leaf | efficient proxy framework with nice features | Proxy library

 by   eycorsican Rust Version: v0.9.1 License: Apache-2.0

kandi X-RAY | leaf Summary

kandi X-RAY | leaf Summary

leaf is a Rust library typically used in Networking, Proxy, Framework applications. leaf has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

A versatile and efficient proxy framework with nice features suitable for various use cases.
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              leaf has a medium active ecosystem.
              It has 1921 star(s) with 371 fork(s). There are 54 watchers for this library.
              There were 2 major release(s) in the last 12 months.
              There are 85 open issues and 159 have been closed. On average issues are closed in 30 days. There are 6 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of leaf is v0.9.1

            kandi-Quality Quality

              leaf has no bugs reported.

            kandi-Security Security

              leaf has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              leaf is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              leaf releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of leaf
            Get all kandi verified functions for this library.

            leaf Key Features

            No Key Features are available at this moment for leaf.

            leaf Examples and Code Snippets

            copy iconCopy
            const HSLToRGB = (h, s, l) => {
              s /= 100;
              l /= 100;
              const k = n => (n + h / 30) % 12;
              const a = s * Math.min(l, 1 - l);
              const f = n =>
                l - a * Math.max(-1, Math.min(k(n) - 3, Math.min(9 - k(n), 1)));
              return [255 * f(0), 255 *  
            copy iconCopy
            from datetime import timedelta, date
            
            def daterange(start, end):
              return [start + timedelta(n) for n in range(int((end - start).days))]
            
            
            from datetime import date
            
            daterange(date(2020, 10, 1), date(2020, 10, 5))
            # [date(2020, 10, 1), date(2020, 10,  
            Returns the leaf at v .
            pythondot img3Lines of Code : 35dot img3License : Permissive (MIT License)
            copy iconCopy
            def get_leaf(self, v):
                    """
                    Tree structure and array storage:
                    Tree index:
                         0         -> storing priority sum
                        / \
                      1     2
                     / \   / \
                    3   4 5   6    -> storing priority for   
            Recursively prints a subtree to a leaf path .
            javadot img4Lines of Code : 20dot img4License : Non-SPDX (GNU General Public License v3.0)
            copy iconCopy
            public void rootToLeafPaths(BinaryNode node, E[] pathList, int pathLength) {
                    if (node == null) return;
            
                    pathList[pathLength] = node.value;
                    pathLength++;
            
                    // if its a leaf node then print the list
                    if (node.left   
            Return a list of leaf level keys from a CrossedColumn .
            pythondot img5Lines of Code : 16dot img5License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def _collect_leaf_level_keys(cross):
              """Collects base keys by expanding all nested crosses.
            
              Args:
                cross: A `CrossedColumn`.
            
              Returns:
                A list of strings or `CategoricalColumn` instances.
              """
              leaf_level_keys = []
              for k in cross.key  

            Community Discussions

            QUESTION

            Find Rows with no leaf - Oracle
            Asked 2021-Jun-14 at 18:01

            I have data in below format in a table .

            NAME PATH A ABC A ABC:A C XYZ:C E XYZ:C:D F XYZ:C:D

            I am trying to get the output of only records which are leaf nodes, so basically I am looking to get output like

            NAME PATH A ABC:A E XYZ:C:D F XYZ:C:D

            I tried doing nested substring on the PATH column but it giving me all rows.

            My Trail :--

            ...

            ANSWER

            Answered 2021-Jun-14 at 18:01

            Since you have the paths, you can use NOT EXISTS and a correlated subquery using LIKE.

            Source https://stackoverflow.com/questions/67974751

            QUESTION

            How to time complexity of recursive function?
            Asked 2021-Jun-14 at 10:35

            Problem Statement: Given a binary tree and a number ‘sum’, find all paths from root-to-leaf such that the sum of all the node values of each path equals ‘sum’.

            How do I calculate the time complexity of this algorithm?

            What is its recurrence relation?

            ...

            ANSWER

            Answered 2021-Jun-11 at 18:12

            This is O(N). There's no looping, and you'll visit each node exactly once.

            Source https://stackoverflow.com/questions/67941727

            QUESTION

            How to push a document in an array nested in another array?
            Asked 2021-Jun-14 at 09:31

            This is my problem : I have a document ( let's call it root) containing an array of another documents (stick), that contain another array of another documents (leaf).

            Or simply said : root{ stickChain[leaveschain1[ leaf1, leaf2],leaveschain2[ leaf1, leaf2] ]}

            I have access to root _id, stick _id, or whatever it is needed to identify each document.

