text instead of numbers.

As text, "10" is ranked lower than "5", because it is ranked by the first symbol ("1" vs "5"). The same is true for "16" vs "9".

To fix it, just convert "Produced" column to numeric type (change field type in Power Query).

This is a sample of one line of the OP's XML file
109555912.69

The OP wants to use the IMPORTXML function to report the ID and Name as well as the Job Cost from the XML data. Presently, the OP's formula is:
=importxml("link","//job-base-cost")

There are two options:
1 - One long column
=importxml("link","//@id | //@name | //job-base-cost")

Note //@id and //@name in the xpath query: // indicate nodes in the document (at any level, not just the root level) and @ indicate attributes. The pipe | operator indicates AND. So the plain english query is to display the id, name and job-base-cost.

2 - Three columns (table format)
={IMPORTXML("link","//@name"),IMPORTXML("link","//job-base-cost"),IMPORTXML("link","//@id")}

This creates a series that will display the fields in each of three columns.

Note: there is an arrayformula that uses a single importXML function described in How do I return multiple columns of data using ImportXML in Google Spreadsheets?. Readers may want to look at whether that option can be implemented.

My thanks to @Tanaike for his comment which spurred me to look at how xpath works.

The problem was where you were trying to set the return of a print to a variable, which you can't do

If you want to specify the routes individualy, you can use named routes, but it is needed to be specified on the method and not on the controller.

In Scala you should always prefer useful types over Any. Do not parse JSON into Map[String, Any] - design case classes around the Api Result data structure and read the JSON into that class:

I think you could do this: