bane | better AppArmor profile generator for Docker containers | Continuous Deployment library

 by   genuinetools Go Version: v0.4.4 License: MIT

kandi X-RAY | bane Summary

kandi X-RAY | bane Summary

bane is a Go library typically used in Devops, Continuous Deployment, Docker applications. bane has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

AppArmor profile generator for docker containers. Basically a better AppArmor profile, than creating one by hand, because who would ever do that. "Reviewing AppArmor profile pull requests is the bane of my existence" Jess Frazelle.
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              bane has a medium active ecosystem.
              It has 1094 star(s) with 83 fork(s). There are 34 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 3 open issues and 4 have been closed. On average issues are closed in 9 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of bane is v0.4.4

            kandi-Quality Quality

              bane has no bugs reported.

            kandi-Security Security

              bane has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              bane is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              bane releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            bane Key Features

            No Key Features are available at this moment for bane.

            bane Examples and Code Snippets

            No Code Snippets are available at this moment for bane.

            Community Discussions

            QUESTION

            In Dataweave 2.0 how to create nested array from flat array - Mule 4
            Asked 2021-Jun-14 at 18:33

            I need to create a nested array using the response received from different API. I have this flat array, with all the data. What would be the best approach to create a nested array where the children are nested to its parent based on its result status.

            Input JSON flat array as follows:

            ...

            ANSWER

            Answered 2021-Jun-11 at 12:36

            A quick and easy way could be as follows:

            Script

            Source https://stackoverflow.com/questions/67933291

            QUESTION

            How do you configure JBOSS to allow port 8080 over HTTPS?
            Asked 2021-Jun-10 at 15:15

            I have a JBOSS server (7.0) running an application that uses ServiceWorkers, which requires an HTTPS connection. I was able to update the standalone.xml and Eclipse launch configuration to bind my JBOSS server to my local IP (I'll worry about port forwarding later). Connecting to http://192.168.0.197:8080/[application] works just fine, except that ServiceWorkers won't start because it isn't an HTTPS connection. If I try https://192.168.0.197:8080/[application], the connection fails with the browser reporting "unable to connect".

            I've researched several documentation sources and can't figure out what needs to be updated. Please forgive any terminology errors - my background is with application programming and networking tends to be the bane of my existence.

            This is the pertinent standalone.xml configuration:

            ...

            ANSWER

            Answered 2021-Jun-10 at 15:15

            It's there in your configuration:

            Source https://stackoverflow.com/questions/67893694

            QUESTION

            How do i get string from Entry in tkinter? I use .get(), but it only returns 0
            Asked 2021-May-22 at 15:53

            I have trouble returning results from Entry in tkinter. I do not use it immediately after creating tne Entry:

            ...

            ANSWER

            Answered 2021-May-22 at 15:02

            The problem lies in the fact that you don't remember the Entry widgets. You just store them to a local variable in function enchwind() and don't store them anywhere. They are created but you lose all reference.

            You could use a list as an attribute of window to store them:

            In the definition of your window, add the line:

            Source https://stackoverflow.com/questions/67650828

            QUESTION

            Python: Need Help Debugging Relatively Simple Function
            Asked 2021-Mar-07 at 21:47

            Below is the simple function I am working on.

            When I execute the 3 tests called out as examples in the specification, I get an error on the 3rd test (crane to bane).

            I know that the error is specifically in the after variable as I would expect that to just be ane and instead, I am seeing rane printed when I run the test.

            I have tried the following and each time, these changes have caused unintentional errors in the first two tests called out in the specification.

            ...

            ANSWER

            Answered 2021-Mar-07 at 21:46

            The reason why your code is not working for crane to bane is because you are not taking into account the length of the input of a (in this case cr, therefore length of 2) here:

            Source https://stackoverflow.com/questions/66521629

            QUESTION

            fail2ban - how to ban ip permanently after it was baned 3 times temporarily
            Asked 2021-Mar-03 at 15:22

            Have set up fail2ban service on CentOS 8 by this tutorial: https://www.cyberciti.biz/faq/how-to-protect-ssh-with-fail2ban-on-centos-8/.

            I have set up settings similiarly according to tutorial above like this:

            ...

            ANSWER

            Answered 2021-Mar-03 at 15:22

            A persistent banning is not advisable - it simply unnecessarily overloads your net-filter subsystem (as well as fail2ban)... It is enough to have a long ban.

            If you use v.0.11, you can use bantime increment feature, your config may looks like in this answer - https://github.com/fail2ban/fail2ban/discussions/2952#discussioncomment-414693

            Source https://stackoverflow.com/questions/66392687

            QUESTION

            Plotting balls of the Diestel-Leader graphs
            Asked 2020-Dec-05 at 18:51

            (I'm sorry if the question involves too much Mathematics, that's the bane of Mathematical programmation !)

            My goal is to visualize finite radii balls in the Diestel-Leader graph DL(p,q). Here is an article by W. Woess which describes with pictures the construction (starting from page 3). I will however give it here with less mathematics to capture the idea.

