Diagon | star2 | Graphics library

 by   ArthurSonzogni C++ Version: v1.1.158 License: MIT

kandi X-RAY | Diagon Summary

kandi X-RAY | Diagon Summary

Diagon is a C++ library typically used in User Interface, Graphics applications. Diagon has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Diagon is an interactive interpreter. It transforms markdown-style expression into an ascii-art representation. It is written in C++ and use WebAssembly, HTML and CSS to make a Web Application.
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              Diagon has a medium active ecosystem.
              It has 1193 star(s) with 50 fork(s). There are 13 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 15 open issues and 20 have been closed. On average issues are closed in 66 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Diagon is v1.1.158

            kandi-Quality Quality

              Diagon has no bugs reported.

            kandi-Security Security

              Diagon has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Diagon is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Diagon releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            Diagon Key Features

            No Key Features are available at this moment for Diagon.

            Diagon Examples and Code Snippets

            No Code Snippets are available at this moment for Diagon.

            Community Discussions

            QUESTION

            Unity2D stacking movement commands
            Asked 2021-Jun-15 at 07:04
            if(CanUp){
                if(Input.GetKey(KeyCode.W)){
                    rb.MovePosition(rb.position + Vector2.up * speed * Time.fixedDeltaTime);
                    if(Input.GetKeyDown(KeyCode.D)){
                        CanUp = false;
                        CanRight = true;
                    }
                }else{
                 CanRight = true;
                }                  
            }
            
            if(CanRight){
                if(Input.GetKey(KeyCode.D)){
                    rb.MovePosition(rb.position + Vector2.right * speed * Time.fixedDeltaTime);
                    if(Input.GetKeyDown(KeyCode.W)){
                        CanUp = true;
                        CanRight = false;
                     }
                }else{
                    CanUp = true;
                }
            }
            
            
            ...

            ANSWER

            Answered 2021-Jun-10 at 10:41

            Generally, you want to reduce cyclomatic complexity to make debugging and figuring out logic easier. Cyclomatic complexity can usually be identified by having a number of if statements nested inside each other. Try:

            Source https://stackoverflow.com/questions/67916530

            QUESTION

            Why getBoundingClientRect returns zero coordinates?
            Asked 2021-Jun-14 at 10:54

            There is a function that returns getBoundingClientRect of HTML element:

            ...

            ANSWER

            Answered 2021-Jun-13 at 16:54

            You seem to use: svg.querySelector("#r12"); to access to your path property.

            According to MDN, the command is: document.querySelector("#r12"); (https://developer.mozilla.org/en-US/docs/Web/API/Document/querySelector)

            Source https://stackoverflow.com/questions/67960552

            QUESTION

            Symmetric 2D array of random numbers
            Asked 2021-Jun-14 at 07:34
            public static int[][] Matrix(int n, int max, int min) {
                int[][] grid = new int[3][3];
                Random rand = new Random();
            
                rand.setSeed(System.currentTimeMillis());
            
                for (int i = 0; i < n; i++) {
                    for (int j = 0; j < i; j++) {
                        int value = Math.abs((min + rand.nextInt((max - min) + 1)));
                        grid[i][j] = value;
                        grid[j][i] = value;
                    }
                }
                return grid;
            }
            
            ...

            ANSWER

            Answered 2021-Jan-14 at 21:36

            You are generating random value for all i and j except when i==j, which are the diagonal values. Also, all the values of the diagonals will be same. So before returning the grid, you can generate one last random value and put it to the diagonals. Something like this

            Source https://stackoverflow.com/questions/65726989

            QUESTION

            How to solve the given task using BFS algorithm?
            Asked 2021-Jun-13 at 22:55

            Is there any better or simpler solution for this task:

            "A matrix of dimensions MxN is given, filled with the numbers 0 and 1. The field on which the number 0 is written represents land, and the field on which it is written number 1 represents water. Write a function largestLake(int [] [] map) which calculates the size of the largest water surface in the matrix map. The size of a water surface is the number of fields of value 1 that that water surface contains. Two water cells are considered connected if they are adjacent horizontally, vertically or diagonally." ?

            Example:
            Input:
            4 5 //MxN
            0 0 1 1 0
            1 0 1 1 0
            0 1 0 0 0
            0 0 0 1 1
            Output:
            6

            I tried to find it with BFS algorithm, but it ended up with too many loops. It says in the task that "The best solution has complexity O (M * N)."

