ureq | Micro C library for handling HTTP requests | HTTP library
kandi X-RAY | ureq Summary
kandi X-RAY | ureq Summary
Micro C library for handling HTTP requests on low resource systems. Please note that ureq is still in heavy development and new features are continuously added. Despite this, it behaves very well in stability tests and current user-end interface won't be probably changed.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of ureq
ureq Key Features
ureq Examples and Code Snippets
Community Discussions
Trending Discussions on ureq
QUESTION
I'm trying to use BS4 to parse through the HTML for an about page on a youtube channel so I can scrape the number of channel views. Below is the code to scrape the channel views (located in the 'yt-formatted-string') and also the whole right column of the page. Both lines of code return either an empty list and a "None" value for the findAll() and find() functions, respectively.
I read another thread saying I may be receiving an empty list or "None" value because the page is accessing an API to get the total channel views to count and the values aren't actually in the HTML I'm parsing.
I know I could access much of this info through the Youtube API, but I want to iterate this code over multiple channels that are not my own. Moreover, I want to understand how to use BS4 to its full extent so I can replicate this process on an Instagram page or Facebook page.
Should I be using a different library that isn't BS4? Is what I'm looking to accomplish even possible?
My CODE
...ANSWER
Answered 2021-Jun-15 at 20:43YouTube is loaded dynamically, therefore urlib
won't support it.
However, the data is available in JSON format on the website. You can convert this data to a Python dictionary (dict
) using the built-in json
library.
This example is using the URL you have provided: https://www.youtube.com/c/Rozziofficial/about, you can change the channel name, it will work for all channels.
Here's an example using requests
, you can use urlib
instead:
QUESTION
I've tried various ideas and I always come back to 2 main results that are wrong. I don't know where I'm going wrong.
...ANSWER
Answered 2021-Jun-01 at 06:10Use zip
to iterate over multiple objects at once instead of nested loops. You will get a tuple of (point, team). Also, eliminate the loop counter variable n
by using enumerate
. This makes your code more pythonic. Check out the corrected code below:
QUESTION
I want to extract "automatically" some information (such as "Date", "Court", "Street"...) from a web page. I want to use Beautiful soup to extract these information.
However, i have some problems using the following code:
...ANSWER
Answered 2021-May-29 at 18:17Here you go dude
QUESTION
I'm trying to build a web scraper with bs4, everything works fine except when the item is on a discount, it outputs the discount %, not the price and I can't figure out how to get the price.
...ANSWER
Answered 2021-May-29 at 08:58The structure of the priceInner is as follows
QUESTION
I am trying to access the live price of a crypto currency coin from an exchange webpage through python.
The XPath of the value I want is in /html/body/luno-exchange-app/luno-navigation/div/luno-market/div/section[2]/luno-orderbook/div/luno-spread/div/luno-orderbook-entry[2]/div/span/span
and I have been doing the following
ANSWER
Answered 2021-May-29 at 04:11It is dynamically added from an ajax request
QUESTION
I'm having trouble getting the div
for each pet in this website: https://indyhumane.org/adoptable-cats/ while trying to scrape details using python and Beautiful Soup
When I inspect the page and check the html source code, I see that the div
containing each pet profile is with a class = "mbcpp_result_animal"
, but when I use the code below, I get zero for the length of the containers
ANSWER
Answered 2021-May-14 at 05:17Because that comes from an additional API call the page makes to retrieve results and update the page. The call has querystring params you can see as follows.
It includes the API endpoint, an api key, criteria to restrict the search and a final random number param, presumably to avoid being served cached results. You could introduce an actual random number.
QUESTION
from bs4 import BeautifulSoup as soup
from urllib.request import urlopen as uReq
web_scrape = 'https://thehackernews.com/'
uClient = uReq(web_scrape)
page_html = uClient.read()
uClient.close()
page_soup = soup(page_html, 'html.parser')
...ANSWER
Answered 2021-Apr-06 at 22:43feedparser
allows you to to check the last-modified headers of the rss feed to check for new messages. It will only return messages if new messages have been posted since the last request. This allows for a low-bandwith solution without any scraping.
QUESTION
I am stuck on this website. I've done some small codes to learn about BeatifulSoup
for the past week, I did some research on how to use it and the respective official documentation. Not only that, but review some tutorials and videos on how to parse a table from websites. I've parsed data from tables using the methods soup.find()
and soup.select()
from several websites such as:
for example, for the MLB stats website I used the following code:
...ANSWER
Answered 2021-Mar-29 at 19:18Problem: The page uses javascript to fetch and display the content, so you cannot just use requests or other similars because javascript code would not be executed.
Solution: use selenium in order to load the page then parse the content with BeautifulSoup.
Sample code here:
QUESTION
I have a lot of code using ureq for http requests and I'm wondering if I can avoid using another http library.
I have a list of urls and I'm invoking ureq::get on them. I'm wondering if I can somehow make these calls in parallel. How would I create separate threads and execute these in parallel?
...ANSWER
Answered 2021-Mar-24 at 09:50You can just use rayon. It's not ideal because it assumes CPU-bound work and will therefore spawn one thread per (logical) core by default, which may be less than you'd want for HTTP requests, but you could always customise the global threadpool (or run your work inside the scope of a local threadpool with a higher thread count).
QUESTION
I'm trying to get content from a url and parse the response using BeautyfulSoup.
This url when loaded it retrieves my favourite watchlist items, the problem is that when the site loads it takes a couple of seconds to displays the data in a table, so when I run urlopen(my_url)
the response has no table, therefore my parsing method fails.
I'm trying to keep it simple as I'm learning the language so I would like to use the tools I've already setup in me code so based on what I have I wonder if there is a way to wait, or check when the content is ready for me to be able to fetch the data (table content).
Here is my code:
...ANSWER
Answered 2021-Feb-21 at 11:21As mentioned in the comments, urllib.request
is quite ancient, and Selenium
can handle javascript:
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