ACVD | perform fast simplification of 3D surface meshes | Service Mesh library

 by   valette C++ Version: Current License: Non-SPDX

kandi X-RAY | ACVD Summary

kandi X-RAY | ACVD Summary

ACVD is a C++ library typically used in Architecture, Service Mesh applications. ACVD has no bugs, it has no vulnerabilities and it has low support. However ACVD has a Non-SPDX License. You can download it from GitHub.

a programm to perform fast simplification of 3D surface meshes
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            kandi-support Support

              ACVD has a low active ecosystem.
              It has 107 star(s) with 43 fork(s). There are 12 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 22 have been closed. On average issues are closed in 201 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of ACVD is current.

            kandi-Quality Quality

              ACVD has no bugs reported.

            kandi-Security Security

              ACVD has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              ACVD has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              ACVD releases are not available. You will need to build from source code and install.

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            ACVD Key Features

            No Key Features are available at this moment for ACVD.

            ACVD Examples and Code Snippets

            No Code Snippets are available at this moment for ACVD.

            Community Discussions

            QUESTION

            Remove comma in unexected column within csv [awk,sed]
            Asked 2020-Dec-09 at 19:56

            Is there a simple way to remove a comma within a csv that isn't suppose to be there using AWK/ SED?

            The .csv is made up of 5 columns, but that additional comma makes some rows come up with 6 columns. For example see below, the third column i am expecting to be number, but as you can see row 3 and 4 are strings.

            ...

            ANSWER

            Answered 2020-Dec-09 at 19:10

            Use this Perl one-liner:

            Source https://stackoverflow.com/questions/65223155

            QUESTION

            How to find a repeated letter in a string with Regular Expressions - Python3
            Asked 2020-Sep-12 at 01:50

            I've tried a lot of differents ways, but I can't make this work. I need to capture two differents strings with regular expressions (I'm using RE on Py3).

            1. I need to take a substring with the same letter repetead 3 times.
            2. I need to take a substring that is XYX, like "BAB" or "ACA" (I don't even know how to start on this)
            ...

            ANSWER

            Answered 2020-Sep-12 at 01:50
            Problems

            You have a few problems:

            1. Your regex ([a-z])\3 captures a single lowercase alpha character, then tries to match capture group 3 (which doesn't exist)
            2. You use re.findall(regular, string) but you've already compiled the regex into regular, so you should be calling it as regular.findall(string)
            3. You encased your regex in single quotes (good) ' but your regex contains a backslash. To escape it you need to use r''
            Solution

            Fixing all of the above, we get the following.

            finditer method

            See code working here

            Source https://stackoverflow.com/questions/63855959

            QUESTION

            Find exact word/string after some characters
            Asked 2020-Jul-17 at 18:30

            I have a list of values,
            ex: ['acvd MF50-107895 htrx867954', 'aasdsasdasdwg 12354 MF34-123445 hwertx86', 'sdfrgrwgvwewerf 4356 MF74-765980 hwer982fg']

            Tried regex to extract the values after character "MF".
            Regex expression i am trying,

            x = re.search(r"MF", txt) the values after character "MF" i need to consider only next 9 characters, the sequence of characters other than spaces and the result should be like this MF50-107895, MF34-123445, MF74-765980.

            ...

            ANSWER

            Answered 2020-Jul-17 at 17:58

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install ACVD

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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          • HTTPS

            https://github.com/valette/ACVD.git

          • CLI

            gh repo clone valette/ACVD

          • sshUrl

            git@github.com:valette/ACVD.git

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