Objectively | Object oriented framework and core library | iOS library

 by   jdolan C Version: Current License: Non-SPDX

kandi X-RAY | Objectively Summary

kandi X-RAY | Objectively Summary

Objectively is a C library typically used in Mobile, iOS, Framework applications. Objectively has no bugs, it has no vulnerabilities and it has low support. However Objectively has a Non-SPDX License. You can download it from GitHub.

Object oriented framework and core library for GNU C. Inspired by Objective-C. Zlib license.
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              Objectively has a low active ecosystem.
              It has 27 star(s) with 6 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 8 have been closed. On average issues are closed in 229 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Objectively is current.

            kandi-Quality Quality

              Objectively has 0 bugs and 0 code smells.

            kandi-Security Security

              Objectively has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Objectively code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Objectively has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              Objectively releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            Objectively Key Features

            No Key Features are available at this moment for Objectively.

            Objectively Examples and Code Snippets

            No Code Snippets are available at this moment for Objectively.

            Community Discussions

            QUESTION

            What is fundamentally wrong in the choice of data structure in this matrix addition code?
            Asked 2022-Apr-03 at 09:02

            Section 2.2.4 here contains the following:

            2.2.4 Totally Inappropriate Data Structures

            Some might find this example hard to believe. This really occurred in some code I’ve seen:

            ...

            ANSWER

            Answered 2022-Apr-02 at 13:35

            Lisp lists are singly-linked. Random access to an element (via nth) requires traversing all predecessors. The storage is likewise wasteful for this purpose. Working with matrices this way is very inefficient.

            Lisp has built-in multidimensional arrays, so a natural fit for this problem would be a two-dimensional array, which can access elements directly instead of traversing links.

            Source https://stackoverflow.com/questions/71717846

            QUESTION

            Return an Array of Only Numbers From a Range With Mixed Datatypes
            Asked 2022-Mar-26 at 21:59
            • Related to the following screenshot, the formula

              ...

            ANSWER

            Answered 2022-Mar-24 at 03:54

            QUESTION

            Go generics: where would I use any instead of interface{}?
            Asked 2022-Mar-26 at 18:42

            As generics have been released in Go 1.18 pretty recently, I've started learning them. I generally get the concept, because I have some Java experience from the past. But I don't get some implementation specifics.

            For instance: when it's more suitable to use any instead of interface{}? Here's an example:

            ...

            ANSWER

            Answered 2022-Mar-26 at 12:55

            any is an alias for interface{}. Spec: Interface types:

            For convenience, the predeclared type any is an alias for the empty interface.

            Since it is an alias, it doesn't matter which one you use. They are one and the same. They are interchangeable. You can replace one with the other, the code will mean the same.

            any is shorter and clearer, but only works from Go 1.18.

            Since they are interchangeable, this also works:

            Source https://stackoverflow.com/questions/71628061

            QUESTION

            Is `Object.freeze(Object.prototype)` only the hazard for extending `Object.prototype` with Symbols?
            Asked 2022-Mar-19 at 21:13

            So, fundamentally, this question is Not opinion-based. I seriously pursuit this issue objectively without feeling mostly arisen from the predominant opinion - Why is extending native objects a bad practice?

            and this quesion is related but unanswered questions:

            If Object.prototype is extended with Symbol property, is it possible to break code without specifically designed APIs to access Symbol in JavaScript?

            Should the extension of built-in Javascript prototypes through symbols also be avoided?

            The first question is already closed as they say it's opinion based, and as you might know in this community once a question is Banned, however we modified it, moderators will never bother to re-open. That is the way how the things work here.

            For the second question. For some unknown reason, the question has been taken more seriously and not considered as opinion based although the context is identical.

            There are two parts to the "don't modify something you don't own" rule:

            1. You can cause name collisions and you can break their code.

              By touching something you don't own, you may accidentally overwrite something used by some other library. This will break their code in unexpected ways.

            2. You can create tight dependencies and they can break your code.

              By binding your code so tightly to some other object, if they make some significant change (like removing or renaming the class, for example), your code might suddenly break.

