SPOJ | Solved SPOJ problems | Learning library

 by   t3nsor C++ Version: Current License: Unlicense

kandi X-RAY | SPOJ Summary

kandi X-RAY | SPOJ Summary

SPOJ is a C++ library typically used in Tutorial, Learning, Example Codes applications. SPOJ has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

This repository contains solutions to almost all problems I have solved on SPOJ. They’re intended as a last resort in case you’ve tried very hard to solve a problem but you just haven’t been able to figure it out. When I was trying to solve GSS2, I mostly found vague hints on online forums, which weren’t helpful. I wasn’t able to solve the problem until after I looked at some code. So obviously the code helps, and there can be good reasons to just look at code rather than being stuck indefinitely.
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            kandi-support Support

              SPOJ has a low active ecosystem.
              It has 239 star(s) with 103 fork(s). There are 26 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 3 have been closed. On average issues are closed in 158 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of SPOJ is current.

            kandi-Quality Quality

              SPOJ has 0 bugs and 0 code smells.

            kandi-Security Security

              SPOJ has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              SPOJ code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              SPOJ is licensed under the Unlicense License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              SPOJ releases are not available. You will need to build from source code and install.

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            SPOJ Key Features

            No Key Features are available at this moment for SPOJ.

            SPOJ Examples and Code Snippets

            No Code Snippets are available at this moment for SPOJ.

            Community Discussions

            QUESTION

            C# Increasing performance of a Linked List
            Asked 2022-Mar-27 at 09:35

            I'm working on SPOJ problem where you have to write an algorithm that based on input string conditions outputs new string, but you can't exceede time limit. problem link

            The fastest i could get was by using two stacks, but time limit was still exceeded, now I tried implementing doubly linked list, but it's twice slower than when I used stack. Do you have any idea on how can I increase performance of implemented linked list, or maybe should I use other data structure for this problem? Thought of implementing Node as a structure but not really sure if you can do that.

            ...

            ANSWER

            Answered 2022-Mar-27 at 09:35

            An implementation using a linked list will not be as fast as one that uses StringBuilder, but assuming you are asking about a linked list based implementation I would suggest not to reimplement LinkedList. Just use the native one.

            This means you don't have to change much in your code, just this:

            • Define the type of the list nodes as char: new LinkedList();
            • Instead of .Head use .First
            • Instead of .Print use string.Join("", list)

            However, there are these problems in your code:

            • When the input is >, you should allow the logic to execute when node is null. Currently you continue, but a null may mean that your "cursor" is in front of the non-empty list, so you should still deal with it, and move the "cursor" to list.First

            • When the input is -, you should still perform the removal even when node.Previous is null, because it is not the previous node that gets removed, but the current node. We should imagine the cursor to be between two consecutive nodes, and your removal logic shows that you took as rule that the cursor is between the current node and node.Next. You could also have taken another approach (with the cursor is just before node), but important is that all your logic is consistent with this choice.

            • When executing the logic for - -- in line with the previous point -- you should take into account that node.Previous could be null, and in that case you cannot do the removal as you have it. Instead, you could first assign the node reference to a temporary variable, then move the cursor, and then delete the node that is referenced by the temporary reference.

            Here is the corrected code, using the native LinkedList implementation. I moved the logic for doing nothing (your continue) inside each separate case, as I find that easier to understand/debug:

            Source https://stackoverflow.com/questions/71631796

            QUESTION

            C# SPOJ time optimalization
            Asked 2021-Nov-09 at 09:17

            I'm trying to get the job done MOHIBPIZ - PIZZA (https://www.spoj.com/problems/MOHIBPIZ/). I'm already sitting on it the second day, I've tried everything I can and found on the internet. The last chance before giving up is to ask you guys For recudces time I'm using InputOutput class created by davidsekar (https://github.com/davidsekar/C-sharp-Programming-IO/blob/master/ConsoleInOut/InputOutput.cs) but still I have time "time limit exceeded". :(

            I tried with two loops, but the method with the function seems more optimal to me. Thanks in advance for all the hints, suggestions and answers.

            This is code (link on ideone: https://ideone.com/):

            ...

            ANSWER

            Answered 2021-Nov-09 at 09:17

            As far as I can see, you have a well known Circle Division problem; see also A000124 sequence:

            number of pieces after n cuts are (n * n + n + 2) / 2

            That's why we can put O(1) time and space complexity

            Code:

            Source https://stackoverflow.com/questions/69874199

            QUESTION

            breaking while loop and doesn't print the result c#
            Asked 2021-Oct-11 at 20:20

            I'm a beginner in c# and I'm training on codeforces and SPOJ to learning how to solve problems, the problem with me is when the loop is break doesn't print all the input it's just end the program without printing

            please can someone tell me what is the mistake in these 2 codes that i write >

            the Input: 1,2,88,42 ,99 Output: 1,2,88

            ...

            ANSWER

            Answered 2021-Oct-11 at 20:20

            Answering to "...the problem is when the loop is break doesn't print all the input it's just end the program...":

            That's because after you breaked loop there is no more code to execute - so Console closes. You can add Console.ReadKey() or Console.ReadLine() at the end of Main method to keep Console opened after loop breaked. Console.ReadKey() would wait until you press any key, Console.ReadLine() would wait until you input something and press Enter (or just press Enter). Or in both ways Console will stay opened until you close it manually.

            Source https://stackoverflow.com/questions/69531620

            QUESTION

            Which character to append to string in suffix array?
            Asked 2021-Jul-30 at 15:22

            I was solving

            https://www.spoj.com/problems/BEADS/

            above question at SPOJ. I have stated the relevant information below:

            Problem Statement: The description of the necklace is a string A = a1a2 ... am specifying sizes of the particular beads, where the last character am is considered to precede character a1 in circular fashion. The disjoint point i is said to be worse than the disjoint point j if and only if the string aiai+1 ... ana1 ... ai-1 is lexicografically smaller than the string ajaj+1 ... ana1 ... aj-1. String a1a2 ... an is lexicografically smaller than the string b1b2 ... bn if and only if there exists an integer i, i <= n, so that aj=bj, for each j, 1 <= j < i and ai < bi.

            Output: For each test case, print exactly one line containing only one integer -- number of the bead which is the first at the worst possible disjoining, i.e. such i, that the string A[i] is lexicographically smallest among all the n possible disjoinings of a necklace. If there are more than one solution, print the one with the lowest i.

            Now the solution is using SUFFIX ARRAY. Input string s, and concat with itself, s'=s+s ,since I have to sort cyclic suffixes of array. Then create a suffix array on s', and output the smallest index that points to a suffix of original s, i.e., index < len(s).

            But there is a problem I face. I was appending '$' character to get SA, but I was getting wrong answer. After looking online, I found 1 solution that had appended '}' to string. I found that ascii('$') < ascii('a') < ascii('z') < ascii('}')

            But i don't understand how this will make a difference, why this is accepted answer and haven;t found a case where this will make a difference. The solution (AC) can be found here:

            Link to Code

            ...

            ANSWER

            Answered 2021-Jul-30 at 15:22

            The difference is in the last condition:

            If there are more than one solution, print the one with the lowest i.

            Consider input "abab".

            The correct answer is 0, which you get when you append '}', because "abababab}" is less than all of its suffixes.

            If you append '$', you get the wrong answer, because "ab$" < "abab$" < "ababab$" < "abababab$".

            Source https://stackoverflow.com/questions/68592556

            QUESTION

            I am trying to find the factors of factorial of a number
            Asked 2021-Jun-10 at 21:59

            I am trying to solve the SPOJ problem DIVFACT where we need to find the factorial of a number. Though I used the correct formulae and at the same time I also checked the special case of 0 and 1,still I am getting wrong answer and it's really difficult for me to figure out what's wrong with my code. Can someone please help me figure out the problem? For reference I am providing the link to the problem:- Link of the problem

            ...

            ANSWER

            Answered 2021-Jun-10 at 21:59

            The problem states that the answer should be in MOD 10^9+7 but you have mistakenly defined MOD as 10^8+7.

            Source https://stackoverflow.com/questions/67927710

            QUESTION

            Vectorization or efficient way to calculate Longest Increasing subsequence of tuples with Pandas
            Asked 2021-May-30 at 03:13

            Using pandas/python, I want to calculate the longest increasing subsequence of tuples for each DTE group, but efficiently with 13M rows. Right now, using apply/iteration, takes about 10 hours.

            Here's roughly my problem:

            DTE Strike Bid Ask 1 100 10 11 1 200 16 17 1 300 17 18 1 400 11 12 1 500 12 13 1 600 13 14 2 100 10 30 2 200 15 20 2 300 16 21 ...