            Basically, the best result I've come so far is, when creating my leaves documents, is to store then at the same level tha sticks, or in another word I've come to create an array of leaves in root.

            I'm working in javascript and using mongoose

            This is the line I've used:

            ...

            ANSWER

            Answered 2021-Jun-14 at 09:31

            I've splitted my dument like this :

            • root[stickChain _id]
            • stick[leavesChain[leaf]]

            Thanks to Andrey Popov for his explications

            Source https://stackoverflow.com/questions/67917435

            QUESTION

            How do you set up MTI in Rails with a polymorphic belongs_to association?
            Asked 2021-Jun-12 at 04:58

            In an effort to create a Short, Self Contained, Correct (Compilable), Example, imagine that I want to do the following.

            I have a blog website. There are two types of posts, TextPost and LinkPost. There are also two types of users, User and Guest. I would like to implement Multiple Table Inheritance with TextPost and LinkPost, by which I mean (hopefully I'm using the term correctly):

            • At the model level, I will have Post, TextPost and LinkPost. TextPost and LinkPost will inherit from Post.
            • At the database level, I will have tables for the "leaf" models of TextPost and LinkPost, but not for Post.

            Each type of Post can belong to either a User or a Guest. So we have a polymorphic belongs_to situation.

            My question is how to accomplish these goals.

            I tried the following, but it doesn't work.

            ...

            ANSWER

            Answered 2021-Jun-12 at 04:58
            1. The names of constants look like the names of local variables, except that they begin with a capital letter.

            2. All the built-in classes, along with the classes you define, have a corresponding global constant with the same name as the class called class name.

            So in your case, when you define User class, there's a constant class name: User, but not user, that why the error NameError (wrong constant name user) is raised.

            try text_post = TextPost.create(title: 'foo', content: 'lorem ipsum', author_id: 1, author_type: 'User')

            Source https://stackoverflow.com/questions/67944435

            QUESTION

            Delete leaf nodes between a range in BST
            Asked 2021-Jun-10 at 13:37

            I want to delete the leaf nodes, the values of which are outside a given range (say [L R]). I made a solution in which I was simply traversing all the nodes and checking if my current leaf node's value is in the given range or not. If it is not then I'm removing this node.

            My approach -

            ...

            ANSWER

            Answered 2021-Jun-10 at 13:37

            Like m.raynal said, since you only want to remove leafs you can't get better than O(n).

            You only can add a shortcut when all the nodes in the branch will be inside the range, something like

            Source https://stackoverflow.com/questions/67920474

            QUESTION

            Scheme equal-tree procedure
            Asked 2021-Jun-10 at 08:33

            Given a new implementation of tree in Scheme using list:

            ...

            ANSWER

            Answered 2021-Jun-09 at 23:06

            You have a reasonable-looking sequence of if tests (though using cond instead would be more idiomatic Scheme). But the values you return do not generally look correct.

            The first problem I see is in your first if clause. If both trees are empty, you return '(). But according to the spec, you should be calling the succ function with that result. This may look unimportant if you use id as your continuation, but note that each recursive step builds up a more detailed succ continuation, so in general succ may be a quite impactful function.

            The second if is also a problem. Again you return '(), when you are supposed to return the first conflicting subtrees. It's not clear to me what that means, but it would be reasonable to pass a pair of tree1 and tree2 to fail.

            The third and fourth clause look fine. You call succ with a pair of the two leaves, as expected.

            The recursive call is clearly wrong: you have mis-parenthesized calls to cons, and your lambda variable is named X but you refer to it as x. The series of cons calls doesn't really look right either, but you can experiment with that once your more pressing syntactic issues are resolved and your base cases work properly.

            Lastly, you are doing a lot of low-level work with cons, car, '(), and so on. You should be using the abstract functions provided to you, such as add-subtree and (make-tree), instead of using the low-level primitives they are built on.

            Source https://stackoverflow.com/questions/67905688

            QUESTION

            How is the value returned from the function SumOfLongRootToLeafPath
            Asked 2021-Jun-09 at 23:20

            I was solving some problems on Binary tree and I got stuck in this question https://www.geeksforgeeks.org/sum-nodes-longest-path-root-leaf-node/ I am using python to solve the question I understood the logic of the solution given on the link but my question is how did the value of maxSum change in the SumOfLongRootToLeafPathUtil(root) function when nothing is returned from SumOfLongRootToLeafPath() function how is the original value of the varaible change please help ps:Please refer to the python code given in the link

            ...