            Using symbols will avoid #1, but you still run into #2. Tight dependencies between classes like that are generally discouraged. If the other class is ever frozen, your code will still break. The answers on this question still apply, just for slightly different reasons.

            Also, I've read opinions(how can we discuss such a thing here without "opinion" base?), they claim

            a) Library code Using Symbols exists and they may tweak Symbol API (such as Object.getOwnPropertySymbols())

            b) extending object property with Symbol is not different from non-Symbol property fundamentally.

            Here, for the major rationale of untouching Object.prototype is due to #1, almost all answers I saw claimed that and we don't have to discuss if there is no Symbol usage.

            However, Using symbols will avoid #1 as they say. So most of the traditional wisdom won't apply anymore.

            Then, as #2 says,

            By binding your code so tightly to some other object, if they make some significant change (like removing or renaming the class, for example), your code might suddenly break.

            well, in principle, any fundamental API version upgrade will break any code. The well-known fact is nothing to do with this specific question. #2 did not answer the question.

            Only considerable part is Object.freeze(Object.prototype) can be the remaining problem. However, this is essentially the same manner to upgrade the basic API by some other unexpectedly.

            As the API users not as API providers, the expected API of Object.prototype is not frozen.

            If some other guys touch the basic API and modifies it as frozen, it is he/she who broke the code. They upgraded the basic API without notice.

            For instance, in Haskell, there are many language extensions. Probably they solve the collision issue well, and most importantly, they won't "freeze" the basic API because freezing the basic API would brake their eco.

            Therefore, I observe that Object.freeze(Object.prototype) is the anti-pattern. It cannot be justified as a matter of course to prevent Object.prototype extension with Symbols.

            So here is my question. Although I observe this way, is it safe to say:

            In case of that Object.freeze(Object.prototype) is not performed, which is the anti-pattern and detectable, it is safe to perform extending Object.prototype with Symbols?

            If you don't think so, please provide a concrete example.

            ...

            ANSWER

            Answered 2022-Mar-17 at 03:18

            Extending the Object prototype is a dangerous practice.

            You have obviously done some research and found that the community of javascript developers overwhelmingly considers it to be a very bad practice.

            If you're working on a personal project all by yourself, and you think the rest of us are all cowards for being unwilling to take the risk, then by all means: go ahead and modify your Object prototype! Nobody can stop you. It's up to you whether you will be guided by our advice. Sometimes the conventional wisdom is wrong. (Spoiler: in this case, the conventional wisdom is right.)

            But if you are working in a shared repository, especially in any kind of professional setting, do not modify the Object prototype. Whatever you want to accomplish by this technique, there will be alternative approaches that avoid the dangers of modifying the base prototypes.

            The number one job of code is to be understood by other developers (including yourself in the future), not just to work. Even if you manage to make this work, it is counterintuitive, and nobody who comes after you will expect to find this. That makes it unacceptable by definition, because what matters here is reasonable expectations, NOT what the language supports. Any person who fails to recognize that professional software development is a team effort has no place writing software professionally.

            You are not going to find a technical limitation to extending the Object prototype. Javascript is a very flexible language -- it will give you plenty of rope with which to hang yourself. That does not mean it's a good idea to place your head in the noose.

            Source https://stackoverflow.com/questions/71505938

            QUESTION

            Abstracting reference containers (Rc, Arc, Box, ...)
            Asked 2022-Mar-14 at 08:17

            I've been hobby programming in Rust for a while now and there's something annoying me when I try to create abstractions. Here's a small example I made of the kind of code I end up with when writing a program in a dependency injection style:

            ...

            ANSWER

            Answered 2022-Mar-14 at 08:17

            Rust is not designed for Java's dependency injection mindset, indeed.

            UserService is now aware of the fact that UserDatabase is used elsewhere. The UserService only needs the UserDatabase to call 1 function. Why should it have to be aware of the fact that the UserDatabase is referenced elsewhere?

            Because this is exactly the kind of things Rust wants to be explicit about.

            This is not just a limitation: Rust wants you to know who owns your objects. The ownership system should design your mind and your program. This "share-style" is indeed not very Rusty - and one of the reasons Rc and friends are not commonly seen in idiomatic Rust (they do appear, but not at the same amount as GC'd languages).

