SpiralS | /// ///// // // Platform Adaptation of DSP Algorithms
kandi X-RAY | SpiralS Summary
kandi X-RAY | SpiralS Summary
/// ///|// |// // Platform Adaptation of DSP Algorithms SpiralS 0.1 Prototype - ETH Zurich Copyright (C) 2013 Georg Ofenbeck (ofenbeck@inf.ethz.ch) This program is free software: you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program. If not, see
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QUESTION
I'm trying to draw a spiral square in python using OpenCV and Numpy. I know that I can do it via turtle and there are so many examples on the internet but I need to do it as I described in the title. So I drew chessboard chessboard via python OpenCV
This is code for it
...ANSWER
Answered 2021-Oct-31 at 19:00If you look at the picture you see that the pattern is actually pretty simple. You have to go right, up, left, down
and repeat a few times. Also the distance you have to go starts with 3 and goes up by two every other step.
After having down that I calculate how much space I need to draw that and shift the points so the coordinates are not negative. Here is my code:
QUESTION
I wrote this recursive code which draws a hexagon spiral in turtle and then is supposed to draw a square spiral. But instead it sends me an error "maximum recursion depth exceeded in comparison". Yet it works when I execute both functions in separate files. In both cases the functions take as a parameter the number of spirals n
.
Could someone explain to me why please.
ANSWER
Answered 2021-Oct-29 at 18:21This is due to an indentation error:
QUESTION
Please help
I have been finding a code for this but failed
source: https://www.singtel.com/etc/singtel/public/tv/epg-parsed-data/23102021.json This is a epg html site
Could you suggest a way to convert this link contents to XML?
btw the link is based on the day https://www.singtel.com/etc/singtel/public/tv/epg-parsed-data/ddMMyyyy.json
maybe this will help
...ANSWER
Answered 2021-Oct-23 at 10:46I am not sure about what you want to do exactly.
Let say your have a JSON data file accessible by a simple GET request (as it seems to be) and want to convert it into an XML file using PHP.
First, you can convert your json to array with json_decode. Then, you can SimpleXML extension to generate an XML output.
As an example:
QUESTION
I'm animating an element along a path, and while the animation works fine I need to be able to animate the element going TO the path, and then along it.
I can't find any examples of ways to do this, should I create an invisible element so I have a target to animate that element to before it starts on the path? If so how could I do that, or is there a better way?
This is my path.
...ANSWER
Answered 2021-Aug-05 at 03:49I was able to create a solution. I wanted to animate an element along a path, but the element doesn't start exactly where the path begins. In my example the path starts on the top-middle side of the container, but the element is closer to the top-left side of the container. This moves an element toward the top-middle side, then starts the animation along the path once the element reaches it.
The code could be adapted to other similar situations. I'm sure there are better ways but I've gone through the GSAP and anime.js libraries and couldn't find a way to do it without the Flip plug-in from GSAP which is under the paid license.
QUESTION
I am trying to make a spiral with a 2d array. However I am missing the last element as shown in the picture.
.
I tried to make all kinds of conditions in the while loop to stop the algorithm one cycle later, but I couldn't and I am getting crazy because of it. The main algorithm code below:
...ANSWER
Answered 2021-Jun-22 at 11:21The reason is that you update the boundary variables (top
, left
, right
, bottom
) with a step of two at a moment that you still need to fill one cell that is outside that box when you start with your next direction (which is why you do two blankGrid
assignments in each iteration of the inner loops -- which looks strange). This is no problem as long as the while
condition is true, but in the last phase that condition will be false, meaning that the "box" has narrowed to nothing. Yet there is still this one cell to place...
One solution is to not change that boundary with 2, but just 1, and do the other increment/decrement when you start with in the next direction.
Your loop body could be updated with this idea as follows:
QUESTION
I am trying to make a grid out of angular spirals. The spiral itself is composed of single lines within a for loop. When I duplicate and shift (translate) the origin of the spiral along one axis (x OR y) it works. But shifting along both (x AND y), in order to make it a grid, it does not work out without decomposing the spiral.
I would really appreciate if anyone could help me with my coding puzzle. By the way I'm very open-minded for any tips and help improving my code writing skills. There surely is a lot of redundancy and long-winded expressions in there... This is my code so far:
...ANSWER
Answered 2021-May-07 at 21:08If you're trying to make a grid of spirals it looks like you just need to use a pair of for loops where you currently have for (let j = 0; j < 5; j++) {
. Pretty much any time you want to create a grid you're going to want a pair of nested for loops.
QUESTION
I have made a simple python program that creates randomly generated spirals using the turtle module. I am still pretty new at python and i was wondering how i could restart the program after the turtle is pretty far away from the center and the spiral is done. Here is my code:
...ANSWER
Answered 2021-Apr-12 at 17:43You could do it by using a global flag variable and installing a turtle timer that calls a function that periodically checks to see whether a spiral has finished being drawn yet by looking at the variable — and if so, resets things and draws another one. In the code below the function that does that is named check_status()
. I also added a short pause before the after each one is finished to allow it to remain visible long enough to be admired. ;¬)
QUESTION
I have a light to dark mode switcher and I have two different logos, one for the dark mode and one for the light mode.
I need to make it so when the page is in the dark mode it shows the dark mode logo but when it is in the light mode it shows the light mode logo.
This sounds really easy but it isn't (at least for new coders like me).
Someone asked me to produce a minimal reproducible example, I hope this is good.
...ANSWER
Answered 2021-Mar-26 at 08:24If I manipulate Light/Dark Theme Toggle
I get this
QUESTION
The following pseudo code works for modelling linear acceleration (applying calculateNextStep
and doNextStep
for each time tick):
ANSWER
Answered 2020-Dec-31 at 10:11You are right with your assumption. The problem lies with the tangential force.
But there are two problems with the way you calculate your tangential force:
- What you mentioned, that the force should apply instantaneously.
- The way you calculate your force, the center of rotation changes throughout the simulation.
Both of those can be fixed by decreasing the timestep and increasing the number of iterations, but those are hardware bound, so you will eventually hit the bottom there.
A better way to fix those problems is by using a different model:
Using a conservative force(examples of that are gravity, electrostatic forces, Forces from a rope that connects your object and the center, …) allows the system to correct itself if it starts spiraling(If your object leaves the desired radius, conservative forces will make sure it comes back).
Here an example implementation for gravity:
QUESTION
I have been asked from my professor to add an object in the middle of an ArrayedList
using listiterator.
I have tried doing in the following way first:
...ANSWER
Answered 2020-Nov-17 at 21:10I have found it after digging deeper in the debugger.
At the moment before adding li.nextIndex() == 5
and li.previousIndex() == 4
After adding the object the aforementioned change to li.nextIndex() == 6
and li.previousIndex() == 5
this is because listIterator's .add()
inserts the object before .next()
.
Moving ahead with this problem sets up a back and forth loop where li.previous()
decreases both li.previousIndex()
and li.nextIndex()
by 1, and calling li.add(emp_M)
increases both aforementioned values by 1.
To fix it, we need to skip the added element after adding:
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