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kandi X-RAY | lintcode Summary
kandi X-RAY | lintcode Summary
以下是题目列表: Trailing ZerosUgly NumberMerge Sorted Array IIBinary Tree SerializationRotate StringFizz BuzzSearch Range in Binary Search TreeMin StackstrStrBinary SearchPermutationsPermutations IISubsetsSubsets IISearch a 2D MatrixInterleaving StringInsert IntervalPartition ArrayMinimum Window SubstringN-QueensN-Queens IIReverse Linked ListReverse Linked List IIRecover Rotated Sorted ArrayImplement Queue by Two StacksMaximum SubarrayMaximum Subarray IIMaximum Subarray IIIMinimum SubarrayMaximum Subarray DifferenceMajority NumberMajority Number IIMajority Number IIIProduct of Array Exclude ItselfPrevious PermuationNext PermutationReverse Words in a StringCompare Strings2 Sum3 Sum ClosestSearch Insert PositionSearch for a RangeSearch in Rotated Sorted Array IIMerge Sorted ArrayMedian of two Sorted ArraysBinary Tree Preorder TraversalBinary Tree Inorder TraversalBinary Tree Postorder TraversalBinary Tree Level Order TraversalBinary Tree Level Order Traversal IIBinary Tree Zigzag Level Order TraversalConstruct Binary Tree from Preorder and Inorder TraversalFirst Bad VersionFind Peak ElementLongest Increasing SubsequenceLongest Common PrefixLongest Common SubstringMedianData Stream MedianSingle NumberSingle Number IIIInsert Node in a Binary Search TreeBinary Search Tree IteratorRemove Node in Binary Search TreeLowest Common AncestorMinimum Adjustment CostBackpackBalanced Binary TreeBinary Tree Maximum Path SumValidate Binary Search TreePartition ListMaximum Depth of Binary TreeSort ListReorder ListRemove Duplicates from Sorted ArrayRemove Duplicates from Sorted List IIUnique PathsUnique Paths IIDistinct SubsequencesEdit DistanceWord LadderWord Ladder IILargest Rectangle in HistogramWord SearchLongest Consecutive SequenceBackpack IIMax TreeTopological SortingHash FunctionRehashingHeapifyWord Search IILRU CacheCombination SumClone GraphSubarray SumSubarray Sum ClosestFast PowerSqrtO(1) Check Power of 2Sort Colors IIInterleaving Positive and Negative NumbersSort ColorsBest Time to Buy and Sell StockBest Time to Buy and Sell Stock IIBest Time to Buy and Sell Stock IIICombinationsRegular Expression MatchingMinimum Depth of Binary TreeUnique CharactersTwo Strings Are AnagramsFind Minimum in Rotated Sorted ArrayFind Minimum in Rotated Sorted Array IIRotate ImageSet Matrix ZeroesUnique Binary Search TreesUnique Binary Search Trees IIMerge Two Sorted ListsNth to Last Node in ListAdd Two NumbersRotate ListAnagramsRemove ElementInsertion Sort ListRemove Nth Node From End of ListRoute Between Two Nodes in GraphUpdate BitsBinary RepresentationFlip BitsDelete DigitsWood CutLargest NumberMatrix Zigzag TraversalGas StationMaximum Product SubarrayWildcard MatchingSegment Tree BuildSegment Tree QuerySegment Tree ModifyInterval Minimum NumberInterval SumInterval Sum IISegment Tree Query IIFirst Missing PositiveTrapping Rain WaterSliding Window MedianTrapping Rain Water IIExpression EvaluationPermutation SequenceCount of Smaller NumberBuilding OutlineExpression Tree BuildValid SudokuCount of Smaller Number before itselfLongest Substring with At Most K Distinct CharactersThe Smallest DifferenceNumber of Airplanes in the SkyLongest Substring Without Repeating CharactersContainer With Most WaterPrint Numbers by RecursionAssignment Operator OverloadingAdd BinaryConvert Sorted Array to Binary Search Tree With Minimal HeightPlus OneDivide Two IntegersGray CodeReverse IntegerCandyHouse RobberBest Time to Buy and Sell Stock IVCoins in a LineCoins in a Line IIDelete Node in the Middle of Singly Linked ListFibonacciCount 1 in BinaryMerge IntervalsNext Permutation IILongest Palindromic SubstringPartition Array by Odd and EvenLongest Increasing Continuous subsequence IILongest Increasing Continuous subsequenceMinimum Size Subarray SumValid PalindromeValid NumberInteger to RomanRoman to IntegerCount and SaySimplify PathLength of Last WordValid ParenthesesEvaluate Reverse Polish NotationContinuous Subarray SumContinuous Subarray Sum IISubarray Sum IIJump Game IIMaximal SquareLongest WordsSpace ReplacementMax Points on a LineInvert Binary TreeFind the Missing NumberNumber of IslandsNumber of Islands IIFind the Weak Connected Component in the Directed GraphScramble StringSubmatrix SumWord BreakTriangleRemove Duplicates from Sorted Array IISort Letters by CasePalindrome Partitioning IIMinimum Path SumMerge k Sorted ListsLinked List CycleLinked List Cycle IIConvert Sorted List to Binary Search TreeClimbing StairsCopy List with Random PointerA + B Problem Digit Counts Kth Largest Element Search a 2D Matrix II String to Integer(atoi) 3 Sum 4 Sum Search in Rotated Sorted Array Construct Binary Tree from Inorder and Postorder Traversal Longest Common Subsequence Single Number II k Sum k Sum II Jump Game Palindrome Partitioning Sqrt(x) Combination Sum II Singleton Sliding Window Maximum Convert Expression to Polish Notation Convert Expression to Reverse Polish Notation Triangle Count Subtree Kth Smallest Number in Sorted Matrix Maximum Gap Find the Connected Component in the Undirected Graph