            I loaded matrix in main and here is my function:

            ...

            ANSWER

            Answered 2021-Jun-13 at 22:55

            QUESTION

            How can I visualize what the loop is doing when traversing through a 2D array?
            Asked 2021-Jun-12 at 22:08

            Consider this code:

            ...

            ANSWER

            Answered 2021-Mar-12 at 12:54

            Try not not imagine as "array traversing", but follow what does the for loop actually do: You declare a variable i and increment it after every iteration and using it to access the arrays. For the outer array, you say "give me first, second, third, ... element" (a[i]). That's equivalent to for each in lists - you go over all elements of the outer array. But on the result (inner array), you access ith element again (a[i][i]) - which means that you're not iterating over every element of the inner array, but just one - first element of the first array, second element of the second array etc.

            Source https://stackoverflow.com/questions/66600170

            QUESTION

            How to remove mutability from this function in scheme (N-queens)
            Asked 2021-Jun-12 at 19:59

            I'm arduously struggling my way through the N-queens problem in SICP (the book; I spent a few days on it -- last question here: Solving Eight-queens in scheme). Here is what I have for the helper functions:

            ...

            ANSWER

            Answered 2021-Jun-12 at 09:35

            When you are doing the SICP problems, it would be most beneficial if you strive to adhere to the spirit of the question. You can determine the spirit from the context: the topics covered till the point you are in the book, any helper code given, the terminology used etc. Specifically, avoid using parts of the scheme language that have not yet been introduced; the focus is not on whether you can solve the problem, it is on how you solve it. If you have been provided helper code, try to use it to the extent you can.

            SICP has a way of building complexity; it does not introduce a concept unless it has presented enough motivation and justification for it. The underlying theme of the book is simplification through abstraction, and in this particular section you are introduced to various higher order procedures -- abstractions like accumulate, map, filter, flatmap which operate on sequences/lists, to make your code more structured, compact and ultimately easier to reason about.

            As illustrated in the opening of this section, you could very well avoid the use of such higher programming constructs and still have programs that run fine, but their (liberal) use results in more structured, readable, top-down style code. It draws parallels from the design of signal processing systems, and shows how we can take inspiration from it to add structure to our code: using procedures like map, filter etc. compartmentalize our code's logic, not only making it look more hygienic but also more comprehensible.

            If you prematurely use techniques which don't come until later in the book, you will be missing out on many key learnings which the authors intend for you from the present section. You need to shed the urge to think in an imperative way. Using set! is not a good way to do things in scheme, until it is. SICP forces you down a 'difficult' path by making you think in a functional manner for a reason -- it is for making your thinking (and code) elegant and 'clean'.

            Just imagine how much more difficult it would be to reason about code which generates a tree recursive process, wherein each (child) function call is mutating the parameters of the function. Also, as I mentioned in the comments, assignment places additional burden upon the programmers (and on those who read their code) by making the order of the expressions have a bearing on the results of the computation, so it is harder to verify that the code does what is intended.

            Edit: I just wanted to add a couple of points which I feel would add a bit more insight:

            1. Your code using set! is not wrong (or even very inelegant), it is just that in doing so, you are being very explicit in telling what you are doing. Iteration also reduces the elegance a bit in addition to being bottom up -- it is generally harder to think bottom up.
            2. I feel that teaching to do things recursively where possible is one of the aims of the book. You will find that recursion is a crucial technique, the use of which is inevitable throughout the book. For instance, in chapter 4, you will be writing evaluators (interpreters) where the authors evaluate the expressions recursively. Even much earlier, in section 2.3, there is the symbolic differentiation problem which is also an exercise in recursive evaluation of expressions. So even though you solved the problem imperatively (using set!, begin) and bottom-up iteration the first time, it is not the right way, as far as the problem statement is concerned.

            Having said all this, here is my code for this problem (for all the structure and readability imparted by FP, comments are still indispensable):

            Source https://stackoverflow.com/questions/67912848

            QUESTION

            How to simplify the code by using a loop?
            Asked 2021-Jun-12 at 10:36

            I should find a method to determine if a word appears in a 2D array diagonally (from top left to bottom right). My method: static boolean findText (...) works in this case because LEGO has 4 letters but of course that's not how you want it to look like and it should be also be able to work for longer and shorter words. How can I do a loop that repeats the if (texts[k][i] == searchText[k]) as often as the searchText is long (so basically searchText.length)? Without messing up the other loop that works perfectly fine at the moment.

