half | Half precision floating point C++ library | Video Game library

 by   melowntech C++ Version: v1.1 License: MIT

kandi X-RAY | half Summary

kandi X-RAY | half Summary

half is a C++ library typically used in Gaming, Video Game applications. half has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Half precision floating point C++ library (imported from sourceforge upstream).
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              half has a low active ecosystem.
              It has 28 star(s) with 4 fork(s). There are 15 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 1 have been closed. On average issues are closed in 1 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of half is v1.1

            kandi-Quality Quality

              half has 0 bugs and 0 code smells.

            kandi-Security Security

              half has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              half code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              half is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              half releases are not available. You will need to build from source code and install.

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            half Key Features

            No Key Features are available at this moment for half.

            half Examples and Code Snippets

            No Code Snippets are available at this moment for half.

            Community Discussions

            QUESTION

            Padding scipy affine_transform output to show non-overlapping regions of transformed images
            Asked 2022-Mar-28 at 11:54

            I have source (src) image(s) I wish to align to a destination (dst) image using an Affine Transformation whilst retaining the full extent of both images during alignment (even the non-overlapping areas).

            I am already able to calculate the Affine Transformation rotation and offset matrix, which I feed to scipy.ndimage.interpolate.affine_transform to recover the dst-aligned src image.

            The problem is that, when the images are not fuly overlapping, the resultant image is cropped to only the common footprint of the two images. What I need is the full extent of both images, placed on the same pixel coordinate system. This question is almost a duplicate of this one - and the excellent answer and repository there provides this functionality for OpenCV transformations. I unfortunately need this for scipy's implementation.

            Much too late, after repeatedly hitting a brick wall trying to translate the above question's answer to scipy, I came across this issue and subsequently followed to this question. The latter question did give some insight into the wonderful world of scipy's affine transformation, but I have as yet been unable to crack my particular needs.

            The transformations from src to dst can have translations and rotation. I can get translations only working (an example is shown below) and I can get rotations only working (largely hacking around the below and taking inspiration from the use of the reshape argument in scipy.ndimage.interpolation.rotate). However, I am getting thoroughly lost combining the two. I have tried to calculate what should be the correct offset (see this question's answers again), but I can't get it working in all scenarios.

            Translation-only working example of padded affine transformation, which follows largely this repo, explained in this answer:

            ...

            ANSWER

            Answered 2022-Mar-22 at 16:44

            If you have two images that are similar (or the same) and you want to align them, you can do it using both functions rotate and shift :

            Source https://stackoverflow.com/questions/71516584

            QUESTION

            msvc std::lower_bound requires const operator*
            Asked 2022-Mar-18 at 20:51

            I am getting a

            ...

            ANSWER

            Answered 2022-Mar-18 at 20:51

            std::lower_bound takes a Cpp17ForwardIterator, which must also be a Cpp17InputIterator. The Cpp17InputIterator requirements include:

            Expression Return type *a reference, convertible to T

            Here, a is a "value of type X or const X", so MSVC is justified in requiring a const-qualified unary indirection operator; the "or" means that the code using the iterator can use either, and the author of the iterator has to support both. (Note that Cpp17InputIterator differs from Cpp17OutputIterator, where the required operation is *r = o, with r a non-const reference, X&.)

            So your operator* should have const qualification, and return a reference; specifically, a reference to T or const T (this is a Cpp17ForwardIterator requirement). You can satisfy this straightforwardly with using reference = const T& and by making cur_ and cur_valid_ mutable.

            The use of mutable here is entirely legitimate; since operator*() const is idempotent, it is "logically const" and the modifications to the data members are non-observable.

            Source https://stackoverflow.com/questions/71531724

            QUESTION

            Make ModalBottomSheetLayout always Expanded
            Asked 2022-Feb-09 at 10:50

            I am using ModalBottomSheetLayout in Jetpack Compose. Whenever it is shown with modalBottomSheetState.show(), it shows HalfExpanded or Expanded depending on the height of its content. This is from the source code:

            ...

            ANSWER

            Answered 2021-Aug-23 at 09:56

            QUESTION

            GitLab Runner fails to upload artifacts with "invalid argument" error
            Asked 2022-Feb-08 at 15:22

            I'm completely new to trying to implement GitLab's CI/CD pipelines, but it's been going quite well. In fact, for my ASP.NET project, if I specify a Publish Profile in the msbuild command that uses Web Deploy, it actually deploys the code successfully to the web server.

            However, I'm now wanting to have the "build" job create artifacts which are uploaded to GitLab that I can then subsequently deploy. We're using a self-hosted instance of GitLab, for which I'm not an admin, but I can speak to the admin if I know what I'm asking for!

            So I've configured my gitlab-ci.yml file like this:

            ...

            ANSWER

            Answered 2022-Feb-08 at 15:22

            After countless hours working on this, it seems that ultimately the issue was that our internal Web Application Firewall was blocking some part of the transfer of artefacts to the server, or the response back from it. With the WAF reconfigured not to block traffic from the machine running the GitLab Runner, the artefacts are successfully uploaded and the job succeeds.

            This would have been significantly easier to diagnose if the logging from GitLab was better. As per my comment on this issue, it should be possible to see the content of the response from the GitLab server after uploading artefacts, even when the response code is 200.

            What's strange - and made diagnosing the issue even harder - is that when I worked through the issue with the admin of our GitLab instance, digging through logs and running it in debug mode, the artefact upload process was uploading something successfully. We could see, for example, the GitLab Runner's log had been uploaded to the server. Clearly the WAF's blocking was selective and didn't block everything in both directions.

