zsh | This is the small /.zshrc file I use on Mac and Linux | Configuration Management library

by mhubig Shell Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | zsh Summary

zsh is a Shell library typically used in Devops, Configuration Management applications. zsh has no bugs and it has low support. However zsh has 6 vulnerabilities. You can download it from GitHub.

This are the ZSH configuration files I use on Mac and Linux. They are now based on the mighty prezto. Use at your own risk.

Support

Quality

Security

License

Reuse

Support

zsh has a low active ecosystem.

It has 1 star(s) with 0 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

zsh has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of zsh is current.

Quality

zsh has no bugs reported.

Security

zsh has 6 vulnerability issues reported (3 critical, 2 high, 1 medium, 0 low).

License

zsh does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

zsh releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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zsh Key Features

No Key Features are available at this moment for zsh.

zsh Examples and Code Snippets

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Community Discussions

Trending Discussions on Configuration Management

Puppet copy file if not empty

Declaring configuration of custom configurable application in java?

To run playbook based on ansible_distribution

QUESTION

Puppet copy file if not empty

Asked 2020-Dec-17 at 02:50

I have a requirement where I need to check for a file on the puppet master and copy it to the agent only if it is not empty.

I have the following so far:

...

ANSWER

Answered 2020-Dec-17 at 02:50

You cannot use an Exec resource to perform the check, because you need to perform the evaluation during catalog building, and resources are not applied until after the catalog is built. Moreover, the test command tests for the existence of a the specified path. It does not know about URLs, and even if it did, it would be unlikely to recognize or handle the puppet: URL scheme. Furthermore, there is no association whatever between resource titles and variable names.

To gather data at catalog building time, you're looking for a puppet function. It is not that hard to add your own custom function to Puppet, but you don't need that for your case -- the built-in file() function will serve your purpose. It might look something like this:

Source https://stackoverflow.com/questions/65333257

QUESTION

Declaring configuration of custom configurable application in java?

Asked 2020-Nov-10 at 11:42

So for a hobby project of mine, I would like to create an application that translates an HTTP call and request between two services.

The application does that based on a configuration that can be set by the user. The idea is that the application listens to an incoming API call translates the call and then forwards it.

Then the application waits for a response then translates the response and sends it back to the caller.

A translation can be as simple as renaming a field value in a body object or replace a header field to the body.

I think a translation should begin with mapping the correct URL so here is an example of what I was thinking of a configuration should look like:

...

ANSWER

Answered 2020-Nov-10 at 11:42

I have done something sort-of-similar in a different context (generate code from an input specification), so I will provide an outline of what I did to provide some food for thought. I used Config4* (disclosure: I developed that). If the approach I describe below is of interest to you, then I suggest you read Chapters 2 and 3 of the Config4* Getting Started Guide to get an overview of the Config4* syntax and API. Alternatively, express the concepts below in a different configuration syntax, such as XML.

Config4* is a configuration syntax, and the subset of syntax relevant to this discussion is as follows:

Source https://stackoverflow.com/questions/64766419

QUESTION

To run playbook based on ansible_distribution

Asked 2020-Feb-10 at 14:44

I have written separate playbooks for tomcat deployment on both Ubuntu and Linux as well, instead of mentioning **

when: ansible_distribution == 'Ubuntu'

**in every line in the playbook, i want to run the whole playbook only when this condition meets.

This is my code

...

ANSWER

Answered 2020-Feb-10 at 14:44

Q: "I want to run the playbook only on the hosts based on the ansible_distribution."

A: It's not possible to include a playbook. This would run the playbooks recursively.

Only import of a playbook is available. Moreover import_playbook is not a task. It's simply a tool to modularize large playbooks with multiple plays.

Ansible conditionals do not apply to import_playbook the same way as they do not apply to playbooks.

Instead, it is possible to create a group that will be used in the playbook.

Source https://stackoverflow.com/questions/60140478

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install zsh

Install zsh and set as login shell.
Install zsh and set as login shell. On Ubuntu do: $ sudo apt-get install zsh $ chsh -s /usr/bin/zsh On Mac OS X do: $ brew install zsh Then set the shell in the system preference pane, like here:
Clone this repository. $ git clone git@github.com:mhubig/zsh.git ~/.zsh
Clone the zgen. $ git clone git@github.com:tarjoilija/zgen.git ~/.zgen
Start ZSH and link the config files. $ zsh % zfiles=(zlogin zlogout zprofile zshenv zshrc) % for file in $zfiles; do ln -s "$HOME/.zsh/$file" "$HOME/.${file:t}" done
Make your own copy of the zlocal file. $ cp ~/.zsh/zlocal.example ~/.zsh/zlocal $ vim ~/.zsh/zlocal
Now restart your terminal!

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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