linked-list | An alternative implementation of std collections | File Utils library
kandi X-RAY | linked-list Summary
kandi X-RAY | linked-list Summary
An alternative implementation of std::collections::LinkedList featuring a prototype Cursor. Documentation is available at
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QUESTION
I am writing code to answer the following LeetCode question:
Given the head of a linked list and an integer
Example 1 ...val
, remove all the nodes of the linked list that hasNode.val == val
, and return the new head
ANSWER
Answered 2021-Jun-15 at 10:52Some issues in your code (as it was first posted):
return skipper(prev,curr)
is going to exit the loop, but there might be more nodes to be removed further down the list.skipper
only takes care of a sub sequence consisting of the same value, but it will not look beyond that. The list is not necessarily sorted, so the occurrences of the value are not necessarily grouped together.Be aware that the variable
prev
inskipper
is not the same variable as the other, outerprev
. So the assignmentprev=curr
inskipper
is quite uselessUnless the list starts with the searched value,
dummy.next
will always remainNone
, which is what the function returns. You should initialisedummy
so it links tohead
as its next node. In your updated code you took care of this, but it is done in an obscure way (in theelse
part).dummy
should just be initialised as the head of the whole list, so it is like any other node.
In your updated code, there some other problems as well:
while prev.next:
risks to be an infinite loop, because it continues whileprev
is not the very last node, but it also doesn't move forward in that list if its value is not equal to the searched value.
I would suggest doing this without the skipper
function. Your main loop can just deal with the cases where current.val == val
, one by one.
Here is the corrected code:
QUESTION
I am working in an environment where I cannot use heap memory but only stack memory. To not be constrained by the #[no_std]
enviroment I tried to use stack memory as heap memory with the linked-list-allocator crate. This was my approach.
ANSWER
Answered 2021-Apr-02 at 10:11After looking into the code and finding what looks a lot like the default entry point I'll put what I think is the confirmation of my guess as an answer: the global_allocator
must be fully initialised before main
, because the default entry point relies on it and allocates: https://github.com/rust-lang/rust/blob/master/library/std/src/rt.rs#L40-L45
QUESTION
How can I call in batch a multiple level of array ?
I want to create an array of unique value with multiples data, then I will manage to make an associative array after unyfing the values.
I have a csv file with lot of value like this :
...ANSWER
Answered 2021-May-21 at 08:21when a variable that requires delayed expansion to access is composed of additional delayed variables, an additional for loop can be used to access sub variables:
QUESTION
when I'm solving the problem Intersection of Two Linked Lists from Leetcode, I found that the HashSet solution doesn't work on my computer. The return result is always null, but it works well on Leetcode.
...ANSWER
Answered 2021-May-18 at 11:53The problem is not from HashSet on your Computer but it's from the input examples, make sure that you used the same ListNode Instances for the Intersection part on the 2 LinkedList for example
QUESTION
What does the --contains
option do in git for-each-ref
?
Does it only return a reference if its revlist has the commit specified after the --contains
option on the command line? (e.g. Does git for-each-ref refs/heads --contains feature/test
only return those heads that contain the commit feature/test
in their revlist? (i.e. the list of commits between them and the first commit, namely git rev-list
))?
The Git docs (v. 2.31.1; see here) are actually outdated: the Notes
section at the bottom states you can use the --merged
and --no-merged
options together, but this was made incompatible with this commit.
The definition provided in the docs is ambiguous: it reuses the word "contains" without clarifying what is meant by that. A reference is a name that points to only one SHA. The idea of "contains" suggests a reference refers to multiple commits, which only makes sense in the context of its git rev-list
.
A commit can come after or before another (simply by time of commit), but if it is not reachable from that commit (i.e. if the commit is not merged into its branch), then the commit has no knowledge of it, so it can't be said to "contain" it.
This is why --merged
and --no-merged
together made sense: it would return the commits reachable from (at least one of) --merged
and none of --no-merged
.
What is meant by "contains"?..."has immediate parent X"? "has ancestor X"? "has cousin X"?
UPDATE:
It does seem I was using an older version of Git. Using both --merged
and --no-merged
together was incompatible in v2.28.1, but is now compatible in v2.31.1. Hence, the Git docs are not outdated.
