urlpattern | A library to match URL patterns , like in gorilla/mux | Router library
kandi X-RAY | urlpattern Summary
kandi X-RAY | urlpattern Summary
urlpattern === A library to match URL patterns, [gorilla/mux] style.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- newRouteRegexp returns a new route regexp .
- braceIndices returns a slice of open braces for braces .
- getPath extracts the path from the request URI
- Queries adds multiple expressions to the Pattern .
- getHost returns host from u .
- uniqueVars returns an error if s1 contains duplicates .
- NewPatternWithOptions returns a new pattern with strict slashes
- extractVars is a helper function to extract vars
- varGroupName returns the name of a variable group .
- NewPattern returns a new Pattern .
urlpattern Key Features
urlpattern Examples and Code Snippets
Community Discussions
Trending Discussions on urlpattern
QUESTION
I am trying to use django-storages to access my "Hetzner" Storage Box (https://www.hetzner.com/storage/storage-box) using SFTP which should hold media data, i.e. image files which users of my website can upload dynamically.
The corresponding part of my settings.py
file looks like:
ANSWER
Answered 2021-Sep-06 at 09:00I feel you may have forgot to migrate your fields in django models ?
In django-storage
documentation on Github, you have those snippet of code.
From:
QUESTION
im trying to learn ajax in django but when i running this simple test i got this error and i cant find the reason, my django version is 4.0
...ANSWER
Answered 2021-Dec-20 at 09:14From the Release Notes of 3.1
The
HttpRequest.is_ajax()
method is deprecated as it relied on a jQuery-specific way of signifying AJAX calls, while current usage tends to use the JavaScript Fetch API. Depending on your use case, you can either write your own AJAX detection method, or use the newHttpRequest.accepts()
method if your code depends on the client Accept HTTP header.
Even though it has been deprecated, you can create a custom function to check the request type as,
QUESTION
I am new to Django Authentication system and I am unable to find the correct debugging method.
I want to create a function to handle login requests and I have done the necessary steps to do the same.
created a login url path in main project URLS.py file.
...
ANSWER
Answered 2022-Mar-05 at 18:09Djnago will fire the view that it first finds for the path members/login
, and that is the login view of the django.contrib.auth
module. You can swap the order of the views to visit the login
view of your view:
QUESTION
I'm trying to develop a simple Django app of a contact form and a thanks page. I'm not using Django 'admin' at all; no database, either. Django 3.2.12. I'm working on localhost using python manage.py runserver
I can't get the actual form to display at http://127.0.0.1:8000/contact/contact
; all I see is the submit button from /contact/contactform/templates/contact.html
:
Static files load OK: http://127.0.0.1:8000/static/css/bootstrap.css
The thanks.html page loads OK: http://127.0.0.1:8000/contact/thanks
This is the directory structure:
/contact/contact/settings.py
...ANSWER
Answered 2022-Feb-17 at 03:06The form
does not display as you are not passing it into your template. You can do this instead in the contact
view:
QUESTION
After upgrading to Django 4.0, I get the following error when running python manage.py runserver
ANSWER
Answered 2022-Jan-10 at 21:38django.conf.urls.url()
was deprecated in Django 3.0, and is removed in Django 4.0+.
The easiest fix is to replace url()
with re_path()
. re_path
uses regexes like url
, so you only have to update the import and replace url
with re_path
.
QUESTION
Question in short
I have migrated my project from Django 2.2 to Django 3.2, and now I want to start using the possibility for asynchronous views. I have created an async view, setup asgi configuration, and run gunicorn with a Uvicorn worker. When swarming this server with 10 users concurrently, they are served synchronously. What do I need to configure in order to serve 10 concurrent users an async view?
Question in detail
This is what I did so far in my local environment:
- I am working with Django 3.2.10 and Python 3.9.
- I have installed
gunicorn
anduvicorn
through pip - I have created an
asgi.py
file with the following contents
ANSWER
Answered 2022-Feb-06 at 21:43When running the gunicorn
command, you can try to add workers
parameter with using options -w
or --workers
.
It defaults to 1
as stated in the gunicorn documentation. You may want to try to increase that value.
Example usage:
QUESTION
Here, select machine name and operation number, after select and save, It is displaying none instead of data like machine name and operation number in the form of table. Please help me out to solve this. I am new in Django.
urls.py:
...ANSWER
Answered 2022-Jan-15 at 06:20try this
QUESTION
The following pages are the code of projects:
If i am using token = jwt.encode(payload,'secret', algorithm='HS256').decode('utf-8')
statement
then
'str' object has no attribute 'decode'
error is occuring. Also, when I am removing and using it without .decode('utf-8')
and proceeding with the further code. it is working fine. But when I am applying payload = jwt.decode(token, 'secret', algorithm=['HS256'])
then
It is required that you pass in a value for the "algorithms" argument when calling decode()"
This above-mentioned error is occurring. Please Help me to rectify this error. This is the mentioned error that saying algorithms argument when calling decode() error should be rectified.
View Page:
...ANSWER
Answered 2022-Jan-11 at 08:21You're missing an 's', the parameter is called "algorithms" in the decode function:
QUESTION
I'm build Django app, and it's work fine on my machine, but when I run inside docker container it's rest framework keep crashing, but when I comment any connection with rest framework it's work fine.
- My machine: Kali Linux 2021.3
- docker machine: Raspberry Pi 4 4gb
- docker container image: python:rc-alpine3.14
- python version on my machine: Python 3.9.7
- python version on container: Python 3.10.0rc2
error output:
...ANSWER
Answered 2022-Jan-07 at 19:13You can downgrade your Python version. That should solve your problem; if not, use collections.abc.Mapping
instead of the deprecated collections.Mapping
.
Refer here: Link
QUESTION
I've recently started learning Django and I've been having a lot of issues with implementing css into my code. I've found a lot of people with the same issue as me but I am still unable to find an answer.
Currently when I run open the website it give me this https://imgur.com/a/0N23s7b
And I'm not sure if this is because of the settings, the actual css or something in the html.
My html boilerplate
...ANSWER
Answered 2021-Sep-11 at 14:56You need to add a space between the name of the template tag and its parameters, so it should be:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install urlpattern
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page