calcium | Exact real and complex numbers in C | Math library

here you go

To parse JSON data you can use JMESPath library.
JMESPath search syntax:

Set.of() doesn't have a defined iteration order and it is subjected to change.

The iteration order of set elements is unspecified and is subject to change.

Collectors.toSet() doesn't define which Set implementation is used.

public static Collector> toSet()

Returns a Collector that accumulates the input elements into a new Set. There are no guarantees on the type, mutability, serializability, or thread-safety of the Set returned; if more control over the returned Set is required, use toCollection(Supplier).

Currently the supplier is hardcoded to HashSet::new. But it can change in the future. So if you need something predictable, better to pass a concrete Set implementation as supplier. Because it is returning HashSet currently and you are passing elements in same order while creating, iteration is returning the data in a particular order every time based on bucket locations. That's why the result is consistent.

You can use

You can use your own datasource like below

a. This is your custom datasource that you defined.

To get the contents of anova, you'll have to use $; anova()$****. Start by defining it as a variable, anova_var <- anova(calcium.aov), and then anova_var$ - then all you options will be there.

More elaborately,

You need to create a list and append to it. Currently, you are just overwriting with the last value.

Here's what you can do so you can search for different options:

Although I had not yet replicated this, I had been planning to do so for a long time. Now your question was a good reason and got me away from Netflix.

Here is a solution using lpSolveAPI: