sansa | Structural variant annotation | Genomics library

 by   dellytools C++ Version: v0.0.8 License: BSD-3-Clause

kandi X-RAY | sansa Summary

kandi X-RAY | sansa Summary

sansa is a C++ library typically used in Artificial Intelligence, Genomics applications. sansa has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Structural variant (SV) annotation.
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            kandi-support Support

              sansa has a low active ecosystem.
              It has 7 star(s) with 0 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 2 have been closed. On average issues are closed in 6 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of sansa is v0.0.8

            kandi-Quality Quality

              sansa has no bugs reported.

            kandi-Security Security

              sansa has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              sansa is licensed under the BSD-3-Clause License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              sansa releases are available to install and integrate.
              Installation instructions are available. Examples and code snippets are not available.

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            sansa Key Features

            No Key Features are available at this moment for sansa.

            sansa Examples and Code Snippets

            No Code Snippets are available at this moment for sansa.

            Community Discussions

            QUESTION

            How can I exchange ids with names in comma data in oracle
            Asked 2021-Jun-15 at 13:33

            I have a table like below which has names and ids.

            ID Name 1 Robb 2 Sansa 3 Arya 4 Bran 5 Rickon 6 Cersei 7 Jaime 8 Tyrion

            And there is another table like below

            Family Name brothers sisters Stark 1,4,5 2,3 Lennister 7,8 6

            I need a query which will give brothers' name for stark family in one row with separate by comma

            Family Name brothers sisters Stark Robb,Bran,Rickon Sansa,Arya

            Thank you for help

            ...

            ANSWER

            Answered 2021-Jun-15 at 13:33

            You can use correlated sub-queries and check whether the id column is a substring of the brothers or sisters and then use LISTAGG to aggregate the matched names.

            Assuming that you want the name to be in the same order as the id are in the brothers or sisters lists then you could use:

            Source https://stackoverflow.com/questions/67986594

            QUESTION

            Suggest friends of friends in a stored procedure in MySQL
            Asked 2021-Mar-16 at 11:20

            I'm trying to write a stored procedure to suggest new friends to a user that is specified in a call statement while excluding the users current friends and limiting the result to three suggestions.

            These are my two tables:

            ...

            ANSWER

            Answered 2021-Mar-16 at 11:20

            Try this. I tested it.

            Source https://stackoverflow.com/questions/66652984

            QUESTION

            Function only printing last 2 key:value pairs of dictionary
            Asked 2021-Mar-09 at 17:00

            I'm creating a function that takes a dictionary as a parameter. The dictionary is made up of a key which is a last name and a value is a list of first names.

            The function should return a new dictionary where each key is the first letter of the key in the parameter, and the value is the number of items in the value of the parameter

            Example

            ...

            ANSWER

            Answered 2021-Mar-09 at 16:53

            Because 2 of your last names start with same letter: Stark, Snow. Thus, overwriting each other as dictionary keys are unique.

            Source https://stackoverflow.com/questions/66551242

            QUESTION

            Nette - database INSERT - number of affected rows
            Asked 2020-Nov-27 at 10:06

            I would like to find out the number of affected (inserted) rows after inserting into the table. I didn't figure out how to do it in the documentation. The update returns the number of affected rows. The insert returns Nette\Database\Table\ActiveRow How do I get it?

            ...

            ANSWER

            Answered 2020-Nov-27 at 10:06

            Nette Database Explorer doesn't return count after insert(). It is not useful information as long as you can count data before insert by yourself.

            Source https://stackoverflow.com/questions/65035317

            QUESTION

            How come Arrays.sort(stringArray, String::compareToIgnoreCase) is using compareToIgnoreCase() instead of Comparator
            Asked 2020-Sep-21 at 02:35

            Need some clarification on how Arrays.sort(stringArray, String::compareToIgnoreCase) is using
            compareTo() whose return type is String and not Comparator which takes two arguements.

            ...

            ANSWER

            Answered 2020-Sep-21 at 02:35

            A Comparator is a functional interface that takes two String parameters and returns an int. Where such a Comparator is required, a lambda with the same characteristics can be used instead.

            The compareToIgnoreCase method has the same characteristics, where the first parameter is the object that the method is called on, and the second parameter is the parameter to the method. The method returns an int (not a String). So it has the form of a Comparator.

            Because of all this, and the way functional interfaces work, one can supply a Comparator object to Arrays.sort via a lambda expression that utilizes compareToIgnoreCase, like this:

            Source https://stackoverflow.com/questions/63984937

            QUESTION

            What will be the output of following and why?
            Asked 2020-Aug-13 at 21:28

            What will the following output and why

            let user = "Brienne of Tarth"; "Sansa Stark"; "Lyanna Mormont"; chrome print last one & when I access user it show the first one. why it happens

            ...

            ANSWER

            Answered 2020-Aug-13 at 21:28

            In a typical REPL (read-eval-print loop) the thing that gets printed is simply whatever the last statement executed evaluated to. You have three statements:

            Source https://stackoverflow.com/questions/63403383

            QUESTION

            Merge 2 objects of objects
            Asked 2020-Aug-07 at 23:11

            I need to merge 2 objects of objects. I have tried both the spread operator and Object.assign. But my end result still is showing just the results of the second objects.

            ...

            ANSWER

            Answered 2020-Aug-07 at 22:59

            Is this what you're going for?:

            Source https://stackoverflow.com/questions/63309980

            QUESTION

            Javascript re-order array of object by value
            Asked 2020-Jul-22 at 03:17

            How do I re-order array of object showing below by follow value. If follow value is not -1, move the item below to the item that has the id value same as follow value.

            Here is the example.

            ...

            ANSWER

            Answered 2020-Jul-22 at 03:17

            I think this will do what you're asking. I'm sure it could be made more efficient, but unless your list gets quite large that shouldn't make much practical difference. Also, this assumes any character will only have one follower. If that's not the rule, then the function will have to be adjusted.

            Source https://stackoverflow.com/questions/63025402

            QUESTION

            SPARQL column headings with different name
            Asked 2020-Jul-07 at 16:02

            I am new to SANSA-STACK and I am using SPARQL Query to perform some operations on Triples RDD , I am using Select with some column names, but when I am completing the query, the column names are getting changed to some random values.

            ...

            ANSWER

            Answered 2020-Jul-07 at 16:02

            Here is a temporary solution that works for my purposes that returns a dataframe with the expected column names. By decomposing rdd.sparql, the rewrite object can be used to obtain the column mappings: https://gist.github.com/JNKHunter/c16caa882993facb31a273ec274cb8e3

            Warning: Sansa query often returns more than one column for each sparql selected element. In those cases this code simply concatenates those columns since columns after the first tend to contain empty strings. Concatenation may not be what you want, however I've yet to discover what those empty string dataframe columns represent.

            Source https://stackoverflow.com/questions/62118243

            QUESTION

            About reduce() method importing in python 3.6
            Asked 2020-Apr-03 at 07:44

            Importing

            ...

            ANSWER

            Answered 2020-Apr-03 at 07:44

            As given in the question comments, to import a class/function from a module, the syntax is:

            Source https://stackoverflow.com/questions/60925042

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sansa

            The easiest way to get sansa is to download a statically linked binary from the sansa github release page or using bioconda. You can also build sansa from source using a recursive clone and make.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
          • HTTPS

            https://github.com/dellytools/sansa.git

          • CLI

            gh repo clone dellytools/sansa

          • sshUrl

            git@github.com:dellytools/sansa.git

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