nbio | Pure Go 1000k+ connections solution | HTTP library
kandi X-RAY | nbio Summary
kandi X-RAY | nbio Summary
Pure Go 1000k+ connections solution, support tls/http1.x/websocket and basically compatible with net/http, with high-performance and low memory cost, non-blocking, event-driven, easy-to-use.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of nbio
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nbio Examples and Code Snippets
Community Discussions
Trending Discussions on nbio
QUESTION
I need to convert this C# function to Delphi. I am converting a function that will generate a string based on the CPU id, BIOS id, and motherboard id.
Can anyone help me, please?
...ANSWER
Answered 2020-Aug-08 at 15:58Here's a working implementation. It uses THashMD5
, which is available in recent versions of Delphi.
QUESTION
I'm trying to get the src for an image, but the HTML code I'm getting back is different from the HTML code shown on the Website.
...ANSWER
Answered 2020-Mar-29 at 12:37That's because they encoded the image into base64 which is being rendered on the browser once you open the page .
you can get the image url from another attribute though as follows:
QUESTION
I'm a college student working on a semester long project and I have hit a wall with my program. Before I go any further, do know that I looked through the similar threads on stack overflow and none of them seem to match my situation.
I have a string input generated from a pdf that contains abundant data from a table. Problem is, some of the table entries for the department column go from 1 row to 2 due to the formatting and I am unable to address it. For example,
PS 253 (handled fine by my algorithm)
MA
243HON (breaks everything)
I need to ultimately be able to put them on the same row and remove the " \n" after MA to send it along to the rest of the program. I attempted checking for \n one or two index places after the department code (MA) and changing the index from which I get 243HON, which did not work.
I have also tried String = string.replaceAll("MA \n", "MA ") as seen in the code. Removing the space between MA and \n does nothing. Here is the relevant part of my code. Thank you!
...ANSWER
Answered 2018-Sep-23 at 00:50I just fixed it. Through the find function, I had discovered that instead of \nMA \n, the format was \nMA \r\n. Changing that largely fixed the problem with a minor irrelevant bug which can be compensated for using an extra space. Thank you for your help nonetheless.
QUESTION
So I want this dataframe/string/vector
...ANSWER
Answered 2018-Aug-01 at 01:54This will remove numbers between quotation marks and them select the last code in each string. I'm using pipes (%>%
) to leave the code cleaner.
QUESTION
So this is a short example of a dataframe:
...ANSWER
Answered 2018-Aug-01 at 01:01I think that I understand what you want. This certainly works on your example.
QUESTION
Summary:
I have a program I want to ship as a single jar
file.
It depends on three big resource files (700MB each) in a binary format. The file content can easily be accessed via indexing, my parser therefore reads these files as RandomAccessFile
-objects.
So my goal is to access resource files from a jar
via File
objects.
My problem:
When accessing the resource files from my file system, there is no issue, but I aim to pack them into the jar
file of the program, so the user does not need to handle these files themselves.
The only way I found so far to access a file packed in a jar
is via InputStream
(generated by class.getResourceAsStream()
), which is totally useless for my application as it would be much too slow reading these files from start to end instead of using RandomAccessFile
.
Copying the file content into a file, reading it and deleting it in runtime is no option eigher for the same reason.
Can someone confirm that there is no way to achieve my goal or provide a solution (or a hint so I can work it out myself)?
What I found so far:
I found this answer and if I understand the answer it says that there is no way to solve my problem:
Resources in a .jar file are not files in the sense that the OS can access them directly via normal file access APIs.
And since java.io.File represents exactly that kind of file (i.e. a thing that looks like a file to the OS), it can't be used to refer to anything in a .jar file.
A possible workaround is to extract the resource to a temporary file and refer to that with a File.
I think I can follow the reasoning behind it, but it is over eight years old now and while I am not very educated when it comes to file systems and archives, I know that the Java language has evolved quite much since then, so maybe there is hope? :)
Probably useless background information:
The files are genomes in the 2bit
format and I use the TwoBitParser
from biojava
via the wrapper class TwoBitFacade
?. The Javadocs
can be found here and here.
ANSWER
Answered 2018-Jun-12 at 12:14Resources are not files, and they live in a JAR file, which is not a random access medium.
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