straightforward | 🏴 A straightforward forward-proxy written in Node.js | Proxy library
kandi X-RAY | straightforward Summary
kandi X-RAY | straightforward Summary
A straightforward forward-proxy written in Node.js.
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body {
background: #DEDEDE;
}
/*-- Extracted from tailwindcss --*/
/*! normalize.css v8.0.1 | MIT License | github.com/necolas/normalize.css */
/* Document
====================================================================
isPointInArea(event) {
const x = event.offsetX;
const y = event.offsetY;
// For rectangle it is straightforward
if (x >= 60 && x <= 325 && y >= 60 && y <= 215) {
retu
Community Discussions
Trending Discussions on straightforward
QUESTION
I am trying to define a subroutine in Raku
whose argument is, say, an Array of Ints (imposing that as a constraint, i.e. rejecting arguments that are not Array
s of Int
s).
Question: What is the "best" (most idiomatic, or straightforward, or whatever you think 'best' should mean here) way to achieve that?
Examples run in the Raku
REPL follow.
What I was hoping would work
...ANSWER
Answered 2021-Jun-15 at 06:40I think the main misunderstanding is that my Int @a = 1,2,3
and [1,2,3]
are somehow equivalent. They are not. The first case defines an array that will only take Int
values. The second case defines an array that will take anything, and just happens to have Int
values in it.
I'll try to cover all versions you tried, why they didn't work, and possibly how it would work. I'll be using a bare dd
as proof that the body of the function was reached.
#1
QUESTION
I’m using R to prepare data to input into a model (written in Fortran, compiled into an .exe).
The model requires a text file as input which I'm generating using R. In the end it’s mostly just a list of variables (like ‘VARIABLE_X = 0.6’). The value of these variables is based on some processing I'm doing in R. An example on how the generated text file partly looks like;
...ANSWER
Answered 2021-Apr-16 at 11:39Maybe something like the following function is what the question asks for.
QUESTION
I am working on recovering from collision. I have the names of bodies in collision and the frames associated with them and now I want to move the body/frame that is closer to the end effector to get out of collision, but I couldn't find a straightforward way to get this information from a MultiBodyPlant
. I could construct another representation of the graph and search through it, but I was wondering if it is possible to maybe get this from drake
instead?
ANSWER
Answered 2021-Jun-14 at 16:07Wow. I think you're right that we don't make this one easy (but we should).
For now, I would think you can call MultibodyPlant::GetJointIndices()
and then loop the joints via MultibodyPlant::get_joint()
to find the joint Joint::child_body() == collision_body
, and then use Joint::parent_body()
. And we can open an issue if avoiding that (small?) linear search becomes important?
QUESTION
Small question regarding Spring Webflux, and how to "chain" http calls please.
With a concrete example, here is a very straightforward sample with Spring MVC, with a rest template.
...ANSWER
Answered 2021-Jun-14 at 13:54I have one big question here. While this is correct (it yields the same response) is this the correct thing to do?
Essentially, yes, you've done it correctly. The only things that aren't really correct there are your Webclient usage, and your style.
You certainly don't have to specify a WebClient per URI (and you shouldn't, they're meant to be reusable.) So if you have different domains and the same webclient, just create a standard instance:
QUESTION
I'm just starting out with JavaScript although I have used a number of other languages previously. I'm finding the orientation pretty painful and I'd appreciate some guidance on how to access child elements within a forEach loop (or a jQuery .each loop). At this stage I don't really care whether the solution is JS or jQuery, I'm just trying to get something that works.
Say I have a node element that I have found using jQuery and I now have some processing to do on each row, which includes needing to find a child-element whose id contains an index related to the parent node in question:
...ANSWER
Answered 2021-Jun-14 at 12:47Since you didn't provide us with markup I assumed your markup would look somewhat like below :
HTML
QUESTION
I have a container with IBM MQ (Docker image ibmcom/mq/9.2.2.0-r1
) exposing two ports (9443 - admin, 1414 - application).
All required setup in OpenShift is done (Pod, Service, Routes).
There are two routes, one for each port.
pointing to the ports accordingly (external ports are default http=80, https=443).
Admin console is accessible through the first route, hence, MQ is up and running.
I tried to connect as a client (JMS 2.0, com.ibm.mq.allclient:9.2.2.0
) using standard approach:
ANSWER
Answered 2021-Jun-12 at 11:32I'm not sure to fully understand your setup, but"Routes"
only route HTTP traffic (On ports 80 or 443 onyl), not TCP traffic.
If you want to access your MQ server from outside the cluster, there are a few solutions, one is to create a service of type: "NodePort"
Your Service is not a NodePort Service. In your case, it should be something like
QUESTION
Let me be straightforward in telling that it may be a bit complicated for me to explain.
Let's assume that I have a vector with run-lengths of (forward) sliding window sizes.
...ANSWER
Answered 2021-Mar-23 at 05:20An option with ugly while
loop :
QUESTION
I've been trying to adapt my code to utilize Dask to utilize multiple machines for processing. While the initial data load is not time-consuming, the subsequent processing takes roughly 12 hours on an 8-core i5. This isn't ideal and figured that using Dask to help spread the processing across machines would be beneficial. The following code works fine with the standard Pandas approach:
...ANSWER
Answered 2021-Jun-13 at 07:02Every time you call .compute()
on Dask dataframe/series, it converts it into pandas
. So what is happening in this line
artists["name"] = artists["name"].astype(str).compute()
is that you are computing the string column and then assigning pandas
series to a dask series (without ensuring alignment of partitions). The solution is to call .compute()
only on the final result, while intermediate steps can use regular pandas
syntax:
QUESTION
I bisected problem in kernel and the first bad commit is merge commit:
Parents of 2b90506a8186 (both are good):
Also v5.12-rc2 is good.
I need to do second bisect to find actual first non-merge bad commit (i.e. one of 028a1e968435..2b90506a8186 - 4885 commits or 01d713689441..2b90506a8186 - 46 commits).
I remember previously on similar case I checkouted into one of the parents (first branch) and applied one-by-one all commits from the other parent (second branch) on the top of the first branch. With this special branch, where I needed to solve few conflicts I could rebase as the history was linear.
But I don't remember how I got the list of commits from the other parent.
It was probably quite straightforward, founding it's parent with git log --first-parent
.
But for this case it I'm not able to generate the list, probably due fact that parents are also merge commits.
I tried to read various sources, but no luck:
- https://github.com/git/git/blob/master/Documentation/howto/revert-a-faulty-merge.txt
- https://github.com/git/git/blob/master/Documentation/git-bisect.txt
- https://github.com/git/git/blob/master/Documentation/git-bisect-lk2009.txt
- https://github.com/git/git/blob/master/Documentation/howto/revert-a-faulty-merge.txt
UPDATE I don't believe there is kernel regression for all devices, just problem with device tree for my particular arm64 device. Finding a problematic commit can help me to temporarily revert problematic commit until I find what needs to be fixed in device tree for my device.
...ANSWER
Answered 2021-Jun-12 at 22:41Parents of 2b90506a8186 (both are good): […] I need to do second bisect to find actual first non-merge bad commit
You know merging 2b90506^2 produces a kernel that won't boot on your rig, so that commit has the bug that will show up in integration: it's bad.
QUESTION
ANSWER
Answered 2021-Jun-10 at 22:23You first create a dataframe where you have min and max for each combination of (xcat, base and col)
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