            ...

            ANSWER

            Answered 2021-Jun-08 at 17:06

            If you didn't have {null} as a possible entry in your multi-dimensional array then, this would be a simple solution

            However, because I guess null is a possible entry then, you would need a way to check the value of each entry before iterating over it. For instance, texts[i].length would crash when it reaches the null value.

            EDIT: Because {null} are possible entries, I have just added simple if statement before entering the 2nd loop. This should work for searching diagonally left top down, I believe.

            EDIT: Had to add another small null check in the 1st if of the 3rd loop.

            Source https://stackoverflow.com/questions/67521499

            QUESTION

            KeyBinding multiple keys pressed not working
            Asked 2021-Jun-11 at 22:43

            So I have a painted rectangle that I want to move with the arrow keys that includes diagonal movement, or rather allowance of multiple keys being pressed at the same time (In other words, movement that is similar to player movement in a 2D game). I have attempted to do this with a KeyListener, which was not working. So I decided to move to KeyBindings and I found an example from this website: https://coderanch.com/t/606742/java/key-bindings (Rob Camick's post)

            I directly copied the code and it works as intended, except it is moving an icon and not a painted rectangle like I want to do. I have attempted to modify the code so that it would move a painted rectangle, but was only failing. Here is my latest attempt, which is also a minimal reproducible:

            ...

            ANSWER

            Answered 2021-Jun-11 at 22:43

            Okay, so one of the issues I have with the code you've presented is the fact that you're leak responsibility. It's not the responsibility of the NavigationAction to register key bindings or modify the state the of UI. It should only be responsible for generating a notification that the state has changed back to a responsible handler.

            This could be achieved through the use of some kind of model, which maintains the some kind of state, which is updated by the NavigationAction and read by the UI or, as I've chosen to do, via a delegation callback.

            Another issue is, what happens when the user releases the key? Another issue is, how do you deal with the delay in repeated key press (ie when you hold the key down, there is a small delay between the first key event and the repeating key events)?

            We can deal with these things through a simple change in mind set. Instead of using the NavigationAction to determine "what" should happen, it should be used to tell our UI "when" something has happened. In this a directional key has been pressed or released.

            Instead of reacting to key stroke directly, we either "add" or "remove" the direction from a state model and allow the Swing Timer to update the state of the UI accordingly, this will generally be faster and smoother.

            It also has the side effect of decoupling logic, as you no longer need to care about "how" the state was changed, only that it was and you can then decide how you want to react to it.

            This approach is generally commonly used (in some form or another) in gaming engines.

            Source https://stackoverflow.com/questions/67154074

            QUESTION

            Resizable diagonal line in a div with css
            Asked 2021-Jun-10 at 12:59

            I need help with a rectangular div whose diagonal length in increased or decreased using js. I want to insert a line in diagonal to label diagonal length as diagonal is minimized or maximized using the +/- buttons.

            I want the line to resize automatically without loosing quality. I want to keep the background color green and the image and label color to be white. For that i want to use css to draw line instead of a image. I have attached image of how div should looks like.

            Thanks alot for the support.

            Div Demo Image

            ...

            ANSWER

            Answered 2021-Jun-10 at 12:59

            You can use another div with a position:absolute

            Source https://stackoverflow.com/questions/67920636

            QUESTION

            Calculation of the first and third quartile
            Asked 2021-Jun-09 at 14:05

            I'm trying to calculate the mean, standard deviation, median, first quartile and third quartile of the lognormal distribution that I fit to my histogram. So far I've only been able to calculate the mean, standard deviation and median, based on the formulas I found on Wikipedia, but I don't know how to calculate the first quartile and the third quartile. How could I calculate in Python the first quartile and the third quartile, based on the lognormal distribution?

            ...

            ANSWER

            Answered 2021-Jun-08 at 20:07

            Given a log-normal distribution, we want to compute its quantiles. Furthermore, the parameters of the log-normal distribution are estimated from data.

            The script below uses OpenTURNS to create the distribution using the LogNormal class. It takes as inputs arguments the mean and standard deviation of the underlying normal distribution. Then we can use the computeQuantile()method to compute the quantiles.

            Source https://stackoverflow.com/questions/67886115

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

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            You can download it from GitHub.

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