            ANSWER

            Answered 2021-Jun-09 at 23:20

            The maxSum list object passed into the SumOfLongRootToLeafPath function is mutable. So, when it is changed within that function, the SumOfLongRootToLeafPathUtil function will see the changes to it. So, there is no need to return a value.

            e.g. showing mutable nature of a list

            Source https://stackoverflow.com/questions/67911298

            QUESTION

            Change variable value on button click in HTML
            Asked 2021-Jun-07 at 23:34

            below I have posted the code for my drop-down menu. At the very end, there is a variable called variableToChange="".

            Probably it is an easy question for the more experienced ones but I want every time I press some button to change the value of the variable. Let's say it should take the text of the button as a new value.

            I guess it should be implemented somewhere into the on click part but I lack the experience here so I can't really implement it. I would really appreciate some help.

            Update: Expected scenario would be: when I press the button called AA the value of variableToChange should be changed to "AA". Similarly, if I press afterwards BC it should be changed again to "BC".

            ...

            ANSWER

            Answered 2021-Jun-07 at 23:27

            QUESTION

            Most effective way to fold polynomial parse tree
            Asked 2021-Jun-07 at 19:34

            I am working on a symbolic algebra system. I'm currently looking at how to carry out polynomial addition/multiplication from a binary parse tree. I will later consider this to be a general ring.

            Parsing is not relevant here -- this intended to be the output of parsing. The parse tree that is formed. If something could be improved here, I'm certainly happy to learn about that too.

            I 'feel' that this tree structure could be folded/crushed, yet I'm not too clear on how to go about it. I believe I can hack something together, but as I'm still learning Haskell, I wanted to learn what the more advanced users would do.

            Below is relevant code background.

            My two relevant data declarations are:

            ...

            ANSWER

            Answered 2021-May-03 at 15:35

            "Fold" has two related but distinct meanings in common parlance.

            1. Fold as in Foldable. Viewing the datatype as a container, Foldable gives you access to the container's elements while throwing away any information about the shape of the container itself. (This is also the sense in which lens's Fold uses the term.) Not every datatype is Foldable — only those which can be viewed as a container.
            2. "Fold" can also mean "catamorphism", which is a technique for writing higher-order functions which reduce a structure to a summary value. Every datatype has a corresponding catamorphism, but the signature of the catamorphism depends on the datatype.

            The two meanings of "fold" happen to coincide when the datatype you're talking about is [] (which partly explains the confusion over the two meanings), but in general they don't. Your Tree happens to be a suitable candidate for either type of fold, and from your question I can't quite tell which one you're after, so I'll show you how to do both.

            The easiest way to write an instance of Foldable is to turn on DeriveFoldable.

            Source https://stackoverflow.com/questions/67368081

            QUESTION

            Regex formula to pick up number score from tweet which could occur with "." before "/" sign and after that sign
            Asked 2021-Jun-07 at 14:43

            I struggle to get the first part of number score occuring before "/" sign in every tweet as below. The problem is that sometimes the score contains decimal like "13.5" or there might be a date written as 9/11 which I do not need.So at the end I need two columns: first with extraction of first part (numerator) of score before "/" sign and in second column to have a denominator occuring after "/" sign, normally it should be always 10. There might be some digits inside the link at the end as well which I do not want to have.

            In the first new column I want to get the bolded part only and in second column to catch "/10" part:

            This is Bella. She hopes her smile made you smile. If not, she is also offering you her favorite monkey. 13.5/10 https://twitter.com/dog_rates/status/883482846933004288

            RT @dog_rates: After so many requests, this is Bretagne. She was the last surviving 9/11 search dog, and our second ever 14/10. RIP https://twitter.com/dog_rates/status/786709082849828864

            Here we have a 1949 1st generation vulpix. Enjoys sweat tea and Fox News. Cannot be phased. 5/10 https://twitter.com/dog_rates/status/786709082849828864

            This is a western brown Mitsubishi terrier. Upset about leaf. Actually 2 dogs here. 7/10 would walk the shit out of https://twitter.com/dog_rates/status/786709082849828864

            I tried to do it as below:

            ...

            ANSWER

            Answered 2021-Jun-02 at 12:28

            You can match and capture both values that are followed with any amount of non-digit chars until the http string:

            Source https://stackoverflow.com/questions/67805049

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install leaf

            More configuration examples can be found here.
            Install GCC or Clang.

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