            ANSWER

            Answered 2021-May-27 at 13:27

            What is the complexity of your algorithm of finding the longest increasing subsequence?

            This article provides an algorithm with the complexity of O(n log n). Upd: doesn't work. You don't even need to modify the code, because in python comparison works for tuples: assert (1, 2) < (3, 4)

            Source https://stackoverflow.com/questions/67698793

            QUESTION

            Count number of digits in factorial - Input/Ouput performance issue
            Asked 2021-May-19 at 07:50

            I am solving task on spoj platform - count number of digits in factorial. I found Kamenetsky Formula and implemented it:

            ...

            ANSWER

            Answered 2021-May-19 at 07:00

            I think the time limit is exceeding because of the slow I/O. This is mainly because of System.out.println's underlying PrintStream. Find more details in this post why-is-system-out-println-so-slow. You can refer to the below Fast I/O template which will help solve this problem.

            Reference - Fast I/O in java

            Source https://stackoverflow.com/questions/67598118

            QUESTION

            Getting EOF Error while giving inputs to code
            Asked 2021-May-16 at 06:21

            I tried a problem from SPOJ called The next palindrome. The problem statement is given as

            A positive integer is called a palindrome if its representation in the decimal system is the same when read from left to right and from right to left. For a given positive integer K of not more than 1000000 digits, write the value of the smallest palindrome larger than K to output. Numbers are always displayed without leading zeros.

            Here is my code

            ...

            ANSWER

            Answered 2021-May-16 at 06:21

            The error is caused because your input "n" makes both arguments same in the range function in this line "for j in range(int(n) + 1, 1000000 + 1)". It looks like this range(1000001, 1000001) which return nothing. Use input of "n" smaller than 1000000. It will work.

            It return empty list when I use this code.

            Source https://stackoverflow.com/questions/67553573

            QUESTION

            How to make code faster to fit it in time limit?
            Asked 2021-Mar-08 at 07:32

            I'm trying to submit this code on spoj https://www.spoj.com/problems/PALIN which is asking to find next smallest palindrome of a given number n, but as this code works, it is slow therefor it exceeds the time limit (2-9 seconds). is there another way to solve this exercise in a faster way?

            The first line contains integer t, the number of test cases. Integers K are given in the next t lines.

            code:

            ...

            ANSWER

            Answered 2021-Mar-08 at 07:29

            The most obvious thing to do is to stop copying and reversing the string. Instead, compare the first character to the last character, then the second to the second-to-last, and so on.

            Also, why are you using strings at all? Strings are complex and expensive. The operations you are performing can be done entirely on numbers.

            Lastly, consider numbers like "473X". None of those can ever be palindromes. You don't have to test all ten of them. If you're going to look at four-digit numbers starting with "47", there's only one that's a palindrome -- so why are you checking all hundred of them?

            Before writing code to solve a problem like this, think through the algorithm you're going to use and make sure you don't have any obvious wasted effort.

            Source https://stackoverflow.com/questions/66525751

            QUESTION

            Using fflush for speeding up code to prevent a time limit exceeded
            Asked 2021-Mar-01 at 16:10

            The following code gets TLE (time limit exceeded) if the standard output is not flushed.

            ...

            ANSWER

            Answered 2021-Mar-01 at 16:10

            The problem specification tells you what to do:

            Attention: the program should clear the output buffer after printing each line.

            It can be done using fflush(stdout) command or by setting the proper type of buffering at the beginning of the execution - setlinebuf(stdout).

            The problem title indicates why:

            (Interactive)

            The judging software is operating the program interactively. After giving the program an input, it waits for output before providing more input. When your program does not flush the buffered output, the judging software keeps waiting until its time limit is exceeded.

            Commonly, output streams to terminals are line-buffered, in which case printing a new-line character causes them to be flushed. However, this judging software is likely using a pipe that is fully buffered, so output will not be flushed until the buffer is full or you explicitly request a flush (or, at the start of the program, you change the buffering mode to unbuffered or line-buffered).

            When you flush the output, the judging software will see it, and then it will continue and provide more input.

            As an alternative to flushing the output after each printf, you can set the stream to line buffering mode by executing setvbuf(stdout, NULL, _IOLBF, 0); at the beginning of the program (before doing any other operation on the stream).

            Source https://stackoverflow.com/questions/66425010

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