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Community Discussions
Trending Discussions on lintcode
QUESTION
I am trying to solve this problem. http://www.lintcode.com/en/problem/coin-change-ii/#
This is the standard coin change problem solvable with dynamic programming. The goal is to find the number of ways to create an amount using an infinite set of coins, where each has a certain value. I have created the following solution :
...ANSWER
Answered 2017-Dec-28 at 20:08Let's consider the loop that works first:
QUESTION
So, I'm doing a problem called "Unique Paths II" in lintcode. However, I encountered a runtime error during a testcase:
...ANSWER
Answered 2019-Sep-12 at 16:13Regardless of the error you should read Why is “using namespace std;” considered bad practice? and enable compiler warnings. In your code are many
QUESTION
So, I was coding a problem on lintcode (number 69). I decided to use dfs using a traditional array as a queue. However, it returned -1 at the commented line, which lintcode says is a segmentation fault with the given input. Here is my code.
...ANSWER
Answered 2019-Jul-17 at 09:16These two lines are a likely culprit:
QUESTION
I am simulating code to erase all zero at the beginning of a string.
...ANSWER
Answered 2018-Jun-02 at 11:08As eraseZero
is a part of class Solution
and not globally defined, you should use the instance, self
in this case, of that class to call it, whether you call it inside or outside the class.
QUESTION
I'm trying to write a program to check if a Tree T2 is a subtree present in Tree T1. I'm using a traversal by storing the state of the tree into a string and checking if T2's substring is a substring present in T1's substring. For some reason, my code fails if I do an in-order in the traverse method to generate a string to hold the representation for the binary tree. Why does this happen? It works fine doing a Post-Order. This is the input case my program fails on:
{9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9} {9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9}
The binary tree representation format can be found http://www.lintcode.com/help/binary-tree-representation/
...ANSWER
Answered 2017-Dec-10 at 17:31The recursive algorithm you implemented does not provide the serialization of a tree in the desired order. Imagine how it works. All the items of the left subtree will always precede any of the items of the right subtree, since the right subtree will always be processed after the left subtree is finished. In the form that is described at the page you mentioned, al the items of a certain level should follow each other, and the items of the next level should be processed after all the items of the given level are done. To write trees in the described order you need a more complicated algorithm.
And furtermore, the described way to represent a tree as a string does not allow to search for subtrees by simply searching substrings. Consider the follwing tree:
QUESTION
Scenario:
I'm trying to solve one question on LintCode, "Longest Consecutive Sequence", where given an unsorted array of integers, find the length of the longest consecutive elements sequence.
Link to the original question: https://www.lintcode.com/en/problem/longest-consecutive-sequence/
So here is my intuitive solution:
...ANSWER
Answered 2017-Feb-06 at 20:21The Time complexity is worst case complexity. So it looks like O(n^2), with n= num of elements in the set.
In fact:
QUESTION
I built a data structure for two sum question. In this data structure I built add and find method.
add - Add the number to an internal data structure.
find - Find if there exists any pair of numbers which sum is equal to the value.
For example:
ANSWER
Answered 2017-Feb-22 at 22:51There does not seem to be anything wrong with your code.
However a coding challenge could possibly require a more performant solution. (You check every item against every item, which would take O(N^2)).
The best solution to implement find
, is using a HashMap
, which would take O(N). It's explained more in detail here.
QUESTION
Edit:
The function is part of an answer to lintcode question "combination sum", if I use the second version, the output is "[[],...,[]], where all inner list is empty, even when they are passed in with values. When I just switch to the first version without changing anything else, it would work.
So I assume it has something to with the Java parameter-passing process that I don't understand. Could you please explain why only the first version can work?
Code:
...ANSWER
Answered 2017-Feb-15 at 21:04Eventually, they're doing the same thing, however, the only difference I can notice is the first one uses more memory and there is no need to actually construct a new ArrayList of an already existing one.
QUESTION
If waitFor
is not used, killing JVM has no effect on its child process. Here is an example.
Bash script:
...ANSWER
Answered 2017-Feb-10 at 10:42There's nothing special about waitPid()
, other than the fact that you keep the parent process in the foreground.
If you fork and then wait for the child to finish, you have a (simplified) process tree like this:
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