Learning-Algorithms | 互联网公司面试真题 LeetCode or hackerrank 算法与数据结构 | Learning library

 by   liuawen C++ Version: Current License: No License

kandi X-RAY | Learning-Algorithms Summary

kandi X-RAY | Learning-Algorithms Summary

Learning-Algorithms is a C++ library typically used in Tutorial, Learning, Example Codes, LeetCode applications. Learning-Algorithms has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

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              Learning-Algorithms has a low active ecosystem.
              It has 7 star(s) with 2 fork(s). There are 3 watchers for this library.
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              It had no major release in the last 6 months.
              Learning-Algorithms has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Learning-Algorithms is current.

            kandi-Quality Quality

              Learning-Algorithms has no bugs reported.

            kandi-Security Security

              Learning-Algorithms has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Learning-Algorithms does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

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              Learning-Algorithms releases are not available. You will need to build from source code and install.

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            Learning-Algorithms Key Features

            No Key Features are available at this moment for Learning-Algorithms.

            Learning-Algorithms Examples and Code Snippets

            Add two lists .
            pythondot img1Lines of Code : 28dot img1License : Permissive (MIT License)
            copy iconCopy
            def add_two_numbers(l1, l2):
                start = ListNode(None)
                # use the same linked list as result so the Space complexity will be O(1)
                start.next = l1
                pointer = start
                transfer = 0
            
                while (l1 is not None) or (l2 is not None) or (transfe  
            Find the index of the subarray in arr .
            pythondot img2Lines of Code : 22dot img2License : Permissive (MIT License)
            copy iconCopy
            def find_subarray(arr, k):
                n = len(arr)
            
                if n == 0:
                    return -1
            
                start = 0
                end = 0
                current_sum = arr[0]
            
                while end < n:
                    if current_sum == k:
                        return (start + 1, end + 1)
            
                    if current_sum <  
            Removes n elements from pointer .
            pythondot img3Lines of Code : 11dot img3License : Permissive (MIT License)
            copy iconCopy
            def remove_recursively(pointer, n):
                if pointer is None:
                    return (0, None)
            
                # go to the end and count how many are there
                result = remove_recursively(pointer.next, n)
            
                if result[0] == n:
                    pointer.next = result[1]
            
                retu  

            Community Discussions

            QUESTION

            How to calculate 95% CI for accuracy and kappa in caret
            Asked 2021-Mar-05 at 10:44

            I am running k-fold repeated training with the caret package and would like to calculate the confidence interval for my accuracy metrics. This tutorial prints a caret training object that shows accuracy/kappa metrics and associated SD: https://machinelearningmastery.com/tune-machine-learning-algorithms-in-r/. However, when I do this, all that is listed are the metric average values.

            ...

            ANSWER

            Answered 2021-Mar-01 at 07:44

            It looks like it is stored in the results variable of the resultant object.

            Source https://stackoverflow.com/questions/66416014

            QUESTION

            Image semantic segmentation of repeating patterns without CNNs
            Asked 2019-Nov-03 at 20:09

            Suppose I have one or multiple tiles consisting of a single pattern (e.g. materials like: wood, concrete, gravel...) that I would like to train my classifier on, and then I'll use the trained classifier to determine to which class each pixel in another image belong.

            Below are example of two tiles I would like to train the classifier on:

            And let's say I want to segment the image below to identify the pixels belonging to the door and those belonging to the wall. It's just an example, I know this image isn't made of exactly the same patterns as the tiles above:

            For this specific problem, is it necessary to use convolutional neural networks? Or is there a way to achieve my goal with a shallow neural network or any other classifier, combined with texture features for example?

            I've already implemented a classifier with Scikit-learn which works on tile pixels individually (see code below where training_data is a vector of singletons), but I want instead to train the classifier on texture patterns.

            ...

            ANSWER

            Answered 2019-Nov-02 at 19:13

            You can use U-Net or SegNet for image segmentation. In fact you add residual layers to your CNN to get this result:

            About U-Net:

            Arxiv: U-Net: Convolutional Networks for Biomedical Image Segmentation

            Seg-Net:

            Arxiv: SegNet: A Deep Convolutional Encoder-Decoder Architecture for Image Segmentation

            Here are Simple Examples of Codes: keras==1.1.0

            U-Net:

            Source https://stackoverflow.com/questions/58504305

            QUESTION

            unable to import cross_validation
            Asked 2019-Oct-27 at 08:40

            While building a new neural network I seem unable to split the data. For some unknown reason it wont import train.test.split

            ImportError: cannot import name 'cross_validation'

            ...

