lopez | Crawling and scraping the Web for fun and profit | Scraper library
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kandi X-RAY | lopez Summary
Crawling and scraping the Web for fun and profit.
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QUESTION
I have the below Array
...ANSWER
Answered 2021-May-18 at 04:37Try using:
QUESTION
ANSWER
Answered 2021-May-07 at 16:16Here is my attempt using a Meijering filter. The Meijering filter relies on symmetry when it looks for tubular structures and hence the regions where rods overlap (breaking the symmetry of the tubular shape) are not that well recovered, as can be seen in the overlay below.
Also, there is some random crap that I have trouble getting rid off digitally, but maybe you can clean your prep a bit more before imaging.
QUESTION
Hello people from stackeoverflow, I have the following table:
Input
!
I need to group by name, lastname and if one or more status of a person are 'sending' then the new_col will be 'not finished', if all status of a person are 'sended' then new_col will be 'finished'.
Expected output
name lastname new_col Juan Perez not finished Maria Lopez not finished Mario Lopez finishedI try grouping but I'm stuck figuring this out.
Thanks in advance.
...ANSWER
Answered 2021-Apr-23 at 08:15SELECT name,
lastname,
CASE WHEN SUM(status != 'sended')
THEN 'not finished'
ELSE 'finished'
END new_col
FROM table
GROUP BY name,
lastname
QUESTION
Most formulas I already checked are about finding if a specific cell exists in a range. I am trying to check the opposite, if values from a specific range exist as substring in a specific cell.
Example, my range A1:A10 is:
...ANSWER
Answered 2021-Mar-16 at 16:22This will return TRUE
if any non-blank string from A1:A10
is in C1
:
=REGEXMATCH(C1, JOIN("|", FILTER(A1:A10, A1:A10 <> "")))
This will return a range of TRUE
/FALSE
for every string in A1:A10
if it is in C1
or not:
=INDEX(REGEXMATCH(C1, A1:A10))
And this one will return only strings in A1:A10
which are in C1
:
=FILTER(A1:A10, REGEXMATCH(C1, A1:A10))
Mind the special regex chars which should be escaped if they are in those A1:A10
strings (there are none in your example, so I did not add this escaping).
QUESTION
i am attempting to find the true file size as suggested by response at previous inquiry.
The response says to use GET projects/:project_id/folders/:folder_id/contents to find the hub_id and file_id of files on the BIM 360 docs hub.
Whevener I use the bucket id as retrieved from GET projects/:project_id/folders/:folder_id/contents the message is returned "Bucket not found"
How to find the bucket_id of files on BIM 360 docs?
For example, this is how my file information reads at GET https://developer.api.autodesk.com/data/v1/projects/:project_id/folders/:folder_id/contents
...ANSWER
Answered 2021-Mar-15 at 21:15You're omitting the required part of the response from GET folder contents on your question.
Keep in mind that you'll need to get the id from included/relationships/storage/data/id
of a specific file version, as you can find here.
With this id obtained, please refer here to understand better how you can retrieve the bucketKey.
You can also find it under included/relationships/storage/meta/href
, but in this case, you'll find the value as "https://developer.api.autodesk.com/oss/v2/buckets//objects/...
QUESTION
I have a dataframe in R that contains people data. First part of a string is a full name. Every so often I encounter a nickname in brackets. There could be other data enclosed in brackets that I do not want to delete. Here is an example of a kind of data I am working with:
...ANSWER
Answered 2021-Feb-26 at 02:54Use positive lookeahd (?=
) so that first letter of last name is matched but not removed.
QUESTION
I need to sort through the JSON and for all the verified users add a option to the attribute which has a id of verified-users-list.
The issue is that I am trying to append the results of the verified users to HTML
function getVerifiedUsers(id, url) {
var ourRequest = new XMLHttpRequest();
ourRequest.open('GET', url);
ourRequest.onload = function() {
var ourData = JSON.parse(ourRequest.responseText);
let test = verified(ourData)
//console.log(test);
$(id).append(`${test.name}`);
}
ourRequest.send();
}
function verified(data) {
var user = {};
var j = 0;
for (let i = 0; i < data.length; i++) {
if (data[i].verified == true) {
user[j] = data[i];
j++;
}
}
return user
}
getVerifiedUsers("#verified-users-list", "http://localhost:3000/user");
AJAX response:
[{
"id": 0,
"name": "Yan Li",
"verified": true
}, {
"id": 1,
"name": "Anna Lopez"
}, {
"id": 2,
"name": "Bobby Patel",
"verified": true
}]
ANSWER
Answered 2021-Jan-29 at 08:54so I have done some refactoring, and this code should work.
The option markup was wrong - id:
part. Also i have refactored verified users loop part.
The doc references you can find below.
QUESTION
I’m looking to Split a text according to each interlocutor.
The original text has this form:
this is a speech text. FIRST PERSON: hi all, thank you for coming. SECOND PERSON: thank you for inviting us. TERCER PERSONA QUE SE LLAMA PEDRO: soy de acuerdo. CUARTA PERSONA (JOHN): Hi. How are you
I’m searching for a final result like this:
first column: FIRST PERSON |SECOND PERSON | TERCER PERSONA QUE SE LLAMA PEDRO | CUARTA PERSONA (JOHN)
second column: hi all, thank you for coming | thank you for inviting us | soy de acuerdo | Hi. How are you
The final result can also be in other format or reshaped.
The Pattern to split is one or more Upper Word and a ":", but one difficulty is that the pattern in capital letters can have optional characters like: ():,;
In fact the original text that I am searching to split is this one: https://lopezobrador.org.mx/2021/01/14/version-estenografica-de-la-conferencia-de-prensa-matutina-del-presidente-andres-manuel-lopez-obrador-458/
I have tried different things using stringr rebus and qdap. First trying this pattern:
...ANSWER
Answered 2021-Jan-21 at 08:38You may use strsplit
on a pattern that matches either :
preceded by a sequence of words with any upper case letters \p{Lu}
, spaces (\s
) and parentheses (and more if you need), or (|
) the space, followed by the same sequence. We want the first el
ement from the resulting list and cleaned with trimws
. The result is an alternating pattern of speaker and text, which we can easily convert into a two-column matrix
by row.
QUESTION
I have array structure as shown in below
...ANSWER
Answered 2021-Jan-21 at 04:02To solve with Rambda:
QUESTION
as it says in the title my xml does not read my xslt, I want to make a list taking the "first name" and "last name" but it doesn't work for me, I don't know if I'm making a mistake when putting the name or maybe I'm not doing well, saying that everything is stored in the same folder so there should be no problem but there is. I am attaching my xml and xslt to see if I am getting something wrong:
xml name "comunidad":
...ANSWER
Answered 2021-Jan-20 at 07:41You are not closing the xsl:value-of
elements properly, and the reason you are not getting a useful error message is perhaps because you are running this in a browser.
Corrected XSLT Stylesheet
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