kh | executing shell scripts | Continuous Deployment library
kandi X-RAY | kh Summary
kandi X-RAY | kh Summary
The King's Hand (kh) is a tool for organizing and executing shell(ish) scripts written in Go
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Top functions reviewed by kandi - BETA
- main is the main function .
- showHelp displays the help for the King
- Initializes the HandHome directory
- parseFlagsAndArgs parses the command line arguments and returns the arguments .
- findFingerDescription returns the name of the sensor
- resolvePath returns the real path of the given path
- linkFingerToHome creates a symlink to the given name
- makeArgs builds FingerArgs from the given command line arguments .
- doInstall executes the passed arguments
- makeHand creates a hh . Hand from the home directory .
kh Key Features
kh Examples and Code Snippets
Community Discussions
Trending Discussions on kh
QUESTION
I know that this is close to a duplicate but I can't get the code to work. I have an object that I need to filter and I'm currently trying to emulate the accepted as an answer the code at Javascript filtering nested arrays
My data object is:
...ANSWER
Answered 2022-Apr-11 at 15:27You can try doing like this:
QUESTION
I am coding a script that is going to test all free proxies available on: https://free-proxy-list.net/
On this site there is a list with all available proxies, and I managed to make my script print them all but, I only want to print the proxy value if https is enabled.
This is how the Html looks when https is enabled:
...ANSWER
Answered 2022-Mar-16 at 15:54You can filter it using xpath //td[@class='hx' and text()='yes']/.. , this xpath will only check for class hx and text()='yes'
Code:
QUESTION
How to make nuget package:moderenwpfui generate only needed language files.
The repository for this nuget package is https://github.com/Kinnara/ModernWpf .
When I generate my app, a lot of language files will be generated. Is there a way to generate only the language I need or preset the language file to the language I use?
The following are all the files generated in the Debug directory, the one without the suffix is the folder, the folder contains the dll library for the language files
ANSWER
Answered 2022-Feb-09 at 09:30Under Project>References you will find ModernWpf and ModernWpf.Controls. You need to set the property Copy Local to False for both of them.
Before you do that, backup these files and copy them manually to debug folder after doing the above steps.
QUESTION
I am trying to plot some geo data using the Plotly function in a shiny app. The problem is I selected point in the map, does not happen correctly as shown follows:
According to the above figure, the selected point "NOE_TASAODF" label is "KH"(on map side) and it does not coincide with the info returned from plotly. Here is the code:
...ANSWER
Answered 2022-Jan-18 at 11:21You can use the customdata argument to pass a unique identifier in this case I passed ID2 from your data.frame - please see the click event:
QUESTION
From this page: https://www.realestate.com.kh/buy/, which looks like this in the inspector:
I'm trying to extract all elements of class css-1uuzwjq eq4or9x0 into a list in order to click on the elements and further explore.
I have this code, in which I try to get the elements by their Xpath:
...ANSWER
Answered 2021-Dec-18 at 02:17//div[@class='list']/div[./header[contains(@class,'featured')]]
QUESTION
I need to find russian names and surnames in english text. I tried SpaCy NER, but it matches only english names (for instance, John Brandon), but not russian (like Vitaliy Ivanov).
I use the transliterate python library to translit english text to russian and then apply russian Spacy nlp model to get names by NER.
But i get different result for the string 'Ivanov Vitaliy' and the same string gotten by transliteration.
The code is as follows:
...ANSWER
Answered 2021-Nov-22 at 19:00You forgot to define the o letter mapping.
Here is the fix:
QUESTION
I am making a program where I want to take an image and reduce its color palette to a preset palette of 60 colors, and then add a dithering effect. This seems to involve two things:
- A color distance algorithm that goes through each pixel, gets its color, and then changes it to the color closest to it in the palette so that that image doesn't have colors that are not contained in the palette.
- A dithering algorithm that goes through the color of each pixel and diffuses the difference between the original color and the new palette color chosen across the surrounding pixels.
After reading about color difference, I figured I would use either the CIE94 or CIEDE2000 algorithm for finding the closest color from my list. I also decided to use the fairly common Floyd–Steinberg dithering algorithm for the dithering effect.
Over the past 2 days I have written my own versions of these algorithms, pulled other versions of them from examples on the internet, tried them both first in Java and now C#, and pretty much every single time the output image has the same issue. Some parts of it look perfectly fine, have the correct colors, and are dithered properly, but then other parts (and sometimes the entire image) end up way too bright, are completely white, or all blur together. Usually darker images or darker parts of images turn out fine, but any part that is bright or has lighter colors at all gets turned up way brighter. Here is an example of an input and output image with these issues:
Input:
]3
Output:
I do have one idea for what may be causing this. When a pixel is sent through the "nearest color" function, I have it output its RGB values and it seems like some of them have their R value (and potentially other values??) pushed way higher than they should be, and even sometimes over 255 as shown in the screenshot. This does NOT happen for the earliest pixels in the image, only for ones that are multiple pixels in already and are already somewhat bright. This leads me to believe it is the dithering/error algorithm doing this, and not the color conversion or color difference algorithms. If that is the issue, then how would I go about fixing that?
