python-llist | Linked list extension module for Python | Dictionary library

 by   ajakubek C Version: Current License: MIT

kandi X-RAY | python-llist Summary

kandi X-RAY | python-llist Summary

python-llist is a C library typically used in Utilities, Dictionary applications. python-llist has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

llist is an extension module for CPython providing basic linked list data structures. Collections implemented in the llist module perform well in problems which rely on fast insertions and/or deletions of elements in the middle of a sequence. For this kind of workload, they can be significantly faster than collections.deque or standard Python lists. This extension requires CPython 2.5 or newer (3.x is supported). If you are looking for an implementation of linked lists in pure Python, visit The pypy-llist module has the same API as this extension, but is significantly slower in CPython. Currently llist provides the following types of linked lists: - dllist - a doubly linked list - sllist - a singly linked list. Full documentation of these classes is available at: To install this package, either run "pip install llist", or download it manually from then unpack the sources and compile them with "python setup.py install". The most current development version is available at: Bugs can be reported at: This software is distributed under the MIT license. Please see the LICENSE file included in the package for details.
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              python-llist has a low active ecosystem.
              It has 61 star(s) with 12 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 8 have been closed. On average issues are closed in 152 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of python-llist is current.

            kandi-Quality Quality

              python-llist has no bugs reported.

            kandi-Security Security

              python-llist has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              python-llist is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              python-llist releases are not available. You will need to build from source code and install.

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            python-llist Key Features

            No Key Features are available at this moment for python-llist.

            python-llist Examples and Code Snippets

            How to use map and reduce in pyspark for list object with some list variables?
            Pythondot img1Lines of Code : 49dot img1License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            spark = (
                SparkSession.builder.master("yarn")
                .appName("read text file in pyspark")
                .getOrCreate()
            )
            
            from pyspark.sql import functions as F, types as T
            
            df = spark.read.format("text").load("/content/dri
            Not able to assign head after reversing a linked list iteratively in Python
            Pythondot img2Lines of Code : 15dot img2License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
                def reverse(self):
                    prev = None
                    current = self
            
                    while current:
                        next=current.next
                        current.next=prev
                        prev=current
                        current=next
                        
                    self.val = prev.va
            Is there an R method to retrieve multiple variables from a function like in Python?
            Pythondot img3Lines of Code : 105dot img3License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            library(gsubfn)
            
            boring_function <- function(x) {
              a <- x + 1
              b <- x - 1
              c <- x / 1
              list(a, b, c)
            }
            
            list[a, b, c] <- boring_function(0)
            a
            ## [1] 1
            b
            ## [1] -1
            c
            ## [1] 0
            
            # target components can be left unspecified i
            Didn't got the odd even linklist
            Pythondot img4Lines of Code : 12dot img4License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            def oddEvenList(self, head):
                dummy1 = odd = ListNode(0)
                dummy2 = even = ListNode(0)
                while head:
                    odd.next = head
                    even.next = head.next
                    odd = odd.next
                    even = even.next
                    head = head.next.next
            Web Data scraping: getting all data by selecting drop down menus python
            Pythondot img5Lines of Code : 27dot img5License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            from selenium import webdriver
            from selenium.webdriver.common.action_chains import ActionChains
            import time
            from selenium.common.exceptions import WebDriverException
            
                driver.execute_script("return arguments[0].s
            What is wrong with this linked list implementation?
            Pythondot img6Lines of Code : 13dot img6License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
                def append(self,new_data):
                    new_node = Node(new_data)
            
                    if self.head is None:
                        self.head = new_node
                        return
            
                    last = self.head
                    while last.next:
                        last = last.next
            
                    la
            copy iconCopy
             def insertNode_pos(self, data, pos):
                new_node = SinglyLinkedListNode(data)
                if pos == 0:
                    new_node.next = self.head
                    self.head = new_node
                    return
            
                temp = self.head
                for iter in range(pos):
                    if ite
            Using dataclasses with Cython
            Pythondot img8Lines of Code : 10dot img8License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            @dataclass
            class Fieldset:
                label: str
                fields: List[Field] = []
            
                __annotations__ = {
                    'label': str,
                    'fields': List[Field],
                }
            
            Can't insert same element again and again at the beginning in LinkedList
            Pythondot img9Lines of Code : 75dot img9License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            ins_hd, in_tl = insert_element(list_head, list_tail, 0, 1)
            ins_hd, in_tl = insert_element(list_head, list_tail, 0, 1)
            # ...
            
            list_head, list_tail = insert_element(list_head, list_tail, 0, 1)
            list_head, list_tail = i
            copy iconCopy
            flipped = reverse(llist)  # two names for the same reversed list
            t1 = list(llist)  # a copy of the reversed list
            t2 = list(reverse(flipped)) # a copy of the re-reversed list, identical to the original
            is_correct = t1 == t2  # False; one is

            Community Discussions

            QUESTION

            Why I can't get dictionary keys by index?
            Asked 2022-Mar-26 at 22:52

            Since Python 3.7, dictionaries are ordered. So why I can't get keys by index?

            ...

            ANSWER

            Answered 2022-Mar-26 at 21:57

            Building in such an API would be an "attractive nuisance": the implementation can't support it efficiently, so better not to tempt people into using an inappropriate data structure.

