z | Pure-fish z directory jumping | Plugin library
kandi X-RAY | z Summary
kandi X-RAY | z Summary
z is a port of z for the fish shell. z tracks the directories you visit. With a combination of frequency and recency, it enables you to jump to the directory in mind. A pure-fish port means z is fast and fish-friendly, with tab-completions and lazy-loading. Top that off with great customizability and a small amount of added functionality. Originally written by @jethrokuan, co-maintained with @krobelus.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of z
z Key Features
z Examples and Code Snippets
def z_function(input_str: str) -> list[int]:
"""
For the given string this function computes value for each index,
which represents the maximal length substring starting from the index
and is the same as the prefix of the same size
def angle(z, deg=False): # pylint: disable=missing-function-docstring
def f(x):
if x.dtype in _tf_float_types:
# Workaround for b/147515503
return array_ops.where_v2(x < 0, np.pi, 0)
else:
return math_ops.angle(x)
public static double zScore(double num, double mean, double stdDev)
{
double z = (num - mean)/stdDev;
return z;
}
Community Discussions
Trending Discussions on z
QUESTION
I'm learning C++ and have come to a bit of a halt. I'm trying to iterate over a vector with a range-based for loop and update a property on each of the objects that belong to it. The loop is inside of an update function. The first time it fires, it works fine; I can see the property gets updated on each member of the vector. However, the next time the for loop is initiated, it's still updating the original data, as if the previous run did not actually update the source values. Is my range declaration configured correctly? Pointers are still a bit of a mystery to me. In general I'd be very thankful for any help!
...ANSWER
Answered 2021-Jun-15 at 23:19Vector3 position = point.position;
makes a copy of point.position
. The following code then updates this copy, which in turn is thrown away when it goes out of scope at the end of the if
statement.
The solution is simple enough - use a reference instead: Vector3 &position = point.position;
. The rest of the code can be left as-is.
QUESTION
I want to extract the name of a prerequisite from the target.
...ANSWER
Answered 2021-Jun-14 at 13:53The short answer is, you can't. Automatic variables, as made clear in the documentation, are only set inside the recipe of a rule, not when expanding the prerequisites. There are advanced features you can take advantage of to work around this, but they are intended only to be used in very complicated situations which this isn't, really.
What you want to do is exactly what pattern rules were created to support:
QUESTION
Is it possible to two reduce objects into one by summing their properties like so for any generic object
...ANSWER
Answered 2021-Jun-04 at 20:04A functional approach would be (but probably not clean)
QUESTION
I have to parse lists of names, addresses, etc. that were OCRed and have invalid/incorrect characters in them and on the state postal code I need to recognize the pattern with a 2 character state followed by a 5 digit postal code and replace any non numeric characters in the postal code. I might have OK 7-41.03
at the end of a string I need to remove the hyphen and period. I know that re.sub('[^0-9]+', '', '7-41.03')
will remove the desired characters but I need it only replace characters in numbers when found at the end of the string and only if preceded by a two character state wrapped in spaces like OK
. It seems if I add anything to the regular expression as far as a lookbehind expression then I can't seem to get the characters replaced. I've come up with the following but I think there must be a simpler expression to accomplish this. Example:
ANSWER
Answered 2021-Jun-15 at 20:02You need to make use of re.sub
callbacks:
QUESTION
I am trying to reduce lines of code because I realized that I am repeating the same equations every time. I am programming a contour map and putting several sources of intensity into it. Until now I put 3 sources, but in the future I want to put more, and that will increase the lines a lot. So I want to see if it is possible to reduce the lines of "source positions" and "Intensity equations". As you can see the last equation is a logaritmic summation of z1, z2 and z3, is it possible to reduce that, any idea?
...ANSWER
Answered 2021-Jun-15 at 15:45You could iterate over certain parts in a loop.
I tried to keep the same format overall and just rearranged the code to show how you might do it.
QUESTION
So... I can sympy.integrate
a normal distribution with mean and standard deviation:
ANSWER
Answered 2021-Jun-15 at 01:38Here's a close case that works:
QUESTION
I have been trying to sort the Column values from A to Z which are populated in the List Box.
I have tried with the following but it does not adjust it. Any help will be appreciated.
...ANSWER
Answered 2021-Jun-15 at 18:37You need to sort the range using the Range.Sort method
QUESTION
First time actually using anything to do with swing - sorry for the poor code and crude visuals!
Using swing for a massively over-complicated password checker school project, and when I came to loading in a JMenuBar, it doesn't render properly the first time. Once I run through one of the options first, it reloads correctly, but the first time it comes out like this:
First render attempt
But after I run one of the methods, either by clicking one of the buttons that I added to check if it was just the JFrame that was broken or using one of the broken menu options, it reloads correctly, but has a little grey bar above where the JMenuBar actually renders: Post-method render
The code for the visuals is as follows:
...ANSWER
Answered 2021-Jun-15 at 18:29You should separate creating your menu from your content. Please review the following example. I decoupled your menu, component, and event logic into meaningful phases.
QUESTION
I am a beginner learning from a tutorial on how to change the colour of a selected area of a picture with a range of colour options.
I can figure out how to change one area, but unsure how to implement the other areas.
What I want to achieve is to click on the selected area, it highlights the border (CSS), then change the colour by using the colour options.
What is the best way to implement this? I'm I correct in thinking maybe a switch statement with onclick to select the specific area of the picture?
...ANSWER
Answered 2021-Jun-15 at 11:48You could try having a "select" function run when you click on one of the areas. This function would "highlight" the area (border-color), and save the id of the area in a variable.
Then when you click on the color swatches another function would run that will take the value previously saved id and select the HTML element based on that.
QUESTION
Say I have a list of every single letter in the alphabet
...ANSWER
Answered 2021-Jun-15 at 18:04An option with tidyverse
- Get the objects in a named
list
(dplyr::lst
) - Convert the named list to a tibble -
enframe
unnest
thelist
column- Extract the substring from the 'name', convert it to upper case
- Do a join (
right_join
) with the 'chars' converted to atibble
arrange
the rows after replacing the NA with 'Unique'pull
the column as avector
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