ShellShock | repository contains useful documents | Continuous Deployment library
kandi X-RAY | ShellShock Summary
kandi X-RAY | ShellShock Summary
This repository contains useful documents which I have written to help educate the cybersecurity community on the "ShellShock" bash vulnerability. These documents are designed to help facilitate learning, including on how to identify possibly vulnerable services and how to remediate such vulnerabilities.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of ShellShock
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QUESTION
My script generates multiple files that contain random names based on the info it extracts. I created this test to try and move all new files created while running into a new directory named after the file being ran.
When I use os.popen("mv " + moveFiles +' ' + filename + "_dir") it works just fine, but os.popen is considered insecure due to shellshock
When switching to cmd = Popen(["mv", str(moveFiles), filename + "_dir"]), I get the following error
mv: cannot stat '/home/test/testing/TestFile1.txt /home/test/testing/TestFile2.txt': No such file or directory
I believe this is due to it adding the apostrophe at the beginning and end of the moveFiles variable which tries to move it as 1 file rather than 2. So it works when a single file is created, but anymore results in the error. Is there a way to remove this?
...ANSWER
Answered 2021-Jul-24 at 14:22Your suspicion is correct: the problem is that you have two filenames joined together with a space. Since you're using Popen() and not os.popen() you're bypassing shell interpretation of the arguments, which means that individual filenames aren't getting separated. This is the same as if you had used quotes on the command line:
QUESTION
I'd like to know how to do 2 execution plans: "traditional" execution plan joins (A with B) and then C. The "new" plan joins (A with B) then (A with C) and then joins the result of those joins so there would be 3 joins. How would I code the traditional and new plan in Oracle SQLPlus given the code below? I also need to measure the time complexity of both methods to show that the new plan takes less time, which I believe I just do with set timer on; The joins can be on whatever attributes work. Same with select statements. I made a artist, b album, c track, and d played.
Here's the database:
...ANSWER
Answered 2021-Apr-18 at 06:13Your question doesn't make a lot of sense, because it's imposing bizarre restrictions that we can't really assess, but I don't mind telling you how to join two joins
You already know how to join three tables in the normal/traditional/sensible sense. Here's how to join them as you ask:
QUESTION
I am learning about the ShellShock vulnerability and I wanted to test older versions of Bash.
I downloaded Bash 4.2 from GNU website. After extracting the content, I compiled it based on GNU guide like that:
ANSWER
Answered 2020-Dec-02 at 10:32Use ./bash instead of bash; your current attempt ends up executing the default system Bash instance, which should hopefully indeed not be vulnerable.
As a rule, the current directory is not included in the PATH, and should not be, for reasons exactly like this.
QUESTION
So I have a data frame each row in cola contains movie info in a string like this:
"The Shellshock (2014) Budget: 35,000,000 Release Date: 10/11/2014 Screen Size: 2515 Enhaced 1.1 "
Im trying to extract the budget and the date in their own columns. The budget can range from 1,000,000 to 150,000,000 and the date is mm-dd-yyyy
The first regex is one I made but it's returning NaN values :'(
the second is one of a few I've tried from StackOverflow. It returns "Wrong number of items passed 3, placement implies 1". So it's matching to the other digits?
...ANSWER
Answered 2020-Jun-07 at 13:39You have several capture groups in your pattern, each of which returns a columns. So the first command gives you two columns, the second give you three. You cannot assign two/three-column data as a new column. Also, the ^ indicates the start of the string and $ the end. You don't want them since your patterns are in the middle.
You then can do something like this:
QUESTION
I am trying to create a vector for columns names of my data set. I opened the .csv file with note pad.
/app/csrf/;/app/xss/;/http/https_redirect/;/http/vulnerability/apache_expect_xss/;/http/vulnerability/apacheusers/;/http/vulnerability/cgi/;/http/vulnerability/clientaccesspolicy/;/http/vulnerability/content_search/;/http/vulnerability/cookies/;/http/vulnerability/dictionary/;/http/vulnerability/dir_traversal/;/http/vulnerability/docker_registry/;/http/vulnerability/domino/;/http/vulnerability/drupal/;/http/vulnerability/embedded/;/http/vulnerability/headers/;/http/vulnerability/httpoptions/;/http/vulnerability/ms10_070/;/http/vulnerability/multiple_index/;/http/vulnerability/negotiate/;/http/vulnerability/origin_reflection/;/http/vulnerability/outdated/;/http/vulnerability/put_del_test/;/http/vulnerability/shellshock/;/http/vulnerability/siebel/;/http/vulnerability/site_files/;/http/vulnerability/strutshock/;/malware/google/;/rdp/enumeration/;/smtp/open_relay/domain/;/ssh/auth_methods/;/ssl/cert/;/ssl/ciphers/;/ssl/mixed/;/tcp/timestamp/
Copied all columns to word. After that i converted all ; symbols to " , " symbol group.
“/app/csrf/” , “/app/xss/” , “/http/https_redirect/” , “/http/vulnerability/apache_expect_xss/” , “/http/vulnerability/apacheusers/” , “/http/vulnerability/cgi/” , “/http/vulnerability/clientaccesspolicy/” , “/http/vulnerability/content_search/” , “/http/vulnerability/cookies/” , “/http/vulnerability/dictionary/” , “/http/vulnerability/dir_traversal/” , “/http/vulnerability/docker_registry/” , “/http/vulnerability/domino/” , “/http/vulnerability/drupal/” , “/http/vulnerability/embedded/” , “/http/vulnerability/headers/” , “/http/vulnerability/httpoptions/” , “/http/vulnerability/ms10_070/” , “/http/vulnerability/multiple_index/” , “/http/vulnerability/negotiate/” , “/http/vulnerability/origin_reflection/” , “/http/vulnerability/outdated/” , “/http/vulnerability/put_del_test/” , “/http/vulnerability/shellshock/” , “/http/vulnerability/siebel/” , “/http/vulnerability/site_files/” , “/http/vulnerability/strutshock/” , “/malware/google/” , “/rdp/enumeration/” , “/smtp/open_relay/domain/” , “/ssh/auth_methods/” , “/ssl/cert/” , “/ssl/ciphers/” , “/ssl/mixed/” , “/tcp/timestamp/”
Last one i copied this columns to R
...ANSWER
Answered 2020-Feb-22 at 23:13This is because Word is using curly quotes instead of normal double quotes. R doesn't understand these. Try copying and pasting the following line into the R console (but don't run it)
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