Here's the relevant code and functions I'm using. At this point it's a mix of stuff I wrote and stuff I've found in libraries or other StackOverflow posts. I believe the main dithering algorithm and C3 class are copied basically directly from this Github page (and changed to work with C#, obviously)
...ANSWER
Answered 2021-Sep-19 at 07:08It appears that when you shift the error to the neighbors in floydSteinbergDithering() the r,g,b values never get clamped until you cast them back to Color.
Since you're using int and not byte there is no prevention of overflows to negative or large values greater than 255 for r, g, and b.
You should consider implementing r,g, and b as properties that clamp to 0-255 when they're set.
This will ensure their values will never be outside your expected range (0 - 255).
QUESTION
I am working with below code in php to show the arabic letters in roman ABCD characters as defined below in my code.
But it is not displaying properly. It is losing the character sorting also and not displaying some of the characters according to my string.
it is showing as _space_aabtkhlmn and it should show as khatm_space_alanbyaa.
I can not figure it out where i am wrong.
Please help why it is showing wrong?
...ANSWER
Answered 2021-Sep-07 at 15:52Your logic splits the string into characters separated by commas. It then checks if space is anywhere in the string, and if so print _space_, and then checks if ء is anywhere in the string, and if so, print "a", and then checks if ا is anywhere in the string, and if so, print "aa." This is going to print the results in the order you test in, not the order of the string.
What I believe you meant to do is this:
QUESTION
This question has been around for while, but I still have a question please. I will discuss the following solution.
Question: Prove that no matter what node we start at in a height-h binary search tree, k successive calls to TREE-SUCCESSOR take O(k + h) time.
Given tree successor algorithm below, that given an x, it will find it's left-most node of right-subtree of x:
Assumptions: Assuming that the worst-case running time of TREE-SUCCESSOR() is O(h), where h is the height of binary search tree and the tree will not be changed between successive calls of the method. The worst case happens when next successor is a leaf at depth h.
You need to call once the method to get the next successor and you need O(h) time for that. Once when you have the next successor you simply can store it and for every other call, you can return it in O(1). Since, you have k−1 remaining calls, the running time is O(k). Combining with the above, you have that the total running time is O(h)+O(k)=O(k+h).
Question: I am not sure by the last statement about how we got running time O(k) please? I assume k successive calls to TREE-SUCCESSOR() means that we are calling it k times on probably same or different nodes? If that is the case, we know that worst time for TREE-SUCCESSOR is O(h), so how we got a total time of O(h+k) please? I can see that if we call TREE-SUCCESSOR() k times, then we should get worst-case of O(kh).
Edit: I would assume probably that k succissive calls to TREE-SUCCESSOR() means: TREE-SUCCESSOR()+⋯+TREE-SUCCESSOR(): k times?
ANSWER
Answered 2021-Aug-12 at 01:41It's commonly known that an in-order traversal of a binary tree takes O(n) time using this method. Your problem is to prove the equivalent statement for partial traversals of a binary tree.
A weaker version of the statement you have to prove is that the amortized cost of each successive call is O(1). I would prove that statement using the potential method. A similar method can be used for the proof you need:
To show that k successive calls require O(k+h) time, we find a "bank function" B that operates on the current node, and show that:
- The time required for y = TREE-SUCCESSOR(x) is in O(1 + B(y) - B(x)); and
- 0 <= B(x) <= h for all x
It follows from (1) that after k successive calls such that y = TREE-SUCCESSORk(x), the total time is in O(k + B(y)-B(x)), and it follows from(2) that B(y)-B(x) is in O(h), so this proves that the time is in O(k + h)
A bank function that works is B(x) = (h + dL(x) - dR(x))/2, where dL is the number of left-child links on the path from root to x, and dR is the number of right-child links on the path from the root to x.
Consider the cases of non-bounded work in TREE-SUCCESOR(x):
- When x has a right child, the extra work is proportional to the number of left-child links added in TREE-MINIMUM. That is the change in dL. The number of right-child links increases by only 1, so the extra work is proportional to the change in B.
- When x has no right child, the extra work is proportional to the number of right-child links we remove by traversing to the parent. That is the decrease in dR. The number of left-child links changes by only 1, so again the extra work is proportional to the change in B.
Those are the only two cases, and in both cases we have total work in O(1 + B(y) - B(x)). Condition 1 is true. Condition 2 is also trivially true from the definition of B, so the statement is proven.
QUESTION
Consider following data frame:
...ANSWER
Answered 2021-Aug-09 at 07:54You can use the following solution. This output is close to what you are looking for as R's data frames cannot have multiple headers, however, we could of course use package kableExtra to produce a table with multiple headers:
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