            It is constructed by taking two infinite trees Tp and Tq, each of respective valence p+1 and q+1. We consider height functions h:TpZ and h':TqZ, meaning that each vertex x with height k has exactly one parent vertex with height k-1 and exactly p (resp. q) children with height k+1.

            Now, the vertex set of DL(p,q) is defined to be {(x,y)∈Tp×Tq : h(x)+h'(y)=0}, and two vertices (x,y) and (x',y') are adjacent in DL(p,q) if and only if x and x' are adjacent in Tp and y and y' are adjacent in Tq.

            It turns out DL(p,q) is not a tree ! Balls whose radii are greater than 4 always have non-contractible loops.

            I am fixing arbitrary elements oTp and o'∈Tq whose heights are zero, and I am willing to plot the sub-graph of DL(p,q) consisting of elements whose distance to (o,o') is at most a certain radius R (that is the ball of radius R). This means that I must find all elements of distance at most R to o in Tp, and of distance at most R to o' in Tq, and then somehow get the adjacencies between couples of such vertices.

            Also, I am mainly concerned about the case p=2 and q=3, that is DL(2,3). However, an algorithm in the general case would be more than welcome !

            So far, I first tried finding a representation for elements in Tp. I tried implementing the representation given in the paragraph (2.1) Tree and sequences. in the article I linked, but even that seemed doomed. Then, I thought about taking a vertex at height -R, and represent all its children up to the generation R (that is, I would have 2R+1 generations of vertices). To represent a child of a vertex, this corresponds to labelling all the downwards edges with an integer from 0 to p-1. I first used a dec2base conversion algorithm :

            ...

            ANSWER

            Answered 2020-Dec-05 at 18:51

            It turns out I was very close to finishing ! It boiled down to writing the definition of the edge set for the Diestel-Leader graph :

            E[DL(p,q)]={(e1,e2)∈E[TpE[Tq] : h(i(e1))+h'(i(e2))=h(t(e1))+h'(t(e2))=0}

            with i(e) denoting the initial vertex of the edge e and t(e) the terminal edge. Therefore, I simply looped through all edges of both trees and checked for that condition :

            Source https://stackoverflow.com/questions/65153003

            QUESTION

            Const shows as NaN
            Asked 2020-Nov-10 at 14:20

            I am working on a random name feature for naming items, Now i have everything working, Except one piece in the code, Where it displays a const as NaN, Here is my code;

            ...

            ANSWER

            Answered 2020-Nov-10 at 14:20

            There are many things wrong with your code

            1. You declare nameOneCompleted inside your if so it's undefined elsewhere. Same for nameTwoCompleted. You should define them in the upper scope
            2. Your if condition is always truthy thus useless
            3. Use const and let instead of the deprecated var
            4. You don't need to do 10 ifs, just define an array and pick the n-th element
            5. Use camel case when naming js variables: its nameDecode2, not NameDecode2
            6. nameDecode2 was a string of several characters, you probably meant to only take the first one, you don't need to slice nameDecode1 for that btw, just use string index. Also convert it to a number before indexing the string.
            7. Don't slice when building substrings, just use substring, it's much easier
            8. I don't know what you tried to do with the ellipsis but it was wrong, also be aware that the CSS text-overflow: ellipsis might come more handy than trimming the string on the JS side

            That should be good:

            Source https://stackoverflow.com/questions/64770206

            QUESTION

            How to add a server name to a discord.py command
            Asked 2020-Nov-02 at 06:12

            Hello I was wondering how I can add in my bots kick command and the rest, the server name or (Guild) they were kicked/baned/warned. From or in...

            This is in DM's and the channel the command was used...

            My Code:

            ...

            ANSWER

            Answered 2020-Nov-02 at 06:12

            QUESTION

            How to get one random object from multiple arrays with percent chance in Javascript?
            Asked 2020-Oct-25 at 10:42

            Let's say I have 3 arrays of objects:

            ...

            ANSWER

            Answered 2020-Oct-25 at 10:20

            You would need to get two random numbers - the first to decide which group to pick and the second to pick that an item from that. To give one group a higher chance of being picked, the first random number needs to be from a range 1-100 (to allow for percentages) and the group is then determined by a range within that.

            For example, to give the fruits group an 80% chance of being picked:

            Source https://stackoverflow.com/questions/64522542

            QUESTION

            I have an array in a json and when I try to access it with the following code it has an error for multiple words. Can anybody help fix the code
            Asked 2020-Oct-25 at 06:47

            The error code it shows is:

            ...

            ANSWER

            Answered 2020-Oct-25 at 06:47

            If spellname is not in spell.spelldictionary, i becomes spell.spelldictionary.length after the for loop, and the execution of msg.channel.send(spell.spelldictionary[i][1]) causes the error.

            You can avoid it by moving msg.channel.send before break in the for loop, so that no message will be sent in this case. Also, it is better to explicitly declare i before using it, or it may cause some unexpected bugs after your code becomes more complicate.

            Source https://stackoverflow.com/questions/64516910

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install bane

            For installation instructions from binaries please visit the Releases Page.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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