It also seems this commit was made on Mar 21, 2017, so well before v2.31.1 (not sure which version exactly it was committed with).
Second, it does seem @LeGEC's answer makes sense (vis-a-vis --contains
/--no-contains
means "give me refs that have this commit after them" and --merged
/--no-merged
means "give me refs that have this commit before them".
Still, it would be nice if the Git documentation could be given further clarified. Using the word in the definition as they've done is very vague.
Because Git is a Directed Acyclic Graph (DAG), commits point to other commits in linked-list-fashion in one direction: backwards in time towards their ancestors. Hence, the names --merged
/--no-merged
and their description in terms of "reachability" make sense.
Does "contains" mean "after and reachable" (i.e. children), or simply "after" (i.e. commits made later in time)?
Since this is a plumbing command (which are used in custom scripts), I need to know exactly what it does and how it works so that my scripts won't have any unexpected side effects.
...ANSWER
Answered 2021-May-12 at 07:21Perhaps I misunderstood your question, please update your question if relevant.
The documentation gives a correct (but perhaps succinct ?) description of these options,
here is one way to word it differently :
--merged develop
means "comes beforedevelop
"--no-merged master
means "doesn't come beforemaster
"--contains feature1
means "comes afterfeature1
"--no-contains feature2
means "doesn't come afterfeature2
"
These 4 options are actually compatible :
QUESTION
I'm supposed to write a function that scan input from user till enter and enter it to linked list. I cant scan it into a String and than put it in a list.
I wrote this code and doesn't enter the chars to linked list and doesn't exit from the console till I press Exit.
...ANSWER
Answered 2021-May-11 at 08:50For this call of scanf
QUESTION
I get error ":( program is free of memory errors valgrind tests failed; see log for more information."
Here is my code:
...ANSWER
Answered 2021-May-11 at 16:48This is wrong
QUESTION
I'm supposed to write a function called - "disAssemblyList" that gets a linked list of chars(without a dummy element). The function should move a nodes with big letters to "bigLetter" linked list (without a dummy element) , move nodes with small letters to "smallLetter" linked list, nums to "nums" linked list and other chars keep into original list.
I need to pass by reference the smallLetter, bigLetter and nums linked lists and return the list with other chars.
I need to scan the original list. The original list can be empty.
for example:
An original linked list:
...ANSWER
Answered 2021-May-10 at 15:30I have not looked through all your code because as I have understood the question is about one function implementation that splits an original list to some other lists.
Though I am sure that there are drawbacks in your code as for example the function print_CharList
outputs internal codes of characters instead of characters stored in a list themselves.
QUESTION
I've got this question where I'm supposed to write a function called - "createList" that gets a linked list(without a dummy element) of ints. The function should remove every element that is bigger than the previous one and the next one. Also, I have to make a new linked list (without a dummy element) where I place all the removed elements from the original linked list. (The elements should stay in the same order that they appeared in the original linked list). (createlist is createListEx4() in my code)
For instance, an original linked list : 3->6->1->9->8->4->5;
would be updated to : 3->1->8->4;
The "removed elements" linked list would be: 6->9->5;
The function will return a pointer to the "removed elements" linked list
I wrote this code and I cant seem to understand how to make it work. There is a memory leak while I print the "removed elements" linked list, and doesn't return the correct elements.
...ANSWER
Answered 2021-May-06 at 16:46Your code is much more complicated than need and also contains a number of logical errors.
For instance, you shouldn't use malloc
and free
when moving node from one list to the other. Just change pointers.
And this part from the start of createListEx4
QUESTION
I found the function below that reverses a linked list recursively:
...ANSWER
Answered 2021-May-05 at 11:45Actually, I don't understand that function. First, you should only need to be passing to such a function the head of the list; I don't know why argument end is being passed or why it even needs to be passed. Also, argument self suggests that this is a method that is part of a class definition that is not being shown. Let's start anew:
Here is a simple class for defining a node that can be linked to another node and be tagged with a "name" for identification. We also include a small function to walk the linked list to print out the nodes:
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