interviews | Everything you need to know to get the job | Learning library

 by   kdn251 Java Version: Current License: MIT

kandi X-RAY | interviews Summary

kandi X-RAY | interviews Summary

interviews is a Java library typically used in Tutorial, Learning, Example Codes, LeetCode applications. interviews has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. However interviews build file is not available. You can download it from GitHub.

Your personal guide to Software Engineering technical interviews. Video solutions to the following interview problems with detailed explanations can be found here. Maintainer - Kevin Naughton Jr.

            kandi-support Support

              interviews has a medium active ecosystem.
              It has 59966 star(s) with 12594 fork(s). There are 2608 watchers for this library.
              It had no major release in the last 6 months.
              There are 31 open issues and 21 have been closed. On average issues are closed in 33 days. There are 82 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of interviews is current.

            kandi-Quality Quality

              interviews has 0 bugs and 0 code smells.

            kandi-Security Security

              interviews has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              interviews code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              interviews is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              interviews releases are not available. You will need to build from source code and install.
              interviews has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              interviews saves you 5461 person hours of effort in developing the same functionality from scratch.
              It has 11447 lines of code, 777 functions and 516 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed interviews and discovered the below as its top functions. This is intended to give you an instant insight into interviews implemented functionality, and help decide if they suit your requirements.
            • Decodes a string .
            • Returns the minimal window .
            • Get the vertical order of the node in the tree
            • Generate matrix .
            • Returns a list of integers .
            • Returns the level order in the tree rooted at the tree
            • Merge k lists .
            • Group an array of Strings
            • Determine how many substrings are unique
            • Return the minimum cost of an array of costs .
            Get all kandi verified functions for this library.

            interviews Key Features

            No Key Features are available at this moment for interviews.

            interviews Examples and Code Snippets

            Function used to perform the operation .
            javascriptdot img1Lines of Code : 21dot img1no licencesLicense : No License
            copy iconCopy
            function performOperation(secondInteger, secondDecimal, secondString) {
                // Declare a variable named 'firstInteger' and initialize with integer value 4.
                const firstInteger = 4;
                // Declare a variable named 'firstDecimal' and initialize wit  
            Helper function for reverseIndex .
            javascriptdot img2Lines of Code : 13dot img2no licencesLicense : No License
            copy iconCopy
            function reverseStringHalfIndex(str) {
              let strArr = str.split('');
              let len = strArr.length;
              let halfIndex = Math.floor(len / 2) - 1;
              let tmp = [];
              for (var i = 0; i <= halfIndex; i++) {
                tmp = strArr[len - i - 1];
                strArr[len - i   
            Reverse an array
            javascriptdot img3Lines of Code : 8dot img3no licencesLicense : No License
            copy iconCopy
            function inPlaceReverse(arr) {
                var i = 0;
                while (i < arr.length - 1 ) {
                  arr.splice(i, 0, arr.pop());
                return arr;

            Community Discussions


            How to find most common words from specific rows and column and list how often it occurs at data.csv?
            Asked 2022-Mar-03 at 20:14

            I want to get 20 most common words from the descriptions of top 10 longest movies from data.csv, by using Python. So far, I got top 10 longest movies, however I am unable to get most common words from those specific movies, my code just gives most common words from whole data.csv itself. I tried Counter, Pandas, Numpy, Mathlib, but I have no idea how to make Python look exactly for most common words in the specific rows and column (description of movies) of the data table

            My code:



            Answered 2022-Mar-03 at 20:05

            You can select the first 10 rows of your dataframe with iloc[0:10].

            In this case, the solution would look like this, with the least modification to your existing code:



            How to calculate cumulative sums in MySQL
            Asked 2022-Feb-21 at 07:02

            I am preparing for interviews and came across this question while practicing some SQL questions recently asked in Amazon. I could not find the table though, but the question is as follows:

            Find the cumulative sum of the top 10 most profitable products of the last 6 months for customers in Seattle.

            Does the approach to solving this type of query look correct? If not, what would be the best way to approach this problem?



            Answered 2022-Feb-21 at 07:02


            css grid relayout if element changes height
            Asked 2022-Jan-21 at 17:51

            I have a css grid layout that looks like this,

            When a box is clicked is grows in height to show information about the service. What I was hoping to be able to do was the "relayout" the grid so grid wrapped around the tallest item? Instead what I have is when I an item grows that row and it's children grow with it.

            What I was hoping for was if report writing was clicked it would grow and take up benchmarking space, benchmarking would move left and consultancy would wrap onto a new line?

            I am using tailwind so my HTML looks like this,



            Answered 2022-Jan-21 at 17:51

            A couple of things.

            You can make the clicked item span two rows by setting grid-row: span 2 This will have the effect of 'pushing' other grid items around.

            In the JS you had a call to remove which I think should have been removeClass

            Here's a (slightly messy) SO snippet created from your codepen:



            Is it acceptable to pass this amount of JSON information as a parameter to a C# COM DLL method?
            Asked 2022-Jan-21 at 05:06

            This question is an extension to this one (Is there a technical reason why it would be better for the COM DLL to delete the passed in temporary JSON when it is finished with it?) where it was suggested I pass JSON content as a BSTR to my C# COM DLL.

