fend | Arbitrary-precision unit-aware calculator | Apps library

by printfn Rust Version: v1.2.0 License: MIT

X-Ray Key Features Code Snippets(2)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | fend Summary

fend is a Rust library typically used in Apps applications. fend has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

fend is an arbitrary-precision unit-aware calculator. See the manual for more information. fend is available on the web at printfn.github.io/fend-website.

Support

Quality

Security

License

Reuse

Support

fend has a low active ecosystem.

It has 245 star(s) with 23 fork(s). There are 5 watchers for this library.

There were 1 major release(s) in the last 12 months.

There are 27 open issues and 66 have been closed. On average issues are closed in 34 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of fend is v1.2.0

Quality

fend has no bugs reported.

Security

fend has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

fend is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

fend releases are available to install and integrate.

Installation instructions, examples and code snippets are available.

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fend Key Features

No Key Features are available at this moment for fend.

fend Examples and Code Snippets

fend,Examples

Rust

Lines of Code : 20

License : Permissive (MIT)

Copy

> 5'10" to cm
177.8 cm

> cos (pi/4) + i * (sin (pi/4))
approx. 0.7071067811 + 0.7071067811i

> 0b1001 + 3
0b1100

> 0xffff to decimal
65535

> 100 °C to °F
210 °F

> 1 lightyear to parsecs
approx. 0.3066013937 parsecs

> tempera

fend,Installation

Rust

Lines of Code : 9

License : Permissive (MIT)

Copy

brew install printfn/fend/fend

yay -Syu aur/fend

nix-env -iA nixpkgs.fend

rustup update
cargo install fend

$ fend
> 1 ft to cm
30.48 cm
>

Community Discussions

Trending Discussions on fend

How to handle graceful failure in Dask?

Spacy Regex Phrase Matcher in Python

How to define a controller method as to accept a JSON that have a media type filed with Spring Boot?

Calculate the days between dates from a grouped data.frame R dplyr

Button (GPIO) Pressing Logic in MicroPython

Two-Button Menu Iteration

Error! cannot create the database connection. / OS X / sqlite3 / python3

Would like to split columns with a variable and not have to use cases

Is it possible to calculate function length at compile time in C++?

Constant Throughput Timer generates too much requests

QUESTION

How to handle graceful failure in Dask?

Asked 2021-Jun-13 at 13:13

I'm running a hour long computation that fetches an external API, process it and save to a dataframe. The API is using Python's request library.

By tweaking the request lib, I managed to fend off problems related to retries and reading errors, but not all possible problems are handled, of course.

Everytime the API fails, my computation just stops, and I lose one hour worth of work.

I'm calling dask like this:

...

ANSWER

Answered 2021-Jun-13 at 13:13

By running .compute on the dask dataframe you are converting it into a pandas dataframe in memory. If you want a future object, then you can run:

Source https://stackoverflow.com/questions/67957646

QUESTION

Spacy Regex Phrase Matcher in Python

Asked 2021-May-29 at 08:53

In a large corpus of text, I am interested in extracting every sentence which has a specific list of (Verb-Noun) or (Adjective-Noun) somewhere in the sentence. I have a long list but here is a sample. In my MWE I am trying to extract sentences with "write/wrote/writing/writes" and "book/s". I have around 30 such pairs of words.

Here is what I have tried but it's not catching most of the sentences:

...

ANSWER

Answered 2021-May-29 at 08:53

The issue is that in the Matcher, by default each dictionary in the pattern corresponds to exactly one token. So your regex doesn't match any number of characters, it matches any one token, which isn't what you want.

To get what you want, you can use the OP value to specify that you want to match any number of tokens. See the operators or quantifiers section in the docs.

However, given your problem, you probably want to actually use the Dependency Matcher instead, so I rewrote your code to use that as well. Try this:

Source https://stackoverflow.com/questions/67748845

QUESTION

How to define a controller method as to accept a JSON that have a media type filed with Spring Boot?

Asked 2021-May-14 at 20:24

I'm trying to take a Json object from front-end. This represent a course. The course have a field logo, the image of the course. In my Controller I have the following method:

...

ANSWER

Answered 2021-May-14 at 20:24

For me how I did something similar was like so: In the back end (Spring):

Source https://stackoverflow.com/questions/67522112

QUESTION

Calculate the days between dates from a grouped data.frame R dplyr

Asked 2021-Apr-28 at 03:30

I would like to calculate the number of days between rows of a data.frame groped by a couple of fields, so if I have the following data.frame:

...

ANSWER

Answered 2021-Apr-28 at 01:11

The following seems to work. I used lead (after arrange to order by date), and some tweaks to avoid dropping groups with only one date

Source https://stackoverflow.com/questions/67292240

QUESTION

Button (GPIO) Pressing Logic in MicroPython

Asked 2021-Apr-05 at 22:01

I had another question open about iterative menu logic, and the problem morphed into button logic, so I'm separating them, since the original question was truly settled.

My code is as follows:

...

ANSWER

Answered 2021-Apr-05 at 10:00

With both of your buttons tied to ground, and using PULL_UP the code is just:

Source https://stackoverflow.com/questions/66880711

QUESTION

Two-Button Menu Iteration

Asked 2021-Mar-30 at 03:49

I've got a script that I'm adapting to micropython on a 2040, and I want to use two buttons to navigate the menu structure. I can't figure out how to make the iterate loop in the multi-choice menus work right... here's what I've got so far:

...

ANSWER

Answered 2021-Mar-30 at 03:49

0.01 second is way too short. The key is, after you detect "button down", you need to wait for "button up". You need something like:

Source https://stackoverflow.com/questions/66864354

QUESTION

Error! cannot create the database connection. / OS X / sqlite3 / python3

Asked 2021-Mar-05 at 22:32

I'm having some trouble connecting to a sqlite3 database I create in the course of a python script. It's in the same directory as the script, and it's getting created, but the table doesn't get created because it's throwing:

...

ANSWER

Answered 2021-Mar-05 at 22:31

Do not close your connection in the db_connect function and you need to return a conn from this function as well.

Source https://stackoverflow.com/questions/66500350

QUESTION

Would like to split columns with a variable and not have to use cases

Asked 2021-Mar-03 at 04:59

Would like to handle the cases with variables but I can't figure out how to set how many arrays to build based off number delineators found, thanks for any assistance that can be provided.

...

ANSWER

Answered 2021-Mar-03 at 04:57

There's a lot of code there but just to address your specific question, you can use a function to generate your fields array:

Source https://stackoverflow.com/questions/66449088

QUESTION

Is it possible to calculate function length at compile time in C++?

Asked 2021-Jan-29 at 20:52

I have this piece of code:

...

ANSWER

Answered 2021-Jan-29 at 19:14

There is no method in standard C++ to get the length of a function.

You'll need to use a compiler specific method.

One method is to have the linker create a segment, and place your function in that segment. Then use the length of the segment.

You may be able to use some assembly language constructs to do this; depends on the assembler and the assembly code.

Note: in embedded systems, there are reasons to move function code, such as to On-Chip memory or swap to external memory, or to perform a checksum on the code.

Source https://stackoverflow.com/questions/65960187

QUESTION

Constant Throughput Timer generates too much requests

Asked 2021-Jan-26 at 09:22

I created a jmeter testplan with a constant throughput timer, but it seems I'm getting way to much responses. instead of 100 im getting 500+, depending on other settings like stoping or continue on error, or response timeout.

I know that the Constant Throughput Timer is not 100% correct and I would understand it, if there are less requests but not why there are more.

I attached the config of my test.

...

ANSWER

Answered 2021-Jan-26 at 09:22

Constant Throughput Timer is precise enough at minute level, so if you configure your test to last longer - you will see the throughput going down gradually and after 1st minute it should be throttled to your 100 requests per minute.

If your scenario is to execute 100 requests evenly distributed across one minute you should rather go for Precise Throughput Timer or Throughput Shaping Timer which have immediate effect

Source https://stackoverflow.com/questions/65898492

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install fend

The easiest way to install fend locally is via your package manager.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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