            ANSWER

            Answered 2018-Oct-11 at 09:23

            The module has been removed since 0.20.

            Deprecated since version 0.18: This module will be removed in 0.20. Use sklearn.model_selection.cross_val_score instead.

            Source https://stackoverflow.com/questions/52756324

            QUESTION

            Using ROC AUC score with Logistic Regression and Iris Dataset
            Asked 2019-May-03 at 11:17

            What I need is to:

            • Apply a logistic regression classifier
            • Report the per-class ROC using the AUC.
            • Use the estimated probabilities of the logistic regression to guide the construction of the ROC.
            • 5fold cross validation for the training your model.

            For this, my approach was to use this really nice tutorial:

            From his idea and method I simply changed how I obtain the raw data which I am getting like this:

            ...

            ANSWER

            Answered 2019-May-03 at 11:17

            The iris dataset is usually ordered with respect to classes. Hence, when you split without shuffling, the test dataset might get only one class.

            One simple solution would be using shuffle parameter.

            Source https://stackoverflow.com/questions/55944240

            QUESTION

            Accuracy SD not showing up in R
            Asked 2019-Jan-29 at 12:07

            I tried to follow the example codes at https://machinelearningmastery.com/tune-machine-learning-algorithms-in-r/ but my output did not showing up accuracy and kappa sd. What am i missing? My caret library is 3.5.2 on Windows 10 Pro.

            My output was:

            ...

            ANSWER

            Answered 2019-Jan-29 at 12:06

            In the tutorial it's not specified how the output with SD's was obtained. It actually wasn't just rf_default. Instead,

            Source https://stackoverflow.com/questions/54418798

            QUESTION

            What is the Search/Prediction Time Complexity of Logistic Regression?
            Asked 2019-Jan-17 at 16:19

            I am looking into the time complexities of Machine Learning Algorithms and I cannot find what is the time complexity of Logistic Regression for predicting a new input. I have read that for Classification is O(c*d) c-beeing the number of classes, d-beeing the number of dimensions and I know that for the Linear Regression the search/prediction time complexity is O(d). Could you maybe explain what is the search/predict time complexity of Logistic Regression? Thank you in advance

            Example For The other Machine Learning Problems: https://www.thekerneltrip.com/machine/learning/computational-complexity-learning-algorithms/

            ...

            ANSWER

            Answered 2019-Jan-17 at 16:19
            Complexity of training for logistic regression methods with gradient based optimization: O((f+1)csE), where:
            • f - number of features (+1 because of bias). Multiplication of each feature times it's weight (f operations, +1 for bias). Another f + 1 operations for summing all of them (obtaining prediction). Using gradient method to improve weights counts for the same number of operations, so in total we get 4* (f+1) (two for forward pass, two for backward), which is simply O(f+1).
            • c - number of classes (possible outputs) in your logistic regression. For binary classification it's one, so this term cancels out. Each class has it's corresponding set of weights.
            • s - number of samples in your dataset, this one is quite intuitive I think.
            • E - number of epochs you are willing to run the gradient descent (whole passes through dataset)

            Note: this complexity can change based on things like regularization (another c operations), but the idea standing behind it goes like this.

            Complexity of predictions for one sample: O((f+1)c)
            • f + 1 - you simply multiply each weight by the value of feature, add bias and sum all of it together in the end.
            • c - you do it for every class, 1 for binary predictions.
            Complexity of predictions for many samples: O((f+1)cs)
            • (f+1)c - see complexity for one sample
            • s - number of samples
            Difference between logistic and linear regression in terms of complexity: activation function.

            For multiclass logistic regression it will be softmax, while linear regression, as the name suggests, has linear activation (effectively no activation). It does not change the complexity using big O notation, but it's another c*f operations during the training (didn't want to clutter the picture further) multiplied by 2 for backprop.

            Source https://stackoverflow.com/questions/54238493

            QUESTION

            Error in impute() in R
            Asked 2017-Sep-14 at 15:19

            I'm learning Random Forest. For learning purpose I'm using following link random Forest. I'm trying to run the code given in this link using my R-3.4.1. But while running the following code for missing value treatment

            ...

            ANSWER

            Answered 2017-Sep-14 at 15:06

            The key mistake (among many mistakes) in that code was that there is no data parameter. The parameter name is obj. When I change that the example code runs.

            You also need to set on= or setkey given that the object is a data.table, or simply change it to a data.frame for the imputation step:

            Source https://stackoverflow.com/questions/46222304

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Learning-Algorithms

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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