            Here is an example of the type of data being passed:



            Answered 2022-Jan-21 at 05:06

            You could always write a test program if you don't know the answer. Here's one that verifies 1 megabyte BSTR which is way more than your example. You could change the amount allocated to whatever you want. At some point it will break.



            matrix maximum diagonal pattern match
            Asked 2022-Jan-16 at 03:00

            I came across a problem while doing technical interviews for matrix pattern matching. I was able to solve the problem using brute force but wonder if there is a more efficient solution as I only got about half credit for efficiency. Thank you in advanced for your input.

            Given a matrix containing the numbers 0, 1, 2 and the pattern [1, 2, 0, 2, 0, 2, 0] find the max length of the matching pattern starting from any point in the matrix but can only travel diagonally.

            here is an example of where we would expect the function to return 12.

            here is where we would expect the function to return 7.

            and empty matrix should return 0.

            Here is my code, like I said previously it does work and passed all the tests but I got docked points.



            Answered 2022-Jan-15 at 22:48

            Building on the accept answer to this question. It's based on a few key ideas:

            You can use np.diagonal over a range to slice every possible diagonal out of the array. You can flip the array around to make sure you get all angles.

            You can tile the pattern to make sure it's at least as long or longer than the largest diagonal.

            You can zip the diagonal and the pattern and the extra values in the pattern will be dropped automatically due to the way zip works.

            Then you can use takewhile on the zipped (diag,pattern) to check how many consecutive matches there are len(set(x))==1.

            If you do this for all the possible combinations and take the max, you should have your answer.



            Cleaner/Simpler way to check if content in array has a value greater than 0
            Asked 2021-Dec-23 at 20:57

            I have this array that combines different data and then if the array contains true, then I'm showing some text. So for example, even if video is the only one that has a length greater than 0 (true), and the rest are false, the text 'Click to go to list' will be still shown. Is there a clean/simplier way of doing this check?



            Answered 2021-Dec-23 at 20:38

            You can check to see if atleast one length property in the array is truthy



            How to combine columns, group them then get a total count?
            Asked 2021-Dec-08 at 21:09

            Below is a table that has candidate_id, two interviews they attended with the interviewer's name, and results for each interview.

            candidate_id interview_1 interview_2 result_1 result_2 1 Interviewer_A Interviewer_B Pass Pass 2 Interviewer_C Interviewer_D Pass Reject

            I need help to combine column interview_1 and interview_2 into one column, and count how many pass and reject each interviewer gave to the candidate, the result I expected to see as below:

            interviewer_name pass_count reject_count Interviewer_A 1 0 Interviewer_B 1 0 Interviewer_C 1 0 Interviewer_D 0 1

            SQL or Python either would work for me! Much appreciated!



            Answered 2021-Dec-08 at 21:00

            In SQL Server, it becomes a small matter for a CROSS APPLY




            formulate capture groups for inconsistently present substrings
            Asked 2021-Nov-27 at 15:09

            I have transcriptions of interviews that are partly irregularly formed:



            Answered 2021-Nov-27 at 13:41

            You could update your pattern to use your 4 capture groups, and make the last part optional by optionally matching the 3rd group and then the 4th group and assert the end of the string:



            SQL Query to find people who have interviews in different rooms inany days
            Asked 2021-Nov-25 at 11:12
            Name Date Room Jerry 2-2-21 D Sam 2-2-21 A Sarah 2-2-21 A Will 3-2-21 B Sam 4-3-21 D Will 2-2-21 B Jerry 2-2-21 D

            Hello, (apologies for my bad English) I made the previous table I'm a new at SQL and wondering to how can I make a query that will return the names of the people who had interviews in different rooms regardless of the day so will would not come up since he had interviews in the same rooms

            my approach



            Answered 2021-Nov-24 at 13:22

            In addition to @Beso answer I would also use DISTINCT in COUNT to be sure there are different rooms.



            Complexity analysis for the permutations algorithm
            Asked 2021-Nov-14 at 15:07

            I'm trying to understand the time and space complexity of an algorithm for generating an array's permutations. Given a partially built permutation where k out of n elements are already selected, the algorithm selects element k+1 from the remaining n-k elements and calls itself to select the remaining n-k-1 elements:



            Answered 2021-Nov-14 at 15:07

            The time complexity of this algorithm, counted by the number of basic operations performed, is Θ(n * n!). Think about the size of the result list when the algorithm terminates-- it contains n! permutations, each of length n, and we cannot create a list with n * n! total elements in less than that amount of time. The space complexity is the same, since the recursion stack only ever has O(n) calls at a time, so the size of the output list dominates the space complexity.

            If you count only the number of recursive calls to permutations(), the function is called O(n!) times, although this is usually not what is meant by 'time complexity' without further specification. In other words, you can generate all permutations in O(n!) time, as long as you don't read or write those permutations after they are generated.

            The part where your derivation of run-time breaks down is in the definition of T(n). If you define T(n) as 'the run-time of permutations(A, start) when the input, A, has length n', then you can not define it recursively in terms of T(n-1) or any other function of T(), because the length of the input in all recursive calls is n, the length of A.

            A more useful way to define T(n) is by specifying it as the run-time of permutations(A', start), when A' is any permutation of a fixed, initial array A, and A.length - start == n. It's easy to write the recurrence relation here:


            Community Discussions, Code Snippets contain sources that include Stack Exchange Network


            No vulnerabilities reported

            Install interviews

            You can download it from GitHub.
            You can use interviews like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the interviews component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer For Gradle installation, please refer .


            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
          • HTTPS


          • CLI

            gh repo clone kdn251/interviews

          • sshUrl


          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link