python-llist | Linked list extension module for Python | Dictionary library
kandi X-RAY | python-llist Summary
kandi X-RAY | python-llist Summary
llist is an extension module for CPython providing basic linked list data structures. Collections implemented in the llist module perform well in problems which rely on fast insertions and/or deletions of elements in the middle of a sequence. For this kind of workload, they can be significantly faster than collections.deque or standard Python lists. This extension requires CPython 2.5 or newer (3.x is supported). If you are looking for an implementation of linked lists in pure Python, visit The pypy-llist module has the same API as this extension, but is significantly slower in CPython. Currently llist provides the following types of linked lists: - dllist - a doubly linked list - sllist - a singly linked list. Full documentation of these classes is available at: To install this package, either run "pip install llist", or download it manually from then unpack the sources and compile them with "python setup.py install". The most current development version is available at: Bugs can be reported at: This software is distributed under the MIT license. Please see the LICENSE file included in the package for details.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of python-llist
python-llist Key Features
python-llist Examples and Code Snippets
spark = (
SparkSession.builder.master("yarn")
.appName("read text file in pyspark")
.getOrCreate()
)
from pyspark.sql import functions as F, types as T
df = spark.read.format("text").load("/content/dri
def reverse(self):
prev = None
current = self
while current:
next=current.next
current.next=prev
prev=current
current=next
self.val = prev.va
library(gsubfn)
boring_function <- function(x) {
a <- x + 1
b <- x - 1
c <- x / 1
list(a, b, c)
}
list[a, b, c] <- boring_function(0)
a
## [1] 1
b
## [1] -1
c
## [1] 0
# target components can be left unspecified i
def oddEvenList(self, head):
dummy1 = odd = ListNode(0)
dummy2 = even = ListNode(0)
while head:
odd.next = head
even.next = head.next
odd = odd.next
even = even.next
head = head.next.next
from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
import time
from selenium.common.exceptions import WebDriverException
driver.execute_script("return arguments[0].s
def append(self,new_data):
new_node = Node(new_data)
if self.head is None:
self.head = new_node
return
last = self.head
while last.next:
last = last.next
la
def insertNode_pos(self, data, pos):
new_node = SinglyLinkedListNode(data)
if pos == 0:
new_node.next = self.head
self.head = new_node
return
temp = self.head
for iter in range(pos):
if ite
@dataclass
class Fieldset:
label: str
fields: List[Field] = []
__annotations__ = {
'label': str,
'fields': List[Field],
}
ins_hd, in_tl = insert_element(list_head, list_tail, 0, 1)
ins_hd, in_tl = insert_element(list_head, list_tail, 0, 1)
# ...
list_head, list_tail = insert_element(list_head, list_tail, 0, 1)
list_head, list_tail = i
flipped = reverse(llist) # two names for the same reversed list
t1 = list(llist) # a copy of the reversed list
t2 = list(reverse(flipped)) # a copy of the re-reversed list, identical to the original
is_correct = t1 == t2 # False; one is
Community Discussions
Trending Discussions on Dictionary
QUESTION
Since Python 3.7, dictionaries are ordered. So why I can't get keys by index?
...ANSWER
Answered 2022-Mar-26 at 21:57Building in such an API would be an "attractive nuisance": the implementation can't support it efficiently, so better not to tempt people into using an inappropriate data structure.
It's for much the same reason that, e.g., a linked list rarely offers an indexing API. That's totally ordered too, but there's no efficient way to find the i
'th element for an arbitrary i
. You have to start at the beginning, and follow i
links in turn to find the i
'th.
Same end result for a CPython dict. It doesn't use a linked list, but same thing in the end: it uses a flat vector under the covers, but basically any number of the vector's entries can be "holes". There's no way to jump over holes short of looking at each entry, one at a time. People expect a[i]
to take O(1)
(constant) time, not O(i)
time.
QUESTION
I have a dictionary of the form:
...ANSWER
Answered 2022-Feb-21 at 05:50I believe this will work:
For each list, we will filter the values where conf
is negative, and after that we will filter conf
itself.
QUESTION
Given a dict:
...ANSWER
Answered 2022-Feb-21 at 15:47You could use a Series and explode
:
QUESTION
I confronted strange behavior in Dictionary collection in Julia. a Dictionary can be defined in Julia like this:
...ANSWER
Answered 2022-Jan-29 at 19:41The key order in Dict
is currently undefined (this might change in the future).
If you want order to be preserved use OrderedDict
from DataStructures.jl:
QUESTION
I have an odd problem, where I am struggling to understand the nature of "static context" in Java, despite the numerous SO questions regarding the topic.
TL;DR:
I have a design flaw, where ...
This works:
...ANSWER
Answered 2022-Jan-26 at 17:11One way to solve the issue is by parameterizing the ParentDTO Class with its own children.
QUESTION
The question in the title pretty much says it all. The catch is that T
cannot be restricted.
Here is what I have tried:
...ANSWER
Answered 2022-Jan-05 at 18:55If you want the compiler to make calling toMap()
an error if T
isn't assignable to [K, V]
for some K
and V
, then in some sense it doesn't matter what the output type is in such a case. It could be Map
or Map
or anything, as long as the toMap()
call is a compiler error. I think you'll end up with a runtime error (you can wade through the spec if you really care) so the function won't return... the "actual" return type is never
which can be safely widened to Map
or anything you want without causing a type safety issue.
Anyway, to make the compiler error happen, you can give toMap()
a this
parameter which requires this
be of ArrayWrapper<[any, any]>
or something equivalent. You could use conditional type inference to manually infer K
and V
from T
:
QUESTION
To know a key k
exist in a map M1[k]v
is very straightforward in Go
.
ANSWER
Answered 2022-Jan-02 at 18:04Use if _, ok := M1[k]; ok { }
. If you use the blank identifier, the value will not be "loaded".
Let's write benchmarks to test it:
QUESTION
I have documents in collection which have structure:
...ANSWER
Answered 2021-Dec-05 at 08:43Here is a possibility (requires Mongo 4.2
or better):
QUESTION
macro test1(name,arg)
println(arg.args[2])
typeof(arg.args[2])
end
@test1 test1 (
(arg1, (:max=>10))
)
...ANSWER
Answered 2021-Nov-06 at 05:49This is because macros work on code before the code is compiled. Source code is first parsed to Symbol
s, literals (integers, floats, strings, etc), or Expr
(expressions). At this point, all expressions contain only these three things.** After the macro is done and returns an expression, that expression is compiled into runtime code where more complicated objects like Dict
s can exist.
The code below illustrates the difference before and after compiling. Note how 1+5
and Dict()
were expressions in the macro body, but is afterward evaluated to an Int64
and a Dict
.
QUESTION
I would like to convert a NamedTuple
to a Dict
in Julia. Say I have the following NamedTuple
:
ANSWER
Answered 2021-Oct-30 at 13:52The simplest way to get an iterator of keys and values for any key-value collection is pairs
:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install python-llist
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page