LintCode | π C++11 Solutions of All 289 LintCode Problems ( No More | Learning library
kandi X-RAY | LintCode Summary
kandi X-RAY | LintCode Summary
Up to date (2016-08-22), there are 289 problems on LintCode Online Judge. The number of problems is increasing recently. Here is the classification of all 289 problems. For more problems and solutions, you can see my LeetCode-Solutions repository. I'll keep updating for full summary and better solutions. Stay tuned for updates.
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QUESTION
I am trying to solve this problem. http://www.lintcode.com/en/problem/coin-change-ii/#
This is the standard coin change problem solvable with dynamic programming. The goal is to find the number of ways to create an amount using an infinite set of coins, where each has a certain value. I have created the following solution :
...ANSWER
Answered 2017-Dec-28 at 20:08Let's consider the loop that works first:
QUESTION
So, I'm doing a problem called "Unique Paths II" in lintcode. However, I encountered a runtime error during a testcase:
...ANSWER
Answered 2019-Sep-12 at 16:13Regardless of the error you should read Why is βusing namespace std;β considered bad practice? and enable compiler warnings. In your code are many
QUESTION
So, I was coding a problem on lintcode (number 69). I decided to use dfs using a traditional array as a queue. However, it returned -1 at the commented line, which lintcode says is a segmentation fault with the given input. Here is my code.
...ANSWER
Answered 2019-Jul-17 at 09:16These two lines are a likely culprit:
QUESTION
I am simulating code to erase all zero at the beginning of a string.
...ANSWER
Answered 2018-Jun-02 at 11:08As eraseZero
is a part of class Solution
and not globally defined, you should use the instance, self
in this case, of that class to call it, whether you call it inside or outside the class.
QUESTION
I'm trying to write a program to check if a Tree T2 is a subtree present in Tree T1. I'm using a traversal by storing the state of the tree into a string and checking if T2's substring is a substring present in T1's substring. For some reason, my code fails if I do an in-order in the traverse method to generate a string to hold the representation for the binary tree. Why does this happen? It works fine doing a Post-Order. This is the input case my program fails on:
{9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9} {9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9}
The binary tree representation format can be found http://www.lintcode.com/help/binary-tree-representation/
...ANSWER
Answered 2017-Dec-10 at 17:31The recursive algorithm you implemented does not provide the serialization of a tree in the desired order. Imagine how it works. All the items of the left subtree will always precede any of the items of the right subtree, since the right subtree will always be processed after the left subtree is finished. In the form that is described at the page you mentioned, al the items of a certain level should follow each other, and the items of the next level should be processed after all the items of the given level are done. To write trees in the described order you need a more complicated algorithm.
And furtermore, the described way to represent a tree as a string does not allow to search for subtrees by simply searching substrings. Consider the follwing tree:
QUESTION
Scenario:
I'm trying to solve one question on LintCode, "Longest Consecutive Sequence", where given an unsorted array of integers, find the length of the longest consecutive elements sequence.
Link to the original question: https://www.lintcode.com/en/problem/longest-consecutive-sequence/
So here is my intuitive solution:
...ANSWER
Answered 2017-Feb-06 at 20:21The Time complexity is worst case complexity. So it looks like O(n^2), with n= num of elements in the set.
In fact:
QUESTION
I built a data structure for two sum question. In this data structure I built add and find method.
add - Add the number to an internal data structure.
find - Find if there exists any pair of numbers which sum is equal to the value.
For example:
ANSWER
Answered 2017-Feb-22 at 22:51There does not seem to be anything wrong with your code.
However a coding challenge could possibly require a more performant solution. (You check every item against every item, which would take O(N^2)).
The best solution to implement find
, is using a HashMap
, which would take O(N). It's explained more in detail here.
QUESTION
Edit:
The function is part of an answer to lintcode question "combination sum", if I use the second version, the output is "[[],...,[]], where all inner list is empty, even when they are passed in with values. When I just switch to the first version without changing anything else, it would work.
So I assume it has something to with the Java parameter-passing process that I don't understand. Could you please explain why only the first version can work?
Code:
...ANSWER
Answered 2017-Feb-15 at 21:04Eventually, they're doing the same thing, however, the only difference I can notice is the first one uses more memory and there is no need to actually construct a new ArrayList of an already existing one.
QUESTION
If waitFor
is not used, killing JVM has no effect on its child process. Here is an example.
Bash script:
...ANSWER
Answered 2017-Feb-10 at 10:42There's nothing special about waitPid()
, other than the fact that you keep the parent process in the foreground.
If you fork and then wait for the child to finish, you have a (simplified) process tree like this:
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