Superhighway | As big a networking library as you 'll need | Networking library
kandi X-RAY | Superhighway Summary
kandi X-RAY | Superhighway Summary
Superhighway is a networking library heavily inspired by tiny-networking. It defines an Endpoint type which encapsulates the relationship between a URLRequest and the Decodable entity it represents.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Superhighway
Superhighway Key Features
Superhighway Examples and Code Snippets
struct Repository: Decodable {
let id: Int64
let name: String
}
func getRepository(author: String, name: String) -> Endpoint {
return Endpoint(json: .get, url: URL(string: "https://api.github.com/repos/\(author)/\(name)")!)
}
let end
// swift-tools-version:5.5
import PackageDescription
let package = Package(
// ...
dependencies: [
.package(url: "https://github.com/rhysforyou/Superhighway.git", "0.5.0"..<"0.6.0")
],
targets: [
.target(
Community Discussions
Trending Discussions on Superhighway
QUESTION
I got the solution But, i can't understand the function named 'isInSecondArray()' and its parameter 'item'. How that works.
...ANSWER
Answered 2020-Aug-03 at 05:54Your code compares two arrays—concretely, it keeps only those items of the first array that the second array contains.
To do so, your function justCoolStuff
takes both arrays. Then it declares a function called isInSecondArray
. This function is then passed to the invocation of the filter function in the line firstArray.filter(isInSecondArray)
.
The filter
function iterates over firstArray
. As it iterates, it passes each item from firstArray
into the isInSecondArray
function. For example, if firstArray
contains five elements, then isInSecondArray
will run five times, once with each item. At every iteration, the isInSecondArray
function iterates over the second array and compares the item from the first array with the current item from the second array. filter
then returns a new array with only those items for which isInSecondArray
returned a truthy value.
In other words, you have two loops, one implicit in filter
, another explicit in the for
loop. The for
loop is nested in the filter
loop. If your arrays have five and four items, respectively, there will be a total of 4 * 5 = 20 iterations. (That number could be reduced significantly if you used sets instead of arrays, but admittedly that's not what you asked about.)
QUESTION
I have the following task:
A word "Superhighway" is given. Check if such word can be composed of entries in the array: [ab, bc, Super, h, igh, way] - yes; [ab, bc, Super, way] - no;
My suggestion is to build Trie from the array and based on the Trie conclude can the target word be derived or not.
Also, I've seen that Dynamic Programming is applicable to similar problems.
Could you please explain the best solution for the task?
...ANSWER
Answered 2019-May-14 at 23:31Dynamic programming should be applied here. The optimal substructure here is:
dp[i]: if s[0, i) can be composed of entries in the provide array.
dp[i] |= dp[j] && (s[j, i) is an entry in the array).
QUESTION
I have my navigation links at the top of my page. I have each link anchored to it's respective div further down the page. I can't get it to transition, it just automatically jumps. I have tried the solution at Scrolling to an Anchor using Transition/CSS3. My code is:
...ANSWER
Answered 2017-Jan-27 at 16:02You need to pass it the event to stop it doing its default action and jumping to the element.
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