Ratios | A calculator for making coffee | Apps library
kandi X-RAY | Ratios Summary
kandi X-RAY | Ratios Summary
Ratios is a free and open source calculator for home brewed coffee. Quickly and easily enter the total amount of coffee you want to make and Ratios will calculate the weight of beans and amount of water needed based on your desired strength. All the information is editable and updates instantly so you can see how different values affect your overall brew.
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QUESTION
This question is an extension of my previous question: Fast python algorithm to find all possible partitions from a list of numbers that has subset sums equal to a ratio . I want to divide a list of numbers so that the ratios of subset sums equal to given values. The difference is now I have a long list of 200 numbers so that a enumeration is infeasible. Note that although there are of course same numbers in the list, every number is distinguishable.
...ANSWER
Answered 2021-Jun-12 at 15:14You can use a greedy heuristic where you generate each partition from num_gen
random permutations of the list. Each random permutation is partitioned into len(ratios)
contiguous sublists. The fact that the partition subsets are sublists of a permutation make enforcing the ratio condition very easy to do during sublist generation: as soon as the sum of the sublist we are currently building reaches one of the ratios, we "complete" the sublist, add it to the partition and start creating a new sublist. We can do this in one pass through the entire permutation, giving us the following algorithm of time complexity O(num_gen * len(lst))
.
QUESTION
df
...ANSWER
Answered 2021-Jun-12 at 09:35df = pd.DataFrame({'channel': {0: 'Facebook', 1: 'Bing', 2: 'Google'},
'ratio_customer_to_lead_owner': {0: 2, 1: 1, 2: 6},
'ratio_customer_to_agent': {0: 5, 1: 1, 2: 13}})
df.set_index('channel').T.plot(kind='bar')
QUESTION
Say I have a list of 20 random integers from 0 to 9. I want to divide the list into N
subsets so that the ratio of subset sums equal to given values, and I want to find all possible partitions. I wrote the following code and got it work for the N = 2
case.
ANSWER
Answered 2021-Mar-20 at 15:55Yes, recursion is called for. The basic logic is to do a bipartition into one part and the rest and then recursively split the rest in all possible ways. I've followed your lead in assuming that everything is distinguishable, which creates a lot of possibilities, possibly too many to enumerate. Nevertheless:
QUESTION
Here's the context: I have to produce a mix of different products. I don't want to produce them in single lots for each product, but instead I want to make lots as small and as homogenous as possible, with each lot containing a small amount of the total production.
For each product I know the demand:
...ANSWER
Answered 2021-Jun-09 at 23:11The problem with your code is in the else
clause, where you set split
to an int
. Indeed, you then try to call split[1]
right after, thus getting an error.
A solution to this problem is to duplicate the splits.update
instruction and modify it to work with an int
, as described below:
QUESTION
I have a predictor variable called "Group", this group has 3 categories (ALTO, MEDIO, BAJO). In my glm for binomial family, the summary shows the intercept + BAJO and MEDIO, but I need to see in my tab_model only ALTO and MEDIO and let BAJO as intercept. Is there any way to change this setting?
...ANSWER
Answered 2021-Jun-09 at 12:29You can use the relevel()
function to specify which level of the factor is the reference level. Assuming the variable Grupo is already a factor, this should work:
QUESTION
Jupyter Notebook. A Batch API call returns a JSON array of objects. Parsing requires for loops (weird). I need to append certain JSON object info into a Pandas DataFrame.
...ANSWER
Answered 2021-Jun-07 at 18:26You have to assign the result of append, e.g.
QUESTION
I'm trying to pivot this tibble with {tidyr} but withouT success...
Can someone help me ?
Many thanks in advance
ANSWER
Answered 2021-Jun-07 at 13:52You could do:
QUESTION
My project is a simple agent based simulation that models the spread of disease. The simulation consists of agents and map, the classes that belong to agents are: Civil
, Medic
and Animal
. Currently I'm trying to fill the map according to the size of populations: noMedics
, noCivils
, noAnimals
and amount of healthy
, ill
, and immune
agents that should add up to total population of both humans and animals.
The way that health status of an agent is determined is simple - random.nextInt(3)
, 0
being healthy, 1
ill and 2
immune. The way that I would usually fill the map with one of the agent class is as follows:
ANSWER
Answered 2021-Jun-05 at 16:48You say that Medics should have an Immune health status. The remaining problem is therefore to assign Civilians and Animals a health status of Healthy, Ill, or Immune such that:
QUESTION
tags within a certain
tag?I am using BeautifulSoup to parse some html page.
I want to get all text information within the
tags under this
When I use find_all
to get all of the
tags, the list contains only the first one. I used to following code to count the no. of
tags present under
tags within that highlighted
ANSWER
Answered 2021-May-18 at 13:56You can go after the direct url that has that info. You'll need to pass in there the correct cookies and csrf tokens though:
QUESTION
I've recently implemented a lazy image loading feature on an image-heavy website, and have been having issues with reflow. I fixed the problem by manually specifying the image dimensions using the width
and height
image attributes, as below:
ANSWER
Answered 2021-May-26 at 22:08The issue was related to a calculation error in Safari's WebKit API. The issue was reported on the WebKit Bugzilla (report), and was patched in WebKit Changeset 276521. Said changeset was merged and released with Safari Technical Preview 125.
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