jki | 构建 Docker image(当 Docker daemon 支持 buildkit 的时候自动启用 | Continuous Deployment library
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[2.7 自动替换修复 deployment 不能访问的镜像] #27-自动替换修复-deployment-不能访问的镜像).
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of jki
jki Key Features
jki Examples and Code Snippets
$ jki config init --save
$ jki config edit
$ jki config view
default-registry: ali
registries:
- name: ali
aliyun:
# 如果使用 access key 的话这里就不用设置
# 用户名、密码请用子账号访问 https://cr.console.aliyun.com/cn-hangzhou/instances/credentials 获取
#username:
curl -s https://api.github.com/repos/iftechio/jki/releases/latest \
| grep browser_download_url \
| grep darwin \
| cut -d '"' -f 4 \
| wget -i -
tar --strip-components=1 -xf jki*
sudo cp jki /usr/local/bin/
Community Discussions
Trending Discussions on jki
QUESTION
I have strings as below.
ABC//DEG//IJK//LMN//OPQ//rstuvwxyz
BCA//EGD//JKI//MNL//PQO//stuvwxyzr
ACB//DGE//IJK//LNM//OQP//rstuvwxyz
ABC//DEG//IJK//LMN//OPQ//rstuvwxyz
CAB//GDE//KIJ//NLM//QOP//rstuvwxyz
BAC//EDG//JIK//MLN//POQ//rstuvwxyz
I want it to be like this,
ABC//DEG//IJK\\LMN//OPQ//rstuvwxyz
BCA//EGD//JKI\\MNL//PQO//stuvwxyzr
ACB//DGE//IJK\\LNM//OQP//rstuvwxyz
ABC//DEG//IJK\\LMN//OPQ//rstuvwxyz
CAB//GDE//KIJ\\NLM//QOP//rstuvwxyz
BAC//EDG//JIK\\MLN//POQ//rstuvwxyz
I have tried
Find what ^.+?\K//
Replace with: \\\\
But this will only change the first occurrence of slash,,,
And I have tried this,
Find what: ^.+\K//
Replace with: \\\\
And this will replace the final slash at the end of every lines ..
I tried also {3} curly brackets with numbers, but no benifits....
Thanks in advance for your helps....
ANSWER
Answered 2021-Mar-15 at 11:28You can use
QUESTION
I have a collection 'collectionName' with many documents like these:
...ANSWER
Answered 2020-Jul-29 at 05:59You can use $addFields to calculate last sent date. $arrayElemAt takes -1
as a parameter which represents the last item of an array:
QUESTION
ANSWER
Answered 2020-May-23 at 17:16If the JSON VI does not know how to interpret the data from the express VI, it can't convert it into JSON. For example, the LabVIEWs native JSON VIs can not de/encode timestamps, since JSON does not have a timestamp data type. An additional convention on how to store timestamps would be necessary, such as seconds since 1970 or a string in ISO time format.
It is even possible that the data wire just contains some references, and storing the reference gives you nothing.
If you convert the express data to a more basic datatype like waveform, the JSON VI should be able to encode it.
QUESTION
I have a file with almost 2 hundred columns, each with a varying number of rows similar to the following (but approximately 80 rows in length):
...ANSWER
Answered 2020-Feb-13 at 07:25It's long enough to do in pure awk
that it's easier to throw it all in a script file of its own instead of doing it as a one-liner:
QUESTION
I have the following table called Stores:
...ANSWER
Answered 2019-Mar-27 at 09:34use where
condition
QUESTION
I am trying to make a simple word game. The idea is user clicks a button and server generates a letter and stores it in an array, and that process repeats ten times (temporary workaround i used below is that i generate all 11 letters at once). Now from the chosen letters user comes up with the longest word he/she can and user then submits the word, and computer checks whether the word is in the dictionary, if it is, it says 'Success' if it isn't, it says 'xzy word doesn't appear in our dictionary.' I am not looking for for all the checks, and security checks, just that a) computer stores the letter in an array as user clicks the button b) computer does the check if user subbmited word is in predifined dictionary (which is in separate .txt file).
Problem(s) i am having at the moment is that every time i click the button all my arrays get overwritten either with new letter, or are just empty. I suspect that the act of submiting is reseting everything, but i can't seem to make the program remember what letters were chosen and doesn't check if word exists in my dictionary. How one would go about storing stuff permanently? the code is below.
...ANSWER
Answered 2019-Feb-18 at 17:56You can store $PosLetters in a $_SESSION. Then each time the page refreshes, you first read out the array from the session before continuing. http://php.net/manual/en/reserved.variables.session.php
QUESTION
A column in a pandas dataframe contains lists of values.
Using a dictionary, I would like to create a new column with mapped values using the dictionary, and for any values not in the dictionary, those values are removed.
Here is a minimal example:
Set up of the dataframe
...ANSWER
Answered 2018-Sep-10 at 02:45You can try with apply
and lambda
:
QUESTION
This is a follow up to this question
How to map a unique number to each unique string in a column of lists
Which asks how to map a unique number to items across multiple pandas columns containing lists.
The solution given seems to be very slow when the number of items (total of items in column A and column B) is in the range of ~40 million. I have found some ways that can assign unique numbers to datasets for ~40 million items faster, but none quite for the situation of multiple columns , one of which contains a list.
Here was the minimal example and solution from the link above:
Setting up the dataframe
...ANSWER
Answered 2018-Sep-10 at 01:18The inefficiency comes from the latitude I took to construct various portions. I can improve performance with a few tweaks
QUESTION
In a pandas dataframe, I have a column where each row contains a list of strings. For each unique string in, I would like to assign a unique number.
If possible, I would like to assign a unique number to each unique string in multiple columns.
Here's a minimal example:
Setting up the initial pandas dataframe
...ANSWER
Answered 2018-Sep-08 at 05:12pandas.factorize
and numpy.split
QUESTION
I'm trying to check if the html tag:
...ANSWER
Answered 2018-Aug-21 at 06:17CSS selector:
You can use a CSS selector combination to target the element of interest.
The data is in a div
, that is inside an element with class td51
.
You can write a CSS selector combination to target this pattern of:
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