            Source https://stackoverflow.com/questions/70880840

            QUESTION

            ScrollViewReader scrollTo with .center anchor bug?
            Asked 2022-Jan-31 at 10:38

            So I'm try to use ScrollViewReader to programmatically scroll a horizontal scroll view. I thought it would work like scrollToItem with .centeredHorizontally in UIKit, and for the most part it does, but the last few elements in the scroll view are being forcefully scrolled to the center of the screen, despite the fact that the scroll view isn't normally able to scroll that far over (without snapping back after releasing the drag, at least). This ends up creating white space across the trailing half of the screen.

            I've seen some other questions about this and it seems like the general opinion is that it's not a bug? On the one hand I suppose we're telling the scroll view to center the item, and it's doing just that -- so, not a bug? On the other hand, that's not how similar functionality worked in UIKit. Also, this behavior is only happening on the trailing end of the scroll view! If it was the intended behavior I would expect that scrolling to the first element in the scroll view using .center anchor would force it into the center of the screen and leave leading white space, but this doesn't happen.

            Is there an elegant solution to this? Or do we have to calculate the width of our elements + spacing and figure out based on the screen width whether we should anchor .center or just scroll to the last element with anchor .trailing in order to replicate the UIKit behavior?

            ...

            ANSWER

            Answered 2021-Jul-25 at 06:31

            I found a package (Amzd/ScrollViewProxy) that was made before ScrollViewReader was released that functions much the same as ScrollViewReader, but also seems to not have the bug (if it is a bug) detailed in the question.

            Usage examples can be seen on the repository page, but here's a quick minimal example.

            Source https://stackoverflow.com/questions/68515053

            QUESTION

            Replacing YouTube HTML links with embed code
            Asked 2022-Jan-30 at 22:33

            I'm writing web pages in markdown and converting them to HTML using md2html tool. I want to process the output HTML file and find any youtube link like this:

            https://www.youtube.com/watch?v=abcdefgh887

            and replace it with the embed code:

            I toyed around a little with Grammars, mostly to get familiar with them, but concluded this probably isn't the ideal tool for the job. Plus I'd prefer to use existing modules that are easily adaptable to other similar tasks rather than roll my own half-baked solution.

            Perl5 has some good tools for this kind of thing but I'd like to use a pure Raku solution so I can learn more Raku.

            Any recommendations for good approaches to this problem?

            ...

            ANSWER

            Answered 2022-Jan-28 at 20:31

            I tried to answer your question without knowing an example.

            You need to extract youtubeId from A tag and then replace A tag into iframe tag.

            pseudo code is:

            Source https://stackoverflow.com/questions/70899694

            QUESTION

            Why is QuackSort 2x faster than Data.List's sort for random lists?
            Asked 2022-Jan-27 at 19:24

            I was looking for the canonical implementation of MergeSort on Haskell to port to HOVM, and I found this StackOverflow answer. When porting the algorithm, I realized something looked silly: the algorithm has a "halve" function that does nothing but split a list in two, using half of the length, before recursing and merging. So I thought: why not make a better use of this pass, and use a pivot, to make each half respectively smaller and bigger than that pivot? That would increase the odds that recursive merge calls are applied to already-sorted lists, which might speed up the algorithm!

            I've done this change, resulting in the following code:

            ...

            ANSWER

            Answered 2022-Jan-27 at 19:15

            Your split splits the list in two ordered halves, so merge consumes its first argument first and then just produces the second half in full. In other words it is equivalent to ++, doing redundant comparisons on the first half which always turn out to be True.

            In the true mergesort the merge actually does twice the work on random data because the two parts are not ordered.

            The split though spends some work on the partitioning whereas an online bottom-up mergesort would spend no work there at all. But the built-in sort tries to detect ordered runs in the input, and apparently that extra work is not negligible.

            Source https://stackoverflow.com/questions/70856865

            QUESTION

            std::erase_if delete an extra elements on std::vector?
            Asked 2021-Dec-28 at 07:50

            I use std::erase_if to erase half the elements from containers using a captured counter as follows. C++20 compiled with gcc10

            ...

            ANSWER

            Answered 2021-Dec-28 at 07:50

            remove_if takes a Predicate. And the standard library requires that a Predicate type:

            Given a glvalue u of type (possibly const) T that designates the same object as *first, pred(u) shall be a valid expression that is equal to pred(*first).

            Your predicate changes its internal state. As such, calling it twice with the same element will yield different results. That means it does not fulfill the requirements of Predicate.

            And therefore, undefined behavior ensues.

            Source https://stackoverflow.com/questions/70503725

            QUESTION

            Element is in first half of the list, Haskell
            Asked 2021-Dec-27 at 20:41

            Reading the book Get Programming with Haskell, one of the questions was to find if a given element is in the first half of a list. This can be done as

            ...

            ANSWER

            Answered 2021-Dec-26 at 03:42

            QUESTION

            Keyboard shortcut to split screen in half with source pane on left and console pane
            Asked 2021-Dec-18 at 08:11

            Is there a keyboard shortcut that splits the RStudio window in half with the source on the left and console on right (and hides all other panes) as per screenshot below?

            ...

            ANSWER

            Answered 2021-Dec-11 at 20:39

            The following might do the trick:

            Set up your own shortcut for Maximize Console

            1. Go to Tools -> Modify Keyboard Shortcuts
            2. Filter: Search for Maximize Console
            3. Under Shortcut add your own shortcut such as Ctrl C M for Console Maximize

            Keep left side for Source ONLY (if you think that it OK).

            1. Go to Preferences (Command ,)
            2. Go to Pane Layout and deselect all in the lower-left corner

            The History panel that you had to deselct from the Source side you can add to the lower-right panel; and then open it using control 4. And you can do the same for the Help panel, which you open using Control 3

            Source https://stackoverflow.com/questions/70258959

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install half

            You can download it from GitHub.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            gh repo clone melowntech/half

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