            It's for much the same reason that, e.g., a linked list rarely offers an indexing API. That's totally ordered too, but there's no efficient way to find the i'th element for an arbitrary i. You have to start at the beginning, and follow i links in turn to find the i'th.

            Same end result for a CPython dict. It doesn't use a linked list, but same thing in the end: it uses a flat vector under the covers, but basically any number of the vector's entries can be "holes". There's no way to jump over holes short of looking at each entry, one at a time. People expect a[i] to take O(1) (constant) time, not O(i) time.

            Source https://stackoverflow.com/questions/71632064

            QUESTION

            Filter a dictionary of lists
            Asked 2022-Mar-24 at 07:56

            I have a dictionary of the form:

            ...

            ANSWER

            Answered 2022-Feb-21 at 05:50

            I believe this will work: For each list, we will filter the values where conf is negative, and after that we will filter conf itself.

            Source https://stackoverflow.com/questions/71184699

            QUESTION

            Convert dict to a dataframe with keys repeating for each value?
            Asked 2022-Feb-21 at 21:29

            Given a dict:

            ...

            ANSWER

            Answered 2022-Feb-21 at 15:47

            You could use a Series and explode:

            Source https://stackoverflow.com/questions/71209171

            QUESTION

            how Julia determines index of dictionary keys?
            Asked 2022-Jan-29 at 20:05

            I confronted strange behavior in Dictionary collection in Julia. a Dictionary can be defined in Julia like this:

            ...

            ANSWER

            Answered 2022-Jan-29 at 19:41

            The key order in Dict is currently undefined (this might change in the future).

            If you want order to be preserved use OrderedDict from DataStructures.jl:

            Source https://stackoverflow.com/questions/70909065

            QUESTION

            Java map function throws non-static method compiler error
            Asked 2022-Jan-27 at 04:17

            I have an odd problem, where I am struggling to understand the nature of "static context" in Java, despite the numerous SO questions regarding the topic.

            TL;DR:

            I have a design flaw, where ...

            This works:

            ...

            ANSWER

            Answered 2022-Jan-26 at 17:11

            One way to solve the issue is by parameterizing the ParentDTO Class with its own children.

            Source https://stackoverflow.com/questions/70860253

            QUESTION

            In Typescript, how can I convert an Array to a Map and infer K and V if T is a tuple [K, V] while having compile time protection if it isn't
            Asked 2022-Jan-05 at 18:55

            The question in the title pretty much says it all. The catch is that T cannot be restricted.

            Here is what I have tried:

            ...

            ANSWER

            Answered 2022-Jan-05 at 18:55

            If you want the compiler to make calling toMap() an error if T isn't assignable to [K, V] for some K and V, then in some sense it doesn't matter what the output type is in such a case. It could be Map or Map or anything, as long as the toMap() call is a compiler error. I think you'll end up with a runtime error (you can wade through the spec if you really care) so the function won't return... the "actual" return type is never which can be safely widened to Map or anything you want without causing a type safety issue.

            Anyway, to make the compiler error happen, you can give toMap() a this parameter which requires this be of ArrayWrapper<[any, any]> or something equivalent. You could use conditional type inference to manually infer K and V from T:

            Source https://stackoverflow.com/questions/70586968

            QUESTION

            Check if key exists in map storing large values
            Asked 2022-Jan-02 at 18:22

            To know a key k exist in a map M1[k]v is very straightforward in Go.

            ...

            ANSWER

            Answered 2022-Jan-02 at 18:04

            Use if _, ok := M1[k]; ok { }. If you use the blank identifier, the value will not be "loaded".

            Let's write benchmarks to test it:

            Source https://stackoverflow.com/questions/70557883

            QUESTION

            Add minimum available key to dictionary MongoDB
            Asked 2021-Dec-05 at 08:43

            I have documents in collection which have structure:

            ...

            ANSWER

            Answered 2021-Dec-05 at 08:43

            Here is a possibility (requires Mongo 4.2 or better):

            Source https://stackoverflow.com/questions/70077265

            QUESTION

            why could macros not understand a Dict parameter?
            Asked 2021-Nov-06 at 05:49
            macro test1(name,arg)
                println(arg.args[2])
                typeof(arg.args[2])
            end 
            
            @test1 test1 (
              (arg1, (:max=>10))
            )
            
            ...

            ANSWER

            Answered 2021-Nov-06 at 05:49

            This is because macros work on code before the code is compiled. Source code is first parsed to Symbols, literals (integers, floats, strings, etc), or Expr (expressions). At this point, all expressions contain only these three things.** After the macro is done and returns an expression, that expression is compiled into runtime code where more complicated objects like Dicts can exist.

            The code below illustrates the difference before and after compiling. Note how 1+5 and Dict() were expressions in the macro body, but is afterward evaluated to an Int64 and a Dict.

            Source https://stackoverflow.com/questions/69632506

            QUESTION

            Julia convert NamedTuple to Dict
            Asked 2021-Oct-30 at 13:52

            I would like to convert a NamedTuple to a Dict in Julia. Say I have the following NamedTuple:

            ...

            ANSWER

            Answered 2021-Oct-30 at 13:52

            The simplest way to get an iterator of keys and values for any key-value collection is pairs:

            Source https://stackoverflow.com/questions/69755763

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install python-llist

            You can download it from GitHub.

            Support

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