bash-functions | A collection of useful Bash/ZSH functions | Plugin library
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kandi X-RAY | bash-functions Summary
A collection of useful Bash/ZSH functions
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Trending Discussions on bash-functions
QUESTION
I try to read a file into a variable with git-bash
. I am using something like this:
ANSWER
Answered 2020-Dec-16 at 08:00Do not use eval.
In bash
, you can $(
instead of $(cat file)
. It's just a bit faster.
You can use a namereference:
QUESTION
Hope you are all well!
I am after achieving this relatively simple task, yet I am failing in getting optimal results, so I need your help.
Scenario:
I have the following files and folders (directories) structure:
...ANSWER
Answered 2020-Oct-20 at 11:59Here is a working solution I have come up with so far which needs to be optimised and cleaned up, its rudimentary and I can use optimisation tips:
QUESTION
It seems that the set -e
option in Bash gets reset inside of functions, when those functions are invoked via a $(...)
expansion.
This surprises me, and I'm not sure if it is a bug or not. I have not been able to find a description of this behavior in the (usually quite thorough) Bash manpage.
Note: here are some other similar SO posts:
But neither of them deals with $(...)
, which is not really discussed in the manpage either.
I also cannot find reference to this issue in the excellent Bash FAQ 105.
Here is a small program to demonstrate the issue:
...ANSWER
Answered 2019-Oct-04 at 00:35The behaviour of set -e
in conjunction with Command Substitution is documented in
Command Execution Environment:
Subshells spawned to execute command substitutions inherit the value of the
-e
option from the parent shell. When not in POSIX mode, Bash clears the-e
option in such subshells.
That seems to say that the behaviour you see is expected — unless you're running in POSIX mode, the -e
option is unset in command substitution subshells in Bash (even though the -e
setting is initially inherited, it is changed soon after the subshell commences execution). It's a funny way of writing it, though.
QUESTION
I know there are several SO questions on exit
vs. return
in bash
scripts (e.g. here).
On this topic, but different from existing questions, I believe, I'd like to know if there is a "best practice" for how to safely implement "early return" from a bash
script such that the user's current shell is not exited if they source the script.
Answers such as this seem based on "exit
", but if the script is sourced, i.e. run with a ".
" (dot space) prefix, the script runs in the current shell's context, in which case exit
statements have the effect of exiting the current shell. I assume this is an undesirable result because a script doesn't know if it is being sourced or being run in a subshell - if the former, the user may unexpectedly have his shell disappear. Is there a way/best practice for early-returns to not exit the current shell if the caller sources it?
E.g. This script...
...ANSWER
Answered 2018-Aug-24 at 23:04The most common solution to bail out of a script without causing the parent shell to terminate is to try return
first. If it fails then exit
.
Your code will look like this:
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