dog | A command-line DNS client | DNS library
kandi X-RAY | dog Summary
kandi X-RAY | dog Summary
dog is a command-line DNS client.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of dog
dog Key Features
dog Examples and Code Snippets
Lines of Code : 7
License : No License
Copyconst listenOnce = (el, evt, fn) =>
el.addEventListener(evt, fn, { once: true });
listenOnce(
document.getElementById('my-id'),
'click',
() => console.log('Hello world')
); // 'Hello world' will only be logged on the first click
def initialize_list_with_values(n, val = 0):
return [val for x in range(n)]
initialize_list_with_values(5, 2) # [2, 2, 2, 2, 2]
@Override
public String name() {
return "Dog";
} @Bean
Dog dog() {
return new Dog();
} @Override
public String getType() {
return "Dog";
} Community Discussions
Trending Discussions on dog
QUESTION
How can I escape metacharacters in a Raku regex the way I would with Perl's quotemeta function (\Q..\E)?
That is, the Perl code
...ANSWER
Answered 2022-Feb-10 at 00:03You can treat characters in a Raku regex literally by surrounding them with quotes (e.g., '.*?') or by using using regular variable interpolation (e.g., $substring inside the regex where $substring is a string contaning metacharacters).
Thus, to translate the Perl program with \Q...\E from your question into Raku, you could write:
QUESTION
Given a list of Strings:
...ANSWER
Answered 2022-Mar-22 at 07:13This problem should be solved easily using a trie.
The trie node should basically keep a track of 2 things:
- Child nodes
- Count of prefixes ending at current node
Insert all strings in the trie, which will be done in O(string length * number of strings). After that, simply traversing the trie, you can hash the prefixes based on the count as per your use case. For suffixes, you can use the same approach, just start traversing the strings in reverse order.
Edit:
On second thought, trie might be the most efficient way, but a simple hashmap implementation should also work here. Here's an example to generate all prefixes with count > 1.
QUESTION
In scala, functions are covariant in their output type, and contravariant in their input type.
For example, if Dog is a subtype of Animal, then
T => Dog is a subtype of T => Animal, and
Animal => T is a subtype of Dog => T
In other words, a producer of Dog can go where a producer of Animal is expected, and
a consumer of Animal can go where a consumer of Dog is expected.
So why do I get this compile error:
...ANSWER
Answered 2022-Mar-11 at 00:37Your logic is correct. Just syntax is wrong.
() => T is not Function1[Unit, T]. It is actually a syntax for lambda with no argument which results in Function0[T]. The parenthesis here is not Unit. It's a syntax to denote zero arguments
The correct way to construct a Unit => Unit is:
QUESTION
I'm experimenting with Chaum's blind signature, and what I'm trying to do is have the blinding and un-blinding done in JavaScript, and signing and verifying in Java (with bouncy castle). For the Java side, my source is this, and for JavaScript, I found blind-signatures. I've created two small codes to play with, for the Java side:
...ANSWER
Answered 2021-Dec-13 at 14:56The blind-signature library used in the NodeJS code for blind signing implements the process described here:
BlindSignature.blind()generates the SHA256 hash of the message and determines the blind message m' = m * re mod N.BlindSignature.sign()calculates the blind signature s' = (m')d mod N.BlindSignature.unblind()determines the unblind signature s = s' * r-1 mod N.BlindSignature.verify()decrypts the unblind signature (se) and compares the result with the hashed message. If both are the same, the verification is successful.
No padding takes place in this process.
In the Java code, the implementation of signing the blind message in signConcealedMessage() is functionally identical to BlindSignature.sign().
In contrast, the verification in the Java code is incompatible with the above process because the Java code uses PSS as padding during verification.
A compatible Java code would be for instance:
QUESTION
I have two data frames that look like this:
...ANSWER
Answered 2021-Dec-29 at 20:16It may be faster with a join
QUESTION
I have a nested list of lists which contains some data frames. However, the data frames can appear at any level in the list. What I want to end up with is a flat list, i.e. just one level, where each element is only the data frames, with all other things discarded.
I have come up with a solution for this, but it looks very clunky and I am sure there ought to be a more elegant solution.
Importantly, I'm looking for something in base R, that can extract data frames at any level inside the nested list. I have tried unlist() and dabbled with rapply() but somehow not found a satisfying solution.
Example code follows: an example list, what I am actually trying to achieve, and my own solution which I am not very happy with. Thanks for any help!
...ANSWER
Answered 2021-Dec-28 at 22:13Maybe consider a simple recursive function like this
QUESTION
I am looking for an easy, concise way to use dplyr::select without rearranging columns.
Consider this dataset:
...ANSWER
Answered 2021-Dec-22 at 21:28We could use match with sort
QUESTION
I've this situation:
...ANSWER
Answered 2021-Dec-26 at 20:48We may use read.dcf from base R
QUESTION
I'm trying to understand polymorphism in haskell. Given the typical example below
...ANSWER
Answered 2021-Nov-14 at 04:48This is a very common mistake: overlooking the direction of the polymorphism.
In short: it's the caller of the function that gets to choose type parameters, not the implementer of the function.
Slightly longer: when you give your function a signature like Animal a => a, you're making a promise to any caller of your function, and that promise reads something like this: "Pick a type. Any type. Whatever type you want. Let's call it a. Now make sure there is an instance Animal a. Now I can return you a value of type a"
So you see, when you write such function, you don't get to return a specific type that you choose. You have to return whatever type the caller of your function will choose later when they call it.
To drive it home with a specific example, imagine that your getA' function is possible, and then consider this code:
QUESTION
Premise: Suppose you have a table containing words, where some may be distinct and some "may overlap", meaning a longer word starts with a shorter one, eg:
...ANSWER
Answered 2021-Nov-02 at 13:42Something like
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