argmin | Mathematical optimization in pure Rust | Computer Vision library
kandi X-RAY | argmin Summary
kandi X-RAY | argmin Summary
argmin is a numerical optimization library written entirely in Rust.
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argmin Key Features
argmin Examples and Code Snippets
def matrix_solve_ls(matrix, rhs, l2_regularizer=0.0, fast=True, name=None):
r"""Solves one or more linear least-squares problems.
`matrix` is a tensor of shape `[..., M, N]` whose inner-most 2 dimensions
form `M`-by-`N` matrices. Rhs is a tens
def _argminmax(fn, a, axis=None):
a = np_array_ops.array(a)
if axis is None:
# When axis is None numpy flattens the array.
a_t = array_ops.reshape(a, [-1])
else:
a_t = np_array_ops.atleast_1d(a)
return fn(input=a_t, axis=axis)
def _convert_argmax_argmin(pfor_input, _, op_func):
t = pfor_input.stacked_input(0)
dimension = pfor_input.unstacked_input(1)
dimension += math_ops.cast(dimension >= 0, dimension.dtype)
output_type = pfor_input.get_attr("output_type")
re
Community Discussions
Trending Discussions on argmin
QUESTION
I want to get the temperature ['thetao']
and salinity ['so']
of the sea surface (just the top layer) for specific geographical location.
I found guidance for how to do this on this website.
...ANSWER
Answered 2022-Mar-22 at 10:50It's because the lats and lons are vectors with different size...
I usually do this if using WGS84 or degrees as unit:
QUESTION
I am training a VQVAE with this dataset (64x64x3). I have downloaded it locally and loaded it with keras in Jupyter notebook. The problem is that when I ran fit()
to train the model I get this error: ValueError: Layer "vq_vae" expects 1 input(s), but it received 2 input tensors. Inputs received: [, ]
. I have taken most of the code from here and adapted it myself. But for some reason I can't make it work for other datasets. You can ignore most of the code here and check it in the page, help is much appreciated.
The code I have so far:
...ANSWER
Answered 2022-Mar-21 at 06:09This kind of model does not work with labels. Try running:
QUESTION
I'm looking to slice out the minimum value along the first axis of an array.
For example, in the code below, I want to print out np.array([13, 0, 12, 3])
.
However, the slicing isn't behaving as I would think it does.
(I do need the argmin array later and don't want to just use np.min(g, axis=1)
)
ANSWER
Answered 2022-Mar-18 at 17:56Your code is printing the first, third, second, and third columns of the g
array, in that order.
QUESTION
I am trying to build a histogram of my dataset online while the samples "x" are being generated so that I can use this histogram to stir the direction of the distribution of samples "y". Here is a toy example which is not really working:
...ANSWER
Answered 2022-Mar-09 at 09:32If hs
should be part of your dataset, your code is working fine:
QUESTION
I use the following code to plot a scatter plot. I have been trying to plot the lower boundary for it. I tried following the other question but I was unable to replicate it for my objective function and data. The code is as follows :
...ANSWER
Answered 2022-Mar-08 at 19:43As you have a linear function, your upper and lower bound will have the same slope a
but different b
-values. So, we calculate them for all points and choose the lowest and highest:
QUESTION
I have to compute the Aroon indicator on data stored in a dataframe:
...ANSWER
Answered 2022-Mar-06 at 22:19You can use sliding_window_view
as replacement of rolling
:
QUESTION
Let us have a numpy array (float) with shape equal to (36, 2, 400, 400). Let us say the 400 by 400 represents an image. Then for each pixel I would like to find the two values (second dimension) which are when taking the norm over the second dimension, the lowest with respect to the first dimension. So I end up with an array of shape (2, 400, 400).
With np.argmin(np.linalg.norm(array, axis=1), axis=0)
I am able to get the index for each of those 2 by 400 by 400 pixels which is almost what I want. But now I want to use this number to slice the original array in the first dimension so I am left with an array of shape (2, 400, 400).
What I can do is loop over all indices and construct the result pixel by pixel, but I am convinced there is a smarter way. Can anyone help me with a smarter way?
A minimal reproducible example as requested where distances is the array:
...ANSWER
Answered 2022-Jan-19 at 09:22The function I was looking for is numpy.take_along_axis().
For the specific example the only thing needed to be done is making sure the nearest_center_index
(output of argmin
) has equal amount of dimensions as the to be sliced array. In the example this can be achieved by passing keepdims=True
to both norm
and argmin
which then can be directly used as the second argument of the numpy function. The third argument should be the xi
axis (in the example axis 0).
Without passing the keepdims=True
, following the exact example, the stated objective can be achieved by:
QUESTION
Given the following matrix:
...ANSWER
Answered 2022-Mar-01 at 10:57Fill the NaNs with infinity using numpy.nan_to_num
, then get the argmin
:
QUESTION
I was using pyspark on AWS EMR (4 r5.xlarge as 4 workers, each has one executor and 4 cores), and I got AttributeError: Can't get attribute 'new_block' on . Below is a snippet of the code that threw this error:
...
ANSWER
Answered 2021-Aug-26 at 14:53I had the same error using pandas 1.3.2 in the server while 1.2 in my client. Downgrading pandas to 1.2 solved the problem.
QUESTION
The present code selects minimum values by scanning the adjoining elements in the same and the succeeding row. However, I want the code to select all the values if they are less than the threshold value. For example, in row 2, I want the code to pick both 0.86 and 0.88 since both are less than 0.9, and not merely minimum amongst 0.86,0.88. Basically, the code should pick up the minimum value if all the adjoining elements are greater than the threshold. If that's not the case, it should pick all the values less than the threshold.
...ANSWER
Answered 2022-Feb-15 at 20:17Try this:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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No vulnerabilities reported
Install argmin
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.
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