            Do not think about services - think about data. Instead of asking who needs access to the user database, ask of whom it is. The owner does not inject the DB to whoever needs it, he just let them take a look. If main() owns the database, the services should take a reference to it (or not exist at all). If both services own it, it should be Rc. Either way, you have to be explicit about that. And that's a good thing!

            Source https://stackoverflow.com/questions/71453504

            QUESTION

            Should async method always call await, if not what is the implication?
            Asked 2022-Mar-05 at 03:03

            In this example,

            ...

            ANSWER

            Answered 2022-Mar-05 at 03:03

            The async keyword on the method is mearly an indicator to the compiler that the code inside the method should be converted into a state-machine with state transitions at the awaits.

            The only technical down-side, that I am aware of, to having an async method that doesn't await anything, is the small amount of overhead introduced by the state-machine. It should have no negative effects, other than a very small performance impact, and a tiny bit of memory-pressure, that can most likely be ignored in your scenario.

            Source https://stackoverflow.com/questions/71355465

            QUESTION

            c++ testing if one file is older than a set of files
            Asked 2022-Mar-01 at 07:43

            I am creating a cache for some data, but of course I want the cache to become invalid if any of the source files from which the cache is made is modified. TO that effect I made this function:

            ...

            ANSWER

            Answered 2022-Mar-01 at 06:01

            due to you want to find youngest_file_ts -> find most recently timestamp (greater number) of a changing file however

            Source https://stackoverflow.com/questions/71303617

            QUESTION

            Try/Catch everything and rethrow Business Exceptions
            Asked 2021-Oct-02 at 17:00

            Imagine some code:

            ...

            ANSWER

            Answered 2021-Oct-01 at 14:17

            It is like, the end user doesn't know what to do with exception so a generic exception will be better.

            You can write diff custom exceptions for diff type of operations, like Database calls, api calls and return only one type of exception to the caller.

            i.e You can define you custom exception like this.

            Source https://stackoverflow.com/questions/69407009

            QUESTION

            How do I determine the optimum variable weights when ranking the "best" candidate for a prize
            Asked 2021-Sep-24 at 23:26

            Consider I am writing a program to objectively select a winner in a competition. There are 'n' human judges secretly assigning a 1st, 2nd, 3rd position ranking to the top three candidates from a pool of 'm' candidates.

            The program must then go through the judges decisions, and based on weights assigned to 1st place, 2nd place and 3rd place, each candidate will be rated based on the number of 1st, 2nd, and 3rd place votes they received, multiplied by the appropriate rating for each finishing position.

            However, at the start, the program has no idea of what weights are appropriate, so I have created an automated "program" that is intended to "discover" the proper weights based on how the judges would pick the winner from a hypothetical situation.

            I present a table where the horizontal axis contains the finishing position, and the judges' codes (e.g. Judge W, Judge X, Judge Y, Judge Z). The vertical axis has three rows (1st place, 2nd place, 3rd place), and at the intersection of each Judge/Row, I have randomly generated a candidate ID (from the set A through F).

            After rendering the table, I then ask the judge who THEY would have chosen as the winner (the judge has the option to PASS if there is not sufficient information to choose).

            After the judges run through an appropriate number of scenarios, I wish to now take the results of the various runs and use that information to determine the "best fit" for the weighting of 1st, 2nd, and 3rd positions.

            Let's say one of the hypothetical grids looks like this:

            ...

            ANSWER

            Answered 2021-Sep-24 at 23:26

            For the winning candidate count how many times he appears in each position, then do the same for all the other candidates. Then write the following formula for each candidate:

            Source https://stackoverflow.com/questions/69317854

            QUESTION

            how to refactor string.contains logic
            Asked 2021-Jul-16 at 16:12

            I have inherited some code that upon first glance smells funny, but perhaps I'm reading into it... while reviewing the code I came across the following and made a note to consider refactoring the logic as I found it difficult to read and prone to errors.

            ...

            ANSWER

            Answered 2021-Jul-16 at 16:12

            I suggest extracting a model, e.g.

            Source https://stackoverflow.com/questions/68411883

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Objectively

            You can download it from GitHub.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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