lopez | Crawling and scraping the Web for fun and profit | Scraper library

 by   tokahuke Rust Version: v0.6.1 License: Non-SPDX

kandi X-RAY | lopez Summary

kandi X-RAY | lopez Summary

lopez is a Rust library typically used in Automation, Scraper, Selenium applications. lopez has no bugs, it has no vulnerabilities and it has low support. However lopez has a Non-SPDX License. You can download it from GitHub.

Crawling and scraping the Web for fun and profit.
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              lopez has a low active ecosystem.
              It has 11 star(s) with 2 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 6 open issues and 1 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of lopez is v0.6.1

            kandi-Quality Quality

              lopez has no bugs reported.

            kandi-Security Security

              lopez has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              lopez has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              lopez releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            lopez Key Features

            No Key Features are available at this moment for lopez.

            lopez Examples and Code Snippets

            No Code Snippets are available at this moment for lopez.

            Community Discussions

            QUESTION

            Remove a duplicate object with a specific key value from an array
            Asked 2021-May-18 at 04:54

            I have the below Array

            ...

            ANSWER

            Answered 2021-May-18 at 04:37

            QUESTION

            Python: how could this image be properly segmented?
            Asked 2021-May-07 at 16:16

            I would like to segment (isolate) the rod-like structures shown in this image:

            The best I've managed to do is this

            ...

            ANSWER

            Answered 2021-May-07 at 16:16

            Here is my attempt using a Meijering filter. The Meijering filter relies on symmetry when it looks for tubular structures and hence the regions where rods overlap (breaking the symmetry of the tubular shape) are not that well recovered, as can be seen in the overlay below.

            Also, there is some random crap that I have trouble getting rid off digitally, but maybe you can clean your prep a bit more before imaging.

            Source https://stackoverflow.com/questions/67421623

            QUESTION

            Group data and add new column
            Asked 2021-Apr-23 at 08:15

            Hello people from stackeoverflow, I have the following table:

            Input

            !

            I need to group by name, lastname and if one or more status of a person are 'sending' then the new_col will be 'not finished', if all status of a person are 'sended' then new_col will be 'finished'.

            Expected output

            name lastname new_col Juan Perez not finished Maria Lopez not finished Mario Lopez finished

            I try grouping but I'm stuck figuring this out.

            Thanks in advance.

            ...

            ANSWER

            Answered 2021-Apr-23 at 08:15
            SELECT name, 
                   lastname, 
                   CASE WHEN SUM(status != 'sended')
                        THEN 'not finished'
                        ELSE 'finished'
                        END new_col
            FROM table
            GROUP BY name, 
                     lastname
            

            Source https://stackoverflow.com/questions/67226301

            QUESTION

            Check if Range exist as substring in a cell (googlesheets)
            Asked 2021-Mar-16 at 16:22

            Most formulas I already checked are about finding if a specific cell exists in a range. I am trying to check the opposite, if values from a specific range exist as substring in a specific cell.

            Example, my range A1:A10 is:

            ...

            ANSWER

            Answered 2021-Mar-16 at 16:22

            This will return TRUE if any non-blank string from A1:A10 is in C1:

            =REGEXMATCH(C1, JOIN("|", FILTER(A1:A10, A1:A10 <> "")))

            This will return a range of TRUE/FALSE for every string in A1:A10 if it is in C1 or not:

            =INDEX(REGEXMATCH(C1, A1:A10))

            And this one will return only strings in A1:A10 which are in C1:

            =FILTER(A1:A10, REGEXMATCH(C1, A1:A10))

            Mind the special regex chars which should be escaped if they are in those A1:A10 strings (there are none in your example, so I did not add this escaping).

            Source https://stackoverflow.com/questions/66652829

            QUESTION

            How to find Bucketkey for BIM360 Docs files?
            Asked 2021-Mar-15 at 21:15

            i am attempting to find the true file size as suggested by response at previous inquiry.

            The response says to use GET projects/:project_id/folders/:folder_id/contents to find the hub_id and file_id of files on the BIM 360 docs hub.

            Whevener I use the bucket id as retrieved from GET projects/:project_id/folders/:folder_id/contents the message is returned "Bucket not found"

            How to find the bucket_id of files on BIM 360 docs?

            For example, this is how my file information reads at GET https://developer.api.autodesk.com/data/v1/projects/:project_id/folders/:folder_id/contents

            ...

            ANSWER

            Answered 2021-Mar-15 at 21:15

            You're omitting the required part of the response from GET folder contents on your question.

            Keep in mind that you'll need to get the id from included/relationships/storage/data/id of a specific file version, as you can find here.

            With this id obtained, please refer here to understand better how you can retrieve the bucketKey.

            You can also find it under included/relationships/storage/meta/href, but in this case, you'll find the value as "https://developer.api.autodesk.com/oss/v2/buckets//objects/...

            Source https://stackoverflow.com/questions/66590381

            QUESTION

            How do I remove part of a string that follows a certain pattern up to, but not including another pattern using R?
            Asked 2021-Feb-26 at 02:54

            I have a dataframe in R that contains people data. First part of a string is a full name. Every so often I encounter a nickname in brackets. There could be other data enclosed in brackets that I do not want to delete. Here is an example of a kind of data I am working with:

            ...

            ANSWER

            Answered 2021-Feb-26 at 02:54

            Use positive lookeahd (?=) so that first letter of last name is matched but not removed.

            Source https://stackoverflow.com/questions/66379385

            QUESTION

            Appending options to select via an AJAX request not working as expected
            Asked 2021-Jan-29 at 08:59

            I need to sort through the JSON and for all the verified users add a option to the attribute which has a id of verified-users-list. The issue is that I am trying to append the results of the verified users to HTML function getVerifiedUsers(id, url) { var ourRequest = new XMLHttpRequest(); ourRequest.open('GET', url); ourRequest.onload = function() { var ourData = JSON.parse(ourRequest.responseText); let test = verified(ourData) //console.log(test); $(id).append(`${test.name}`); } ourRequest.send(); } function verified(data) { var user = {}; var j = 0; for (let i = 0; i < data.length; i++) { if (data[i].verified == true) { user[j] = data[i]; j++; } } return user } getVerifiedUsers("#verified-users-list", "http://localhost:3000/user"); AJAX response: [{ "id": 0, "name": "Yan Li", "verified": true }, { "id": 1, "name": "Anna Lopez" }, { "id": 2, "name": "Bobby Patel", "verified": true }]

            ...

            ANSWER

            Answered 2021-Jan-29 at 08:54

            so I have done some refactoring, and this code should work. The option markup was wrong - id: part. Also i have refactored verified users loop part. The doc references you can find below.

            Source https://stackoverflow.com/questions/65951159

            QUESTION

            How to split a text / string with pattern of upper case letters?
            Asked 2021-Jan-21 at 08:48

            I’m looking to Split a text according to each interlocutor.

            The original text has this form:

            this is a speech text. FIRST PERSON: hi all, thank you for coming. SECOND PERSON: thank you for inviting us. TERCER PERSONA QUE SE LLAMA PEDRO: soy de acuerdo. CUARTA PERSONA (JOHN): Hi. How are you

            I’m searching for a final result like this:

            first column: FIRST PERSON |SECOND PERSON | TERCER PERSONA QUE SE LLAMA PEDRO | CUARTA PERSONA (JOHN)

            second column: hi all, thank you for coming | thank you for inviting us | soy de acuerdo | Hi. How are you

            The final result can also be in other format or reshaped.

            The Pattern to split is one or more Upper Word and a ":", but one difficulty is that the pattern in capital letters can have optional characters like: ():,;

            In fact the original text that I am searching to split is this one: https://lopezobrador.org.mx/2021/01/14/version-estenografica-de-la-conferencia-de-prensa-matutina-del-presidente-andres-manuel-lopez-obrador-458/

            I have tried different things using stringr rebus and qdap. First trying this pattern:

            ...

            ANSWER

            Answered 2021-Jan-21 at 08:38

            You may use strsplit on a pattern that matches either : preceded by a sequence of words with any upper case letters \p{Lu}, spaces (\s) and parentheses (and more if you need), or (|) the space, followed by the same sequence. We want the first element from the resulting list and cleaned with trimws. The result is an alternating pattern of speaker and text, which we can easily convert into a two-column matrix by row.

            Source https://stackoverflow.com/questions/65802238

            QUESTION

            How to remove duplicate object values from the array which is nested inside the object of an array?
            Asked 2021-Jan-21 at 04:23

            I have array structure as shown in below

            ...

            ANSWER

            Answered 2021-Jan-21 at 04:02

            QUESTION

            Why won't my xml and xslt link if the conditions are met?
            Asked 2021-Jan-20 at 07:41

            as it says in the title my xml does not read my xslt, I want to make a list taking the "first name" and "last name" but it doesn't work for me, I don't know if I'm making a mistake when putting the name or maybe I'm not doing well, saying that everything is stored in the same folder so there should be no problem but there is. I am attaching my xml and xslt to see if I am getting something wrong:

            xml name "comunidad":

            ...

            ANSWER

            Answered 2021-Jan-20 at 07:41

            You are not closing the xsl:value-of elements properly, and the reason you are not getting a useful error message is perhaps because you are running this in a browser.

            Corrected XSLT Stylesheet

            Source https://stackoverflow.com/questions/65791247

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install lopez

            You can download